Precalculus Examples

$\sec (x) = \frac{\sqrt{37}}{6}$

Step 1

Use the definition of secant to find the known sides of the unit circle right triangle. The quadrant determines the sign on each of the values.

$\sec (x) = \frac{hypotenuse}{adjacent}$

Step 2

Find the opposite side of the unit circle triangle. Since the adjacent side and hypotenuse are known, use the Pythagorean theorem to find the remaining side.

$Opposite = \sqrt{{hypotenuse}^{2} - {adjacent}^{2}}$

Step 3

Replace the known values in the equation.

$Opposite = \sqrt{{(\sqrt{37})}^{2} - {(6)}^{2}}$

Step 4

Simplify inside the radical.

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Step 4.1

Rewrite ${\sqrt{37}}^{2}$ as $37$ .

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Step 4.1.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{37}$ as $37^{\frac{1}{2}}$ .

Opposite $= \sqrt{{(37^{\frac{1}{2}})}^{2} - {(6)}^{2}}$

Step 4.1.2

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

Opposite $= \sqrt{37^{\frac{1}{2} \cdot 2} - {(6)}^{2}}$

Step 4.1.3

Combine $\frac{1}{2}$ and $2$ .

Opposite $= \sqrt{37^{\frac{2}{2}} - {(6)}^{2}}$

Step 4.1.4

Cancel the common factor of $2$ .

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Step 4.1.4.1

Cancel the common factor.

Opposite $= \sqrt{37^{\frac{2}{2}} - {(6)}^{2}}$

Step 4.1.4.2

Rewrite the expression.

Opposite $= \sqrt{37 - {(6)}^{2}}$

Step 4.1.5

Evaluate the exponent.

Opposite $= \sqrt{37 - {(6)}^{2}}$

Step 4.2

Raise $6$ to the power of $2$ .

Opposite $= \sqrt{37 - 1 \cdot 36}$

Step 4.3

Multiply $- 1$ by $36$ .

Opposite $= \sqrt{37 - 36}$

Step 4.4

Subtract $36$ from $37$ .

Opposite $= \sqrt{1}$

Step 4.5

Any root of $1$ is $1$ .

Opposite $= 1$

Step 5

Find the value of sine.

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Step 5.1

Use the definition of sine to find the value of $\sin (x)$ .

$\sin (x) = \frac{opp}{hyp}$

Step 5.2

Substitute in the known values.

$\sin (x) = \frac{1}{\sqrt{37}}$

Step 5.3

Simplify the value of $\sin (x)$ .

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Step 5.3.1

Multiply $\frac{1}{\sqrt{37}}$ by $\frac{\sqrt{37}}{\sqrt{37}}$ .

$\sin (x) = \frac{1}{\sqrt{37}} \cdot \frac{\sqrt{37}}{\sqrt{37}}$

Step 5.3.2

Combine and simplify the denominator.

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Step 5.3.2.1

Multiply $\frac{1}{\sqrt{37}}$ by $\frac{\sqrt{37}}{\sqrt{37}}$ .

$\sin (x) = \frac{\sqrt{37}}{\sqrt{37} \sqrt{37}}$

Step 5.3.2.2

Raise $\sqrt{37}$ to the power of $1$ .

$\sin (x) = \frac{\sqrt{37}}{\sqrt{37} \sqrt{37}}$

Step 5.3.2.3

Raise $\sqrt{37}$ to the power of $1$ .

$\sin (x) = \frac{\sqrt{37}}{\sqrt{37} \sqrt{37}}$

Step 5.3.2.4

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\sin (x) = \frac{\sqrt{37}}{{\sqrt{37}}^{1 + 1}}$

Step 5.3.2.5

Add $1$ and $1$ .

$\sin (x) = \frac{\sqrt{37}}{{\sqrt{37}}^{2}}$

Step 5.3.2.6

Rewrite ${\sqrt{37}}^{2}$ as $37$ .

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Step 5.3.2.6.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{37}$ as $37^{\frac{1}{2}}$ .

$\sin (x) = \frac{\sqrt{37}}{{(37^{\frac{1}{2}})}^{2}}$

Step 5.3.2.6.2

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\sin (x) = \frac{\sqrt{37}}{37^{\frac{1}{2} \cdot 2}}$

Step 5.3.2.6.3

Combine $\frac{1}{2}$ and $2$ .

$\sin (x) = \frac{\sqrt{37}}{37^{\frac{2}{2}}}$

Step 5.3.2.6.4

Cancel the common factor of $2$ .

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Step 5.3.2.6.4.1

Cancel the common factor.

$\sin (x) = \frac{\sqrt{37}}{37^{\frac{2}{2}}}$

Step 5.3.2.6.4.2

Rewrite the expression.

$\sin (x) = \frac{\sqrt{37}}{37}$

Step 5.3.2.6.5

Evaluate the exponent.

$\sin (x) = \frac{\sqrt{37}}{37}$

Step 6

Find the value of cosine.

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Step 6.1

Use the definition of cosine to find the value of $\cos (x)$ .

$\cos (x) = \frac{adj}{hyp}$

Step 6.2

Substitute in the known values.

$\cos (x) = \frac{6}{\sqrt{37}}$

Step 6.3

Simplify the value of $\cos (x)$ .

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Step 6.3.1

Multiply $\frac{6}{\sqrt{37}}$ by $\frac{\sqrt{37}}{\sqrt{37}}$ .

$\cos (x) = \frac{6}{\sqrt{37}} \cdot \frac{\sqrt{37}}{\sqrt{37}}$

Step 6.3.2

Combine and simplify the denominator.

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Step 6.3.2.1

Multiply $\frac{6}{\sqrt{37}}$ by $\frac{\sqrt{37}}{\sqrt{37}}$ .

$\cos (x) = \frac{6 \sqrt{37}}{\sqrt{37} \sqrt{37}}$

Step 6.3.2.2

Raise $\sqrt{37}$ to the power of $1$ .

$\cos (x) = \frac{6 \sqrt{37}}{\sqrt{37} \sqrt{37}}$

Step 6.3.2.3

Raise $\sqrt{37}$ to the power of $1$ .

$\cos (x) = \frac{6 \sqrt{37}}{\sqrt{37} \sqrt{37}}$

Step 6.3.2.4

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\cos (x) = \frac{6 \sqrt{37}}{{\sqrt{37}}^{1 + 1}}$

Step 6.3.2.5

Add $1$ and $1$ .

$\cos (x) = \frac{6 \sqrt{37}}{{\sqrt{37}}^{2}}$

Step 6.3.2.6

Rewrite ${\sqrt{37}}^{2}$ as $37$ .

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Step 6.3.2.6.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{37}$ as $37^{\frac{1}{2}}$ .

$\cos (x) = \frac{6 \sqrt{37}}{{(37^{\frac{1}{2}})}^{2}}$

Step 6.3.2.6.2

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\cos (x) = \frac{6 \sqrt{37}}{37^{\frac{1}{2} \cdot 2}}$

Step 6.3.2.6.3

Combine $\frac{1}{2}$ and $2$ .

$\cos (x) = \frac{6 \sqrt{37}}{37^{\frac{2}{2}}}$

Step 6.3.2.6.4

Cancel the common factor of $2$ .

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Step 6.3.2.6.4.1

Cancel the common factor.

$\cos (x) = \frac{6 \sqrt{37}}{37^{\frac{2}{2}}}$

Step 6.3.2.6.4.2

Rewrite the expression.

$\cos (x) = \frac{6 \sqrt{37}}{37}$

Step 6.3.2.6.5

Evaluate the exponent.

$\cos (x) = \frac{6 \sqrt{37}}{37}$

Step 7

Find the value of tangent.

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Step 7.1

Use the definition of tangent to find the value of $\tan (x)$ .

$\tan (x) = \frac{opp}{adj}$

Step 7.2

Substitute in the known values.

$\tan (x) = \frac{1}{6}$

Step 8

Find the value of cotangent.

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Step 8.1

Use the definition of cotangent to find the value of $\cot (x)$ .

$\cot (x) = \frac{adj}{opp}$

Step 8.2

Substitute in the known values.

$\cot (x) = \frac{6}{1}$

Step 8.3

Divide $6$ by $1$ .

$\cot (x) = 6$

Step 9

Find the value of cosecant.

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Step 9.1

Use the definition of cosecant to find the value of $\csc (x)$ .

$\csc (x) = \frac{hyp}{opp}$

Step 9.2

Substitute in the known values.

$\csc (x) = \frac{\sqrt{37}}{1}$

Step 9.3

Divide $\sqrt{37}$ by $1$ .

$\csc (x) = \sqrt{37}$

Step 10

This is the solution to each trig value.

$\sin (x) = \frac{\sqrt{37}}{37}$

$\cos (x) = \frac{6 \sqrt{37}}{37}$

$\tan (x) = \frac{1}{6}$

$\cot (x) = 6$

$\sec (x) = \frac{\sqrt{37}}{6}$

$\csc (x) = \sqrt{37}$