Precalculus Examples

$\log_{6.31} (x + 4) = \log_{4.23} (x - 1)$

Step 1

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = 6.31$ , $x = x + 4$ , and $y = \log_{4.23} (x - 1)$ .

$b = 6.31$

$x = x + 4$

$y = \log_{4.23} (x - 1)$

Step 2

Substitute the values of $b$ , $x$ , and $y$ into the equation $b^{y} = x$ .

${6.31}^{\log_{4.23} (x - 1)} = x + 4$