Precalculus Examples

$\log_{12} (2) + \log_{12} (6)$

Step 1

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{12} (2 \cdot 6)$

Step 2

Multiply $2$ by $6$ .

$\log_{12} (12)$

Step 3

Logarithm base $12$ of $12$ is $1$ .

$1$