Precalculus Examples

$| 8 - 8 x | < - 13$

Step 1

Since $| 8 - 8 x |$ is always positive and $- 13$ is negative, $| 8 - 8 x |$ is always greater than $- 13$ so the inequality cannot be true.

No solution

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$