Precalculus Examples

$\log ({(0.3)}^{1.7}) = (1 - 2 x)$

Step 1

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = 10$ , $x = {(0.3)}^{1.7}$ , and $y = 1 - 2 x$ .

$b = 10$

$x = {(0.3)}^{1.7}$

$y = 1 - 2 x$

Step 2

Substitute the values of $b$ , $x$ , and $y$ into the equation $b^{y} = x$ .

$10^{1 - 2 x} = {(0.3)}^{1.7}$