Precalculus Examples

$2 \cos (\frac{π}{6}) - 6 \tan (\frac{π}{3})$

Step 1

Simplify each term.

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Step 1.1

The exact value of $\cos (\frac{π}{6})$ is $\frac{\sqrt{3}}{2}$ .

$2 \frac{\sqrt{3}}{2} - 6 \tan (\frac{π}{3})$

Step 1.2

Cancel the common factor of $2$ .

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Step 1.2.1

Cancel the common factor.

$2 \frac{\sqrt{3}}{2} - 6 \tan (\frac{π}{3})$

Step 1.2.2

Rewrite the expression.

$\sqrt{3} - 6 \tan (\frac{π}{3})$

Step 1.3

The exact value of $\tan (\frac{π}{3})$ is $\sqrt{3}$ .

$\sqrt{3} - 6 \sqrt{3}$

Step 2

Subtract $6 \sqrt{3}$ from $\sqrt{3}$ .

$- 5 \sqrt{3}$

Step 3

The result can be shown in multiple forms.

Exact Form:

$- 5 \sqrt{3}$

Decimal Form:

$- 8.66025403 \dots$