Precalculus Examples

$- 0.3476 x^{2} + 10.948 x - 23.078 = 0.9699$

Step 1

Move all terms to the left side of the equation and simplify.

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Step 1.1

Subtract $0.9699$ from both sides of the equation.

$- 0.3476 x^{2} + 10.948 x - 23.078 - 0.9699 = 0$

Step 1.2

Subtract $0.9699$ from $- 23.078$ .

$- 0.3476 x^{2} + 10.948 x - 24.0479 = 0$

Step 2

Once the quadratic is in standard form, the values of $a$ , $b$ , and $c$ can be found.

$a x^{2} + b x + c$

Step 3

Use the standard form of the equation to find $a$ , $b$ , and $c$ for this quadratic.

$a = - 0.3476$ , $b = 10.948$ , $c = - 24.0479$