Precalculus Examples

$(- 8, 1)$ , $(- 8, 7)$

Step 1

Find the slope of the line between $(- 8, 1)$ and $(- 8, 7)$ using $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ , which is the change of $y$ over the change of $x$ .

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Step 1.1

Slope is equal to the change in $y$ over the change in $x$ , or rise over run.

$m = \frac{change in y}{change in x}$

Step 1.2

The change in $x$ is equal to the difference in x-coordinates (also called run), and the change in $y$ is equal to the difference in y-coordinates (also called rise).

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$

Step 1.3

Substitute in the values of $x$ and $y$ into the equation to find the slope.

$m = \frac{7 - (1)}{- 8 - (- 8)}$

Step 1.4

Simplify.

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Step 1.4.1

Multiply $- 1$ by $- 8$ .

$\frac{7 - (1)}{- 8 + 8}$

Step 1.4.2

Add $- 8$ and $8$ .

$\frac{7 - (1)}{0}$

Step 1.4.3

The expression contains a division by $0$ . The expression is undefined.

Undefined

Step 2

The slope of the line is undefined, which means that it is perpendicular to the x-axis at $x = - 8$ .

$x = - 8$

Step 3