Precalculus Examples

${(x + 2)}^{2} = 14$

Step 1

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x + 2 = \pm \sqrt{14}$

Step 2

The complete solution is the result of both the positive and negative portions of the solution.

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Step 2.1

First, use the positive value of the $\pm$ to find the first solution.

$x + 2 = \sqrt{14}$

Step 2.2

Subtract $2$ from both sides of the equation.

$x = \sqrt{14} - 2$

Step 2.3

Next, use the negative value of the $\pm$ to find the second solution.

$x + 2 = - \sqrt{14}$

Step 2.4

Subtract $2$ from both sides of the equation.

$x = - \sqrt{14} - 2$

Step 2.5

The complete solution is the result of both the positive and negative portions of the solution.

$x = \sqrt{14} - 2, - \sqrt{14} - 2$

Step 3

The result can be shown in multiple forms.

Exact Form:

$x = \sqrt{14} - 2, - \sqrt{14} - 2$

Decimal Form:

$x = 1.74165738 \dots, - 5.74165738 \dots$