Precalculus Examples

$\log_{9} (x) + \log_{9} (x + 10) = k$

Step 1

Use the product property of logarithms, $\log_{b} (x) + \log_{b} (y) = \log_{b} (x y)$ .

$\log_{9} (x (x + 10)) = k$

Step 2

Apply the distributive property.

$\log_{9} (x \cdot x + x \cdot 10) = k$

Step 3

Simplify the expression.

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Step 3.1

Multiply $x$ by $x$ .

$\log_{9} (x^{2} + x \cdot 10) = k$

Step 3.2

Move $10$ to the left of $x$ .

$\log_{9} (x^{2} + 10 x) = k$