Precalculus Examples

$\log_{5} (- 3 x + 7) = 0$

Step 1

Rewrite $\log_{5} (- 3 x + 7) = 0$ in exponential form using the definition of a logarithm. If $x$ and $b$ are positive real numbers and $b \neq 1$ , then $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ .

$5^{0} = - 3 x + 7$

Step 2

Solve for $x$ .

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Step 2.1

Rewrite the equation as $- 3 x + 7 = 5^{0}$ .

$- 3 x + 7 = 5^{0}$

Step 2.2

Anything raised to $0$ is $1$ .

$- 3 x + 7 = 1$

Step 2.3

Move all terms not containing $x$ to the right side of the equation.

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Step 2.3.1

Subtract $7$ from both sides of the equation.

$- 3 x = 1 - 7$

Step 2.3.2

Subtract $7$ from $1$ .

$- 3 x = - 6$

Step 2.4

Divide each term in $- 3 x = - 6$ by $- 3$ and simplify.

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Step 2.4.1

Divide each term in $- 3 x = - 6$ by $- 3$ .

$\frac{- 3 x}{- 3} = \frac{- 6}{- 3}$

Step 2.4.2

Simplify the left side.

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Step 2.4.2.1

Cancel the common factor of $- 3$ .

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Step 2.4.2.1.1

Cancel the common factor.

$\frac{- 3 x}{- 3} = \frac{- 6}{- 3}$

Step 2.4.2.1.2

Divide $x$ by $1$ .

$x = \frac{- 6}{- 3}$

Step 2.4.3

Simplify the right side.

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Step 2.4.3.1

Divide $- 6$ by $- 3$ .

$x = 2$