Precalculus Examples

$e^{x} + 6 e^{- x} - 7 = 0$

Step 1

Rewrite $e^{- x}$ as exponentiation.

$e^{x} + 6 {(e^{x})}^{- 1} - 7 = 0$

Step 2

Substitute $u$ for $e^{x}$ .

$u + 6 u^{- 1} - 7 = 0$

Step 3

Simplify each term.

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Step 3.1

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$u + 6 (\frac{1}{u}) - 7 = 0$

Step 3.2

Combine $6$ and $\frac{1}{u}$ .

$u + \frac{6}{u} - 7 = 0$

Step 4

Solve for $u$ .

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Step 4.1

Find the LCD of the terms in the equation.

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Step 4.1.1

Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.

$1, u, 1, 1$

Step 4.1.2

The LCM of one and any expression is the expression.

$u$

Step 4.2

Multiply each term in $u + \frac{6}{u} - 7 = 0$ by $u$ to eliminate the fractions.

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Step 4.2.1

Multiply each term in $u + \frac{6}{u} - 7 = 0$ by $u$ .

$u \cdot u + \frac{6}{u} u - 7 u = 0 u$

Step 4.2.2

Simplify the left side.

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Step 4.2.2.1

Simplify each term.

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Step 4.2.2.1.1

Multiply $u$ by $u$ .

$u^{2} + \frac{6}{u} u - 7 u = 0 u$

Step 4.2.2.1.2

Cancel the common factor of $u$ .

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Step 4.2.2.1.2.1

Cancel the common factor.

$u^{2} + \frac{6}{u} u - 7 u = 0 u$

Step 4.2.2.1.2.2

Rewrite the expression.

$u^{2} + 6 - 7 u = 0 u$

Step 4.2.3

Simplify the right side.

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Step 4.2.3.1

Multiply $0$ by $u$ .

$u^{2} + 6 - 7 u = 0$

Step 4.3

Solve the equation.

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Step 4.3.1

Factor $u^{2} + 6 - 7 u$ using the AC method.

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Step 4.3.1.1

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $6$ and whose sum is $- 7$ .

$- 6, - 1$

Step 4.3.1.2

Write the factored form using these integers.

$(u - 6) (u - 1) = 0$

Step 4.3.2

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$u - 6 = 0$

$u - 1 = 0$

Step 4.3.3

Set $u - 6$ equal to $0$ and solve for $u$ .

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Step 4.3.3.1

Set $u - 6$ equal to $0$ .

$u - 6 = 0$

Step 4.3.3.2

Add $6$ to both sides of the equation.

$u = 6$

Step 4.3.4

Set $u - 1$ equal to $0$ and solve for $u$ .

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Step 4.3.4.1

Set $u - 1$ equal to $0$ .

$u - 1 = 0$

Step 4.3.4.2

Add $1$ to both sides of the equation.

$u = 1$

Step 4.3.5

The final solution is all the values that make $(u - 6) (u - 1) = 0$ true.

$u = 6, 1$

Step 5

Substitute $6$ for $u$ in $u = e^{x}$ .

$6 = e^{x}$

Step 6

Solve $6 = e^{x}$ .

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Step 6.1

Rewrite the equation as $e^{x} = 6$ .

$e^{x} = 6$

Step 6.2

Take the natural logarithm of both sides of the equation to remove the variable from the exponent.

$\ln (e^{x}) = \ln (6)$

Step 6.3

Expand the left side.

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Step 6.3.1

Expand $\ln (e^{x})$ by moving $x$ outside the logarithm.

$x \ln (e) = \ln (6)$

Step 6.3.2

The natural logarithm of $e$ is $1$ .

$x \cdot 1 = \ln (6)$

Step 6.3.3

Multiply $x$ by $1$ .

$x = \ln (6)$

Step 7

Substitute $1$ for $u$ in $u = e^{x}$ .

$1 = e^{x}$

Step 8

Solve $1 = e^{x}$ .

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Step 8.1

Rewrite the equation as $e^{x} = 1$ .

$e^{x} = 1$

Step 8.2

Take the natural logarithm of both sides of the equation to remove the variable from the exponent.

$\ln (e^{x}) = \ln (1)$

Step 8.3

Expand the left side.

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Step 8.3.1

Expand $\ln (e^{x})$ by moving $x$ outside the logarithm.

$x \ln (e) = \ln (1)$

Step 8.3.2

The natural logarithm of $e$ is $1$ .

$x \cdot 1 = \ln (1)$

Step 8.3.3

Multiply $x$ by $1$ .

$x = \ln (1)$

Step 8.4

The natural logarithm of $1$ is $0$ .

$x = 0$

Step 9

List the solutions that makes the equation true.

$x = \ln (6), 0$

Step 10

The result can be shown in multiple forms.

Exact Form:

$x = \ln (6), 0$

Decimal Form:

$x = 1.79175946 \dots, 0$