Precalculus Examples

$10^{\log (0.82)}$

Step 1

Log base $10$ of $0.82$ is approximately $- 0.08618614$ .

$10^{- 0.08618614}$

Step 2

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{1}{10^{0.08618614}}$

Step 3

Raise $10$ to the power of $0.08618614$ .

$\frac{1}{1.\overline{21951}}$

Step 4

Divide $1$ by $1.\overline{21951}$ .

$0.82$