Precalculus Examples

$\ln (\frac{\sqrt[5]{x} {(3 x + 1)}^{4}}{3 (x - 2) e^{5 x - 7}})$

Step 1

Rewrite $\ln (\frac{\sqrt[5]{x} {(3 x + 1)}^{4}}{3 (x - 2) e^{5 x - 7}})$ as $\ln (\sqrt[5]{x} {(3 x + 1)}^{4}) - \ln (3 (x - 2) e^{5 x - 7})$ .

$\ln (\sqrt[5]{x} {(3 x + 1)}^{4}) - \ln (3 (x - 2) e^{5 x - 7})$

Step 2

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt[5]{x}$ as $x^{\frac{1}{5}}$ .

$\ln (x^{\frac{1}{5}} {(3 x + 1)}^{4}) - \ln (3 (x - 2) e^{5 x - 7})$

Step 3

Rewrite $\ln (x^{\frac{1}{5}} {(3 x + 1)}^{4})$ as $\ln (x^{\frac{1}{5}}) + \ln ({(3 x + 1)}^{4})$ .

$\ln (x^{\frac{1}{5}}) + \ln ({(3 x + 1)}^{4}) - \ln (3 (x - 2) e^{5 x - 7})$

Step 4

Expand $\ln (x^{\frac{1}{5}})$ by moving $\frac{1}{5}$ outside the logarithm.

$\frac{1}{5} \ln (x) + \ln ({(3 x + 1)}^{4}) - \ln (3 (x - 2) e^{5 x - 7})$

Step 5

Expand $\ln ({(3 x + 1)}^{4})$ by moving $4$ outside the logarithm.

$\frac{1}{5} \ln (x) + 4 \ln (3 x + 1) - \ln (3 (x - 2) e^{5 x - 7})$

Step 6

Rewrite $\ln (3 (x - 2) e^{5 x - 7})$ as $\ln (3 (x - 2)) + \ln (e^{5 x - 7})$ .

$\frac{1}{5} \ln (x) + 4 \ln (3 x + 1) - (\ln (3 (x - 2)) + \ln (e^{5 x - 7}))$

Step 7

Rewrite $\ln (3 (x - 2))$ as $\ln (3) + \ln (x - 2)$ .

$\frac{1}{5} \ln (x) + 4 \ln (3 x + 1) - (\ln (3) + \ln (x - 2) + \ln (e^{5 x - 7}))$

Step 8

Expand $\ln (e^{5 x - 7})$ by moving $5 x - 7$ outside the logarithm.

$\frac{1}{5} \ln (x) + 4 \ln (3 x + 1) - (\ln (3) + \ln (x - 2) + (5 x - 7) \ln (e))$

Step 9

The natural logarithm of $e$ is $1$ .

$\frac{1}{5} \ln (x) + 4 \ln (3 x + 1) - (\ln (3) + \ln (x - 2) + (5 x - 7) \cdot 1)$

Step 10

Multiply $5 x - 7$ by $1$ .

$\frac{1}{5} \ln (x) + 4 \ln (3 x + 1) - (\ln (3) + \ln (x - 2) + 5 x - 7)$

Step 11

Simplify each term.

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Step 11.1

Combine $\frac{1}{5}$ and $\ln (x)$ .

$\frac{\ln (x)}{5} + 4 \ln (3 x + 1) - (\ln (3) + \ln (x - 2) + 5 x - 7)$

Step 11.2

Apply the distributive property.

$\frac{\ln (x)}{5} + 4 \ln (3 x + 1) - \ln (3) - \ln (x - 2) - (5 x) - - 7$

Step 11.3

Simplify.

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Step 11.3.1

Multiply $5$ by $- 1$ .

$\frac{\ln (x)}{5} + 4 \ln (3 x + 1) - \ln (3) - \ln (x - 2) - 5 x - - 7$

Step 11.3.2

Multiply $- 1$ by $- 7$ .

$\frac{\ln (x)}{5} + 4 \ln (3 x + 1) - \ln (3) - \ln (x - 2) - 5 x + 7$

Step 12

To write $4 \ln (3 x + 1)$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$\frac{\ln (x)}{5} + 4 \ln (3 x + 1) \cdot \frac{5}{5} - \ln (3) - \ln (x - 2) - 5 x + 7$

Step 13

Combine $4 \ln (3 x + 1)$ and $\frac{5}{5}$ .

$\frac{\ln (x)}{5} + \frac{4 \ln (3 x + 1) \cdot 5}{5} - \ln (3) - \ln (x - 2) - 5 x + 7$

Step 14

Combine the numerators over the common denominator.

$\frac{\ln (x) + 4 \ln (3 x + 1) \cdot 5}{5} - \ln (3) - \ln (x - 2) - 5 x + 7$

Step 15

Multiply $5$ by $4$ .

$\frac{\ln (x) + 20 \ln (3 x + 1)}{5} - \ln (3) - \ln (x - 2) - 5 x + 7$

Step 16

To write $- \ln (x - 2)$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$\frac{\ln (x) + 20 \ln (3 x + 1)}{5} - \ln (x - 2) \cdot \frac{5}{5} - \ln (3) - 5 x + 7$

Step 17

Combine $- \ln (x - 2)$ and $\frac{5}{5}$ .

$\frac{\ln (x) + 20 \ln (3 x + 1)}{5} + \frac{- \ln (x - 2) \cdot 5}{5} - \ln (3) - 5 x + 7$

Step 18

Combine the numerators over the common denominator.

$\frac{\ln (x) + 20 \ln (3 x + 1) - \ln (x - 2) \cdot 5}{5} - \ln (3) - 5 x + 7$

Step 19

Multiply $5$ by $- 1$ .

$\frac{\ln (x) + 20 \ln (3 x + 1) - 5 \ln (x - 2)}{5} - \ln (3) - 5 x + 7$