Precalculus Examples

$\log (7) \cdot 3.01$

Step 1

Multiply $\log (7) \cdot 3.01$ .

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Step 1.1

Reorder $\log (7)$ and $3.01$ .

$3.01 \cdot \log (7)$

Step 1.2

Simplify $3.01 \cdot \log (7)$ by moving $3.01$ inside the logarithm.

$\log (7^{3.01})$

Step 2

Raise $7$ to the power of $3.01$ .

$\log (349.7398347)$

Step 3

Log base $10$ of $349.7398347$ is approximately $2.5437451$ .

$2.5437451$