Precalculus Examples

$y = \frac{1}{8} x + 6$ , $(- 3, 0)$

Step 1

Find the slope when $y = \frac{1}{8} x + 6$ .

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Step 1.1

Rewrite in slope-intercept form.

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Step 1.1.1

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Step 1.1.2

Simplify the right side.

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Step 1.1.2.1

Combine $\frac{1}{8}$ and $x$ .

$y = \frac{x}{8} + 6$

Step 1.1.3

Reorder terms.

$y = \frac{1}{8} x + 6$

Step 1.2

Using the slope-intercept form, the slope is $\frac{1}{8}$ .

$m = \frac{1}{8}$

Step 2

The equation of a perpendicular line must have a slope that is the negative reciprocal of the original slope.

$m_{perpendicular} = - \frac{1}{\frac{1}{8}}$

Step 3

Simplify $- \frac{1}{\frac{1}{8}}$ to find the slope of the perpendicular line.

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Step 3.1

Multiply the numerator by the reciprocal of the denominator.

$m_{perpendicular} = - (1 \cdot 8)$

Step 3.2

Multiply $- (1 \cdot 8)$ .

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Step 3.2.1

Multiply $8$ by $1$ .

$m_{perpendicular} = - 1 \cdot 8$

Step 3.2.2

Multiply $- 1$ by $8$ .

$m_{perpendicular} = - 8$

Step 4

Find the equation of the perpendicular line using the point-slope formula.

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Step 4.1

Use the slope $- 8$ and a given point $(- 3, 0)$ to substitute for $x_{1}$ and $y_{1}$ in the point-slope form $y - y_{1} = m (x - x_{1})$ , which is derived from the slope equation $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ .

$y - (0) = - 8 \cdot (x - (- 3))$

Step 4.2

Simplify the equation and keep it in point-slope form.

$y + 0 = - 8 \cdot (x + 3)$

Step 5

Solve for $y$ .

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Step 5.1

Add $y$ and $0$ .

$y = - 8 \cdot (x + 3)$

Step 5.2

Simplify $- 8 \cdot (x + 3)$ .

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Step 5.2.1

Apply the distributive property.

$y = - 8 x - 8 \cdot 3$

Step 5.2.2

Multiply $- 8$ by $3$ .

$y = - 8 x - 24$

Step 6