Precalculus Examples

$\frac{\cot (θ)}{1 + \tan (- θ)} + \frac{\tan (θ)}{1 + \cot (- θ)} = \cot (θ) + \tan (θ) + 1$

Step 1

The provided equation is an identity.

$\frac{\cot (θ)}{1 + \tan (- θ)} + \frac{\tan (θ)}{1 + \cot (- θ)} = \cot (θ) + \tan (θ) + 1$ is an identity