Precalculus Examples

Solve for ? sin(x)=cos(x)
sin(x)=cos(x)sin(x)=cos(x)
Step 1
Divide each term in the equation by cos(x)cos(x).
sin(x)cos(x)=cos(x)cos(x)sin(x)cos(x)=cos(x)cos(x)
Step 2
Convert from sin(x)cos(x)sin(x)cos(x) to tan(x)tan(x).
tan(x)=cos(x)cos(x)tan(x)=cos(x)cos(x)
Step 3
Cancel the common factor of cos(x)cos(x).
Tap for more steps...
Step 3.1
Cancel the common factor.
tan(x)=cos(x)cos(x)
Step 3.2
Rewrite the expression.
tan(x)=1
tan(x)=1
Step 4
Take the inverse tangent of both sides of the equation to extract x from inside the tangent.
x=arctan(1)
Step 5
Simplify the right side.
Tap for more steps...
Step 5.1
The exact value of arctan(1) is π4.
x=π4
x=π4
Step 6
The tangent function is positive in the first and third quadrants. To find the second solution, add the reference angle from π to find the solution in the fourth quadrant.
x=π+π4
Step 7
Simplify π+π4.
Tap for more steps...
Step 7.1
To write π as a fraction with a common denominator, multiply by 44.
x=π44+π4
Step 7.2
Combine fractions.
Tap for more steps...
Step 7.2.1
Combine π and 44.
x=π44+π4
Step 7.2.2
Combine the numerators over the common denominator.
x=π4+π4
x=π4+π4
Step 7.3
Simplify the numerator.
Tap for more steps...
Step 7.3.1
Move 4 to the left of π.
x=4π+π4
Step 7.3.2
Add 4π and π.
x=5π4
x=5π4
x=5π4
Step 8
Find the period of tan(x).
Tap for more steps...
Step 8.1
The period of the function can be calculated using π|b|.
π|b|
Step 8.2
Replace b with 1 in the formula for period.
π|1|
Step 8.3
The absolute value is the distance between a number and zero. The distance between 0 and 1 is 1.
π1
Step 8.4
Divide π by 1.
π
π
Step 9
The period of the tan(x) function is π so values will repeat every π radians in both directions.
x=π4+πn,5π4+πn, for any integer n
Step 10
Consolidate the answers.
x=π4+πn, for any integer n
(
(
)
)
|
|
[
[
]
]
7
7
8
8
9
9
°
°
θ
θ
4
4
5
5
6
6
/
/
^
^
×
×
>
>
π
π
1
1
2
2
3
3
-
-
+
+
÷
÷
<
<
,
,
0
0
.
.
%
%
=
=
 [x2  12  π  xdx ]