Precalculus Examples

$r = 0.65 \log (0.39 e) + 1.45$

Step 1

Simplify each term.

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Step 1.1

Multiply $0.39$ by $e$ .

$r = 0.65 \log (1.06012991) + 1.45$

Step 1.2

Log base $10$ of $1.06012991$ is approximately $0.02535908$ .

$r = 0.65 \cdot 0.02535908 + 1.45$

Step 1.3

Multiply $0.65$ by $0.02535908$ .

$r = 0.0164834 + 1.45$

Step 2

Add $0.0164834$ and $1.45$ .

$r = 1.4664834$