Precalculus Examples

$\log (1.18 \cdot 10^{51})$

Step 1

Rewrite $\log (1.18 \cdot 10^{51})$ as $\log (1.18) + \log (10^{51})$ .

$\log (1.18) + \log (10^{51})$

Step 2

Expand $\log (10^{51})$ by moving $51$ outside the logarithm.

$\log (1.18) + 51 \log (10)$

Step 3

Log base $10$ of $1.18$ is approximately $0.071882$ .

$0.071882 + 51 \log (10)$

Step 4

Logarithm base $10$ of $10$ is $1$ .

$0.071882 + 51 \cdot 1$

Step 5

Multiply $51$ by $1$ .

$0.071882 + 51$

Step 6

Add $0.071882$ and $51$ .

$51.071882$