Precalculus Examples

$θ = g r + g v t$

Step 1

Rewrite the equation as $g r + g v t = θ$ .

$g r + g v t = θ$

Step 2

Subtract $g v t$ from both sides of the equation.

$g r = θ - g v t$

Step 3

Divide each term in $g r = θ - g v t$ by $g$ and simplify.

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Step 3.1

Divide each term in $g r = θ - g v t$ by $g$ .

$\frac{g r}{g} = \frac{θ}{g} + \frac{- g v t}{g}$

Step 3.2

Simplify the left side.

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Step 3.2.1

Cancel the common factor of $g$ .

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Step 3.2.1.1

Cancel the common factor.

$\frac{g r}{g} = \frac{θ}{g} + \frac{- g v t}{g}$

Step 3.2.1.2

Divide $r$ by $1$ .

$r = \frac{θ}{g} + \frac{- g v t}{g}$

$r = \frac{θ}{g} + \frac{- g v t}{g}$

$r = \frac{θ}{g} + \frac{- g v t}{g}$

Step 3.3

Simplify the right side.

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Step 3.3.1

Simplify each term.

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Step 3.3.1.1

Cancel the common factor of $g$ .

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Step 3.3.1.1.1

Cancel the common factor.

$r = \frac{θ}{g} + \frac{- g v t}{g}$

Step 3.3.1.1.2

Divide $- 1 v t$ by $1$ .

$r = \frac{θ}{g} - 1 v t$

$r = \frac{θ}{g} - 1 v t$

Step 3.3.1.2

Rewrite $- 1 v$ as $- v$ .

$r = \frac{θ}{g} - v t$

$r = \frac{θ}{g} - v t$

$r = \frac{θ}{g} - v t$

$r = \frac{θ}{g} - v t$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$