Precalculus Examples

$\log (1.05 \cdot 10^{28})$

Step 1

Rewrite $\log (1.05 \cdot 10^{28})$ as $\log (1.05) + \log (10^{28})$ .

$\log (1.05) + \log (10^{28})$

Step 2

Expand $\log (10^{28})$ by moving $28$ outside the logarithm.

$\log (1.05) + 28 \log (10)$

Step 3

Log base $10$ of $1.05$ is approximately $0.02118929$ .

$0.02118929 + 28 \log (10)$

Step 4

Logarithm base $10$ of $10$ is $1$ .

$0.02118929 + 28 \cdot 1$

Step 5

Multiply $28$ by $1$ .

$0.02118929 + 28$

Step 6

Add $0.02118929$ and $28$ .

$28.02118929$