Precalculus Examples

$9 x^{3} + 9 x^{2} - x - 1 = 0$

Step 1

Factor the left side of the equation.

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Step 1.1

Factor out the greatest common factor from each group.

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Step 1.1.1

Group the first two terms and the last two terms.

$(9 x^{3} + 9 x^{2}) - x - 1 = 0$

Step 1.1.2

Factor out the greatest common factor (GCF) from each group.

$9 x^{2} (x + 1) - (x + 1) = 0$

Step 1.2

Factor the polynomial by factoring out the greatest common factor, $x + 1$ .

$(x + 1) (9 x^{2} - 1) = 0$

Step 1.3

Rewrite $9 x^{2}$ as ${(3 x)}^{2}$ .

$(x + 1) ({(3 x)}^{2} - 1) = 0$

Step 1.4

Rewrite $1$ as $1^{2}$ .

$(x + 1) ({(3 x)}^{2} - 1^{2}) = 0$

Step 1.5

Factor.

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Step 1.5.1

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 3 x$ and $b = 1$ .

$(x + 1) ((3 x + 1) (3 x - 1)) = 0$

Step 1.5.2

Remove unnecessary parentheses.

$(x + 1) (3 x + 1) (3 x - 1) = 0$

Step 2

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x + 1 = 0$

$3 x + 1 = 0$

$3 x - 1 = 0$

Step 3

Set $x + 1$ equal to $0$ and solve for $x$ .

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Step 3.1

Set $x + 1$ equal to $0$ .

$x + 1 = 0$

Step 3.2

Subtract $1$ from both sides of the equation.

$x = - 1$

Step 4

Set $3 x + 1$ equal to $0$ and solve for $x$ .

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Step 4.1

Set $3 x + 1$ equal to $0$ .

$3 x + 1 = 0$

Step 4.2

Solve $3 x + 1 = 0$ for $x$ .

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Step 4.2.1

Subtract $1$ from both sides of the equation.

$3 x = - 1$

Step 4.2.2

Divide each term in $3 x = - 1$ by $3$ and simplify.

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Step 4.2.2.1

Divide each term in $3 x = - 1$ by $3$ .

$\frac{3 x}{3} = \frac{- 1}{3}$

Step 4.2.2.2

Simplify the left side.

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Step 4.2.2.2.1

Cancel the common factor of $3$ .

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Step 4.2.2.2.1.1

Cancel the common factor.

$\frac{3 x}{3} = \frac{- 1}{3}$

Step 4.2.2.2.1.2

Divide $x$ by $1$ .

$x = \frac{- 1}{3}$

Step 4.2.2.3

Simplify the right side.

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Step 4.2.2.3.1

Move the negative in front of the fraction.

$x = - \frac{1}{3}$

Step 5

Set $3 x - 1$ equal to $0$ and solve for $x$ .

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Step 5.1

Set $3 x - 1$ equal to $0$ .

$3 x - 1 = 0$

Step 5.2

Solve $3 x - 1 = 0$ for $x$ .

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Step 5.2.1

Add $1$ to both sides of the equation.

$3 x = 1$

Step 5.2.2

Divide each term in $3 x = 1$ by $3$ and simplify.

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Step 5.2.2.1

Divide each term in $3 x = 1$ by $3$ .

$\frac{3 x}{3} = \frac{1}{3}$

Step 5.2.2.2

Simplify the left side.

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Step 5.2.2.2.1

Cancel the common factor of $3$ .

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Step 5.2.2.2.1.1

Cancel the common factor.

$\frac{3 x}{3} = \frac{1}{3}$

Step 5.2.2.2.1.2

Divide $x$ by $1$ .

$x = \frac{1}{3}$

Step 6

The final solution is all the values that make $(x + 1) (3 x + 1) (3 x - 1) = 0$ true.

$x = - 1, - \frac{1}{3}, \frac{1}{3}$

Step 7

The result can be shown in multiple forms.

Exact Form:

$x = - 1, - \frac{1}{3}, \frac{1}{3}$

Decimal Form:

$x = - 1, - 0.\overline{3}, 0.\overline{3}$