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Precalculus
Write in Exponential Form log base 7 of 2401=4
log
7
(
2401
)
=
4
log
7
(
2401
)
=
4
Step 1
For logarithmic
equations
,
log
b
(
x
)
=
y
log
b
(
x
)
=
y
is
equivalent
to
b
y
=
x
b
y
=
x
such that
x
>
0
x
>
0
,
b
>
0
b
>
0
, and
b
≠
1
b
≠
1
. In this case,
b
=
7
b
=
7
,
x
=
2401
x
=
2401
, and
y
=
4
y
=
4
.
b
=
7
b
=
7
x
=
2401
x
=
2401
y
=
4
y
=
4
Step 2
Substitute the values of
b
b
,
x
x
, and
y
y
into the
equation
b
y
=
x
b
y
=
x
.
7
4
=
2401
7
4
=
2401
l
o
g
7
(
2
4
0
1
)
=
4
l
o
g
7
(
2
4
0
1
)
=
4
(
(
)
)
|
|
[
[
]
]
√
√
≥
≥
7
7
8
8
9
9
≤
≤
°
°
θ
θ
4
4
5
5
6
6
/
/
^
^
×
×
>
>
π
π
1
1
2
2
3
3
-
-
+
+
÷
÷
<
<
∞
∞
,
,
0
0
.
.
%
%
=
=
⎡
⎢
⎣
x
2
1
2
√
π
∫
x
d
x
⎤
⎥
⎦
[
x
2
1
2
π
∫
x
d
x
]
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