Precalculus Examples

$\log_{8} (16) - \log_{8} (2)$

Step 1

Use the quotient property of logarithms, $\log_{b} (x) - \log_{b} (y) = \log_{b} (\frac{x}{y})$ .

$\log_{8} (\frac{16}{2})$

Step 2

Logarithm base $8$ of $\frac{16}{2}$ is $1$ .

$1$