Precalculus Examples

Solve for x cos(x)^2-2.4cos(x)-0.81=0
Step 1
Substitute for .
Step 2
Use the quadratic formula to find the solutions.
Step 3
Substitute the values , , and into the quadratic formula and solve for .
Step 4
Simplify.
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Step 4.1
Simplify the numerator.
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Step 4.1.1
Raise to the power of .
Step 4.1.2
Multiply .
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Step 4.1.2.1
Multiply by .
Step 4.1.2.2
Multiply by .
Step 4.1.3
Add and .
Step 4.1.4
Rewrite as .
Step 4.1.5
Pull terms out from under the radical, assuming positive real numbers.
Step 4.2
Multiply by .
Step 5
The final answer is the combination of both solutions.
Step 6
Substitute for .
Step 7
Set up each of the solutions to solve for .
Step 8
Solve for in .
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Step 8.1
The range of cosine is . Since does not fall in this range, there is no solution.
No solution
No solution
Step 9
Solve for in .
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Step 9.1
Take the inverse cosine of both sides of the equation to extract from inside the cosine.
Step 9.2
Simplify the right side.
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Step 9.2.1
Evaluate .
Step 9.3
The cosine function is negative in the second and third quadrants. To find the second solution, subtract the reference angle from to find the solution in the third quadrant.
Step 9.4
Solve for .
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Step 9.4.1
Remove parentheses.
Step 9.4.2
Simplify .
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Step 9.4.2.1
Multiply by .
Step 9.4.2.2
Subtract from .
Step 9.5
Find the period of .
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Step 9.5.1
The period of the function can be calculated using .
Step 9.5.2
Replace with in the formula for period.
Step 9.5.3
The absolute value is the distance between a number and zero. The distance between and is .
Step 9.5.4
Divide by .
Step 9.6
The period of the function is so values will repeat every radians in both directions.
, for any integer
, for any integer
Step 10
List all of the solutions.
, for any integer