Precalculus Examples

$(6 x + 5) - (8 x + 15)$

Step 1

Simplify each term.

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Step 1.1

Apply the distributive property.

$6 x + 5 - (8 x) - 1 \cdot 15$

Step 1.2

Multiply $8$ by $- 1$ .

$6 x + 5 - 8 x - 1 \cdot 15$

Step 1.3

Multiply $- 1$ by $15$ .

$6 x + 5 - 8 x - 15$

$6 x + 5 - 8 x - 15$

Step 2

Simplify by adding terms.

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Step 2.1

Subtract $8 x$ from $6 x$ .

$- 2 x + 5 - 15$

Step 2.2

Subtract $15$ from $5$ .

$- 2 x - 10$

$- 2 x - 10$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$