Precalculus Examples

$\frac{3}{\ln (4)} + \frac{2}{\ln^{3} (2)} + \frac{2 {(\ln (2) - 1)}^{2}}{\ln^{3} (2)} + \frac{1}{5}$

Step 1

Simplify the denominator.

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Step 1.1

Rewrite $\ln (4)$ as $\ln (2^{2})$ .

$\frac{3}{\ln (2^{2})} + \frac{2}{\ln^{3} (2)} + \frac{2 {(\ln (2) - 1)}^{2}}{\ln^{3} (2)} + \frac{1}{5}$

Step 1.2

Expand $\ln (2^{2})$ by moving $2$ outside the logarithm.

$\frac{3}{2 \ln (2)} + \frac{2}{\ln^{3} (2)} + \frac{2 {(\ln (2) - 1)}^{2}}{\ln^{3} (2)} + \frac{1}{5}$

Step 2

Combine the numerators over the common denominator.

$\frac{3}{2 \ln (2)} + \frac{2 + 2 {(\ln (2) - 1)}^{2}}{\ln^{3} (2)} + \frac{1}{5}$