Precalculus Examples

m = - 9

$m = - 9$ ,

(7, 9)

$(7, 9)$

Step 1

Find the value of

b

$b$ using the formula for the equation of a line.

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Step 1.1

Use the formula for the equation of a line to find

b

$b$ .

y = m x + b

$y = m x + b$

Step 1.2

Substitute the value of

m

$m$ into the equation.

y = (- 9) \cdot x + b

$y = (- 9) \cdot x + b$

Step 1.3

Substitute the value of

x

$x$ into the equation.

y = (- 9) \cdot (7) + b

$y = (- 9) \cdot (7) + b$

Step 1.4

Substitute the value of

y

$y$ into the equation.

9 = (- 9) \cdot (7) + b

$9 = (- 9) \cdot (7) + b$

Step 1.5

Find the value of

b

$b$ .

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Step 1.5.1

Rewrite the equation as

(- 9) \cdot (7) + b = 9

$(- 9) \cdot (7) + b = 9$ .

(- 9) \cdot (7) + b = 9

$(- 9) \cdot (7) + b = 9$

Step 1.5.2

Multiply

- 9

$- 9$ by

7

$7$ .

- 63 + b = 9

$- 63 + b = 9$

Step 1.5.3

Move all terms not containing

b

$b$ to the right side of the equation.

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Step 1.5.3.1

Add

63

$63$ to both sides of the equation.

b = 9 + 63

$b = 9 + 63$

Step 1.5.3.2

Add

9

$9$ and

63

$63$ .

b = 72

$b = 72$

b = 72

$b = 72$

b = 72

$b = 72$

b = 72

$b = 72$

Step 2

Now that the values of

m

$m$ (slope) and

b

$b$ (y-intercept) are known, substitute them into

y = m x + b

$y = m x + b$ to find the equation of the line.

y = - 9 x + 72

$y = - 9 x + 72$

Step 3

m = - 9, (7, 9)

$m = - 9, (7, 9)$

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[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$