Precalculus Examples

x = \frac{1}{10} \cdot (\frac{3 (10) - 7}{2 (10) + 9})

$x = \frac{1}{10} \cdot (\frac{3 (10) - 7}{2 (10) + 9})$

Step 1

Multiply

\frac{1}{10}

$\frac{1}{10}$ by

\frac{3 (10) - 7}{2 (10) + 9}

$\frac{3 (10) - 7}{2 (10) + 9}$ .

x = \frac{1}{10} \cdot \frac{3 (10) - 7}{2 (10) + 9}

$x = \frac{1}{10} \cdot \frac{3 (10) - 7}{2 (10) + 9}$

Step 2

Simplify

\frac{1}{10} \cdot \frac{3 (10) - 7}{2 (10) + 9}

$\frac{1}{10} \cdot \frac{3 (10) - 7}{2 (10) + 9}$ .

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Step 2.1

Simplify the numerator.

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Step 2.1.1

Multiply

3

$3$ by

10

$10$ .

x = \frac{1}{10} \cdot \frac{30 - 7}{2 (10) + 9}

$x = \frac{1}{10} \cdot \frac{30 - 7}{2 (10) + 9}$

Step 2.1.2

Subtract

7

$7$ from

30

$30$ .

x = \frac{1}{10} \cdot \frac{23}{2 (10) + 9}

$x = \frac{1}{10} \cdot \frac{23}{2 (10) + 9}$

x = \frac{1}{10} \cdot \frac{23}{2 (10) + 9}

$x = \frac{1}{10} \cdot \frac{23}{2 (10) + 9}$

Step 2.2

Simplify the denominator.

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Step 2.2.1

Multiply

2

$2$ by

10

$10$ .

x = \frac{1}{10} \cdot \frac{23}{20 + 9}

$x = \frac{1}{10} \cdot \frac{23}{20 + 9}$

Step 2.2.2

Add

20

$20$ and

9

$9$ .

x = \frac{1}{10} \cdot \frac{23}{29}

$x = \frac{1}{10} \cdot \frac{23}{29}$

x = \frac{1}{10} \cdot \frac{23}{29}

$x = \frac{1}{10} \cdot \frac{23}{29}$

Step 2.3

Multiply

\frac{1}{10} \cdot \frac{23}{29}

$\frac{1}{10} \cdot \frac{23}{29}$ .

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Step 2.3.1

Multiply

\frac{1}{10}

$\frac{1}{10}$ by

\frac{23}{29}

$\frac{23}{29}$ .

x = \frac{23}{10 \cdot 29}

$x = \frac{23}{10 \cdot 29}$

Step 2.3.2

Multiply

10

$10$ by

29

$29$ .

x = \frac{23}{290}

$x = \frac{23}{290}$

x = \frac{23}{290}

$x = \frac{23}{290}$

x = \frac{23}{290}

$x = \frac{23}{290}$

Step 3

The result can be shown in multiple forms.

Exact Form:

x = \frac{23}{290}

$x = \frac{23}{290}$

Decimal Form:

x = 0.07931034 \dots

$x = 0.07931034 \dots$