Precalculus Examples

$\sin (2 x + \frac{π}{3}) = \frac{\sqrt{3}}{2}$

Step 1

Take the inverse sine of both sides of the equation to extract $x$ from inside the sine.

$2 x + \frac{π}{3} = \arcsin (\frac{\sqrt{3}}{2})$

Step 2

Simplify the right side.

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Step 2.1

The exact value of $\arcsin (\frac{\sqrt{3}}{2})$ is $\frac{π}{3}$ .

$2 x + \frac{π}{3} = \frac{π}{3}$

Step 3

Move all terms not containing $x$ to the right side of the equation.

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Step 3.1

Subtract $\frac{π}{3}$ from both sides of the equation.

$2 x = \frac{π}{3} - \frac{π}{3}$

Step 3.2

Combine the numerators over the common denominator.

$2 x = \frac{π - π}{3}$

Step 3.3

Subtract $π$ from $π$ .

$2 x = \frac{0}{3}$

Step 3.4

Divide $0$ by $3$ .

$2 x = 0$

Step 4

Divide each term in $2 x = 0$ by $2$ and simplify.

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Step 4.1

Divide each term in $2 x = 0$ by $2$ .

$\frac{2 x}{2} = \frac{0}{2}$

Step 4.2

Simplify the left side.

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Step 4.2.1

Cancel the common factor of $2$ .

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Step 4.2.1.1

Cancel the common factor.

$\frac{2 x}{2} = \frac{0}{2}$

Step 4.2.1.2

Divide $x$ by $1$ .

$x = \frac{0}{2}$

Step 4.3

Simplify the right side.

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Step 4.3.1

Divide $0$ by $2$ .

$x = 0$

Step 5

The sine function is positive in the first and second quadrants. To find the second solution, subtract the reference angle from $π$ to find the solution in the second quadrant.

$2 x + \frac{π}{3} = π - \frac{π}{3}$

Step 6

Solve for $x$ .

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Step 6.1

Simplify $π - \frac{π}{3}$ .

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Step 6.1.1

To write $π$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$2 x + \frac{π}{3} = π \cdot \frac{3}{3} - \frac{π}{3}$

Step 6.1.2

Combine fractions.

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Step 6.1.2.1

Combine $π$ and $\frac{3}{3}$ .

$2 x + \frac{π}{3} = \frac{π \cdot 3}{3} - \frac{π}{3}$

Step 6.1.2.2

Combine the numerators over the common denominator.

$2 x + \frac{π}{3} = \frac{π \cdot 3 - π}{3}$

Step 6.1.3

Simplify the numerator.

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Step 6.1.3.1

Move $3$ to the left of $π$ .

$2 x + \frac{π}{3} = \frac{3 \cdot π - π}{3}$

Step 6.1.3.2

Subtract $π$ from $3 π$ .

$2 x + \frac{π}{3} = \frac{2 π}{3}$

Step 6.2

Move all terms not containing $x$ to the right side of the equation.

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Step 6.2.1

Subtract $\frac{π}{3}$ from both sides of the equation.

$2 x = \frac{2 π}{3} - \frac{π}{3}$

Step 6.2.2

Combine the numerators over the common denominator.

$2 x = \frac{2 π - π}{3}$

Step 6.2.3

Subtract $π$ from $2 π$ .

$2 x = \frac{π}{3}$

Step 6.3

Divide each term in $2 x = \frac{π}{3}$ by $2$ and simplify.

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Step 6.3.1

Divide each term in $2 x = \frac{π}{3}$ by $2$ .

$\frac{2 x}{2} = \frac{\frac{π}{3}}{2}$

Step 6.3.2

Simplify the left side.

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Step 6.3.2.1

Cancel the common factor of $2$ .

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Step 6.3.2.1.1

Cancel the common factor.

$\frac{2 x}{2} = \frac{\frac{π}{3}}{2}$

Step 6.3.2.1.2

Divide $x$ by $1$ .

$x = \frac{\frac{π}{3}}{2}$

Step 6.3.3

Simplify the right side.

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Step 6.3.3.1

Multiply the numerator by the reciprocal of the denominator.

$x = \frac{π}{3} \cdot \frac{1}{2}$

Step 6.3.3.2

Multiply $\frac{π}{3} \cdot \frac{1}{2}$ .

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Step 6.3.3.2.1

Multiply $\frac{π}{3}$ by $\frac{1}{2}$ .

$x = \frac{π}{3 \cdot 2}$

Step 6.3.3.2.2

Multiply $3$ by $2$ .

$x = \frac{π}{6}$

Step 7

Find the period of $\sin (2 x + \frac{π}{3})$ .

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Step 7.1

The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Step 7.2

Replace $b$ with $2$ in the formula for period.

$\frac{2 π}{| 2 |}$

Step 7.3

The absolute value is the distance between a number and zero. The distance between $0$ and $2$ is $2$ .

$\frac{2 π}{2}$

Step 7.4

Cancel the common factor of $2$ .

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Step 7.4.1

Cancel the common factor.

$\frac{2 π}{2}$

Step 7.4.2

Divide $π$ by $1$ .

$π$

Step 8

The period of the $\sin (2 x + \frac{π}{3})$ function is $π$ so values will repeat every $π$ radians in both directions.

$x = π n, \frac{π}{6} + π n$ , for any integer $n$