Precalculus Examples

$\sqrt{36 - x^{2}}$

Step 1

Rewrite $36$ as $6^{2}$ .

$\sqrt{6^{2} - x^{2}}$

Step 2

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 6$ and $b = x$ .

$\sqrt{(6 + x) (6 - x)}$