Precalculus Examples

$9^{2 x - 1} = \frac{1}{3 x}$

Step 1

Reduce by cancelling the common factors.

$9^{2 x - 1} = \frac{1}{3 x}$

Step 2

Convert the exponential equation to a logarithmic equation using the logarithm base $(9)$ of the right side $(\frac{1}{3 x})$ equals the exponent $(2 x - 1)$ .

$\log_{9} (\frac{1}{3 x}) = 2 x - 1$