Precalculus Examples

$\frac{6 x + 5}{x^{4} - 25 x^{2}}$

Step 1

Decompose the fraction and multiply through by the common denominator.

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Step 1.1

Factor the fraction.

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Step 1.1.1

Factor $x^{2}$ out of $x^{4} - 25 x^{2}$ .

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Step 1.1.1.1

Factor $x^{2}$ out of $x^{4}$ .

$\frac{6 x + 5}{x^{2} x^{2} - 25 x^{2}}$

Step 1.1.1.2

Factor $x^{2}$ out of $- 25 x^{2}$ .

$\frac{6 x + 5}{x^{2} x^{2} + x^{2} \cdot - 25}$

Step 1.1.1.3

Factor $x^{2}$ out of $x^{2} x^{2} + x^{2} \cdot - 25$ .

$\frac{6 x + 5}{x^{2} (x^{2} - 25)}$

Step 1.1.2

Rewrite $25$ as $5^{2}$ .

$\frac{6 x + 5}{x^{2} (x^{2} - 5^{2})}$

Step 1.1.3

Factor.

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Step 1.1.3.1

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x$ and $b = 5$ .

$\frac{6 x + 5}{x^{2} ((x + 5) (x - 5))}$

Step 1.1.3.2

Remove unnecessary parentheses.

$\frac{6 x + 5}{x^{2} (x + 5) (x - 5)}$

Step 1.2

For each factor in the denominator, create a new fraction using the factor as the denominator, and an unknown value as the numerator. Since the factor in the denominator is linear, put a single variable in its place $C$ .

$\frac{A}{x^{2}} + \frac{B}{x} + \frac{C}{x + 5}$

Step 1.3

$\frac{A}{x^{2}} + \frac{B}{x} + \frac{C}{x + 5} + \frac{D}{x - 5}$

Step 1.4

Multiply each fraction in the equation by the denominator of the original expression. In this case, the denominator is $x^{2} (x + 5) (x - 5)$ .

$\frac{(6 x + 5) (x^{2} (x + 5) (x - 5))}{x^{2} (x + 5) (x - 5)} = \frac{A (x^{2} (x + 5) (x - 5))}{x^{2}} + \frac{B (x^{2} (x + 5) (x - 5))}{x} + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.5

Cancel the common factor of $x^{2}$ .

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Step 1.5.1

Cancel the common factor.

Step 1.5.2

Rewrite the expression.

$\frac{(6 x + 5) ((x + 5) (x - 5))}{(x + 5) (x - 5)} = \frac{A (x^{2} (x + 5) (x - 5))}{x^{2}} + \frac{B (x^{2} (x + 5) (x - 5))}{x} + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.6

Cancel the common factor of $x + 5$ .

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Step 1.6.1

Cancel the common factor.

Step 1.6.2

Rewrite the expression.

$\frac{(6 x + 5) (x - 5)}{x - 5} = \frac{A (x^{2} (x + 5) (x - 5))}{x^{2}} + \frac{B (x^{2} (x + 5) (x - 5))}{x} + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.7

Cancel the common factor of $x - 5$ .

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Step 1.7.1

Cancel the common factor.

Step 1.7.2

Divide $6 x + 5$ by $1$ .

$6 x + 5 = \frac{A (x^{2} (x + 5) (x - 5))}{x^{2}} + \frac{B (x^{2} (x + 5) (x - 5))}{x} + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8

Simplify each term.

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Step 1.8.1

Cancel the common factor of $x^{2}$ .

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Step 1.8.1.1

Cancel the common factor.

$6 x + 5 = \frac{A (x^{2} (x + 5) (x - 5))}{x^{2}} + \frac{B (x^{2} (x + 5) (x - 5))}{x} + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.1.2

Divide $A ((x + 5) (x - 5))$ by $1$ .

$6 x + 5 = A ((x + 5) (x - 5)) + \frac{B (x^{2} (x + 5) (x - 5))}{x} + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.2

Expand $(x + 5) (x - 5)$ using the FOIL Method.

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Step 1.8.2.1

Apply the distributive property.

$6 x + 5 = A (x (x - 5) + 5 (x - 5)) + \frac{B (x^{2} (x + 5) (x - 5))}{x} + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.2.2

Apply the distributive property.

$6 x + 5 = A (x \cdot x + x \cdot - 5 + 5 (x - 5)) + \frac{B (x^{2} (x + 5) (x - 5))}{x} + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.2.3

Apply the distributive property.

$6 x + 5 = A (x \cdot x + x \cdot - 5 + 5 x + 5 \cdot - 5) + \frac{B (x^{2} (x + 5) (x - 5))}{x} + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.3

Combine the opposite terms in $x \cdot x + x \cdot - 5 + 5 x + 5 \cdot - 5$ .

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Step 1.8.3.1

Reorder the factors in the terms $x \cdot - 5$ and $5 x$ .

$6 x + 5 = A (x \cdot x - 5 x + 5 x + 5 \cdot - 5) + \frac{B (x^{2} (x + 5) (x - 5))}{x} + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.3.2

Add $- 5 x$ and $5 x$ .

$6 x + 5 = A (x \cdot x + 0 + 5 \cdot - 5) + \frac{B (x^{2} (x + 5) (x - 5))}{x} + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.3.3

Add $x \cdot x$ and $0$ .

$6 x + 5 = A (x \cdot x + 5 \cdot - 5) + \frac{B (x^{2} (x + 5) (x - 5))}{x} + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.4

Simplify each term.

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Step 1.8.4.1

Multiply $x$ by $x$ .

$6 x + 5 = A (x^{2} + 5 \cdot - 5) + \frac{B (x^{2} (x + 5) (x - 5))}{x} + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.4.2

Multiply $5$ by $- 5$ .

$6 x + 5 = A (x^{2} - 25) + \frac{B (x^{2} (x + 5) (x - 5))}{x} + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.5

Apply the distributive property.

$6 x + 5 = A x^{2} + A \cdot - 25 + \frac{B (x^{2} (x + 5) (x - 5))}{x} + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.6

Move $- 25$ to the left of $A$ .

$6 x + 5 = A x^{2} - 25 \cdot A + \frac{B (x^{2} (x + 5) (x - 5))}{x} + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.7

Cancel the common factor of $x^{2}$ and $x$ .

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Step 1.8.7.1

Factor $x$ out of $B (x^{2} (x + 5) (x - 5))$ .

$6 x + 5 = A x^{2} - 25 A + \frac{x (B ((x (x + 5)) (x - 5)))}{x} + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.7.2

Cancel the common factors.

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Step 1.8.7.2.1

Raise $x$ to the power of $1$ .

$6 x + 5 = A x^{2} - 25 A + \frac{x (B ((x (x + 5)) (x - 5)))}{x} + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.7.2.2

Factor $x$ out of $x^{1}$ .

$6 x + 5 = A x^{2} - 25 A + \frac{x (B ((x (x + 5)) (x - 5)))}{x \cdot 1} + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.7.2.3

Cancel the common factor.

$6 x + 5 = A x^{2} - 25 A + \frac{x (B ((x (x + 5)) (x - 5)))}{x \cdot 1} + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.7.2.4

Rewrite the expression.

$6 x + 5 = A x^{2} - 25 A + \frac{B ((x (x + 5)) (x - 5))}{1} + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.7.2.5

Divide $B ((x (x + 5)) (x - 5))$ by $1$ .

$6 x + 5 = A x^{2} - 25 A + B ((x (x + 5)) (x - 5)) + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.8

Apply the distributive property.

$6 x + 5 = A x^{2} - 25 A + B ((x \cdot x + x \cdot 5) (x - 5)) + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.9

Multiply $x$ by $x$ .

$6 x + 5 = A x^{2} - 25 A + B ((x^{2} + x \cdot 5) (x - 5)) + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.10

Move $5$ to the left of $x$ .

$6 x + 5 = A x^{2} - 25 A + B ((x^{2} + 5 \cdot x) (x - 5)) + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.11

Expand $(x^{2} + 5 x) (x - 5)$ using the FOIL Method.

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Step 1.8.11.1

Apply the distributive property.

$6 x + 5 = A x^{2} - 25 A + B (x^{2} (x - 5) + 5 x (x - 5)) + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.11.2

Apply the distributive property.

$6 x + 5 = A x^{2} - 25 A + B (x^{2} x + x^{2} \cdot - 5 + 5 x (x - 5)) + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.11.3

Apply the distributive property.

$6 x + 5 = A x^{2} - 25 A + B (x^{2} x + x^{2} \cdot - 5 + 5 x \cdot x + 5 x \cdot - 5) + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.12

Simplify and combine like terms.

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Step 1.8.12.1

Simplify each term.

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Step 1.8.12.1.1

Multiply $x^{2}$ by $x$ by adding the exponents.

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Step 1.8.12.1.1.1

Multiply $x^{2}$ by $x$ .

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Step 1.8.12.1.1.1.1

Raise $x$ to the power of $1$ .

$6 x + 5 = A x^{2} - 25 A + B (x^{2} x + x^{2} \cdot - 5 + 5 x \cdot x + 5 x \cdot - 5) + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.12.1.1.1.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$6 x + 5 = A x^{2} - 25 A + B (x^{2 + 1} + x^{2} \cdot - 5 + 5 x \cdot x + 5 x \cdot - 5) + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.12.1.1.2

Add $2$ and $1$ .

$6 x + 5 = A x^{2} - 25 A + B (x^{3} + x^{2} \cdot - 5 + 5 x \cdot x + 5 x \cdot - 5) + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.12.1.2

Move $- 5$ to the left of $x^{2}$ .

$6 x + 5 = A x^{2} - 25 A + B (x^{3} - 5 \cdot x^{2} + 5 x \cdot x + 5 x \cdot - 5) + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.12.1.3

Multiply $x$ by $x$ by adding the exponents.

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Step 1.8.12.1.3.1

Move $x$ .

$6 x + 5 = A x^{2} - 25 A + B (x^{3} - 5 x^{2} + 5 (x \cdot x) + 5 x \cdot - 5) + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.12.1.3.2

Multiply $x$ by $x$ .

$6 x + 5 = A x^{2} - 25 A + B (x^{3} - 5 x^{2} + 5 x^{2} + 5 x \cdot - 5) + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.12.1.4

Multiply $- 5$ by $5$ .

$6 x + 5 = A x^{2} - 25 A + B (x^{3} - 5 x^{2} + 5 x^{2} - 25 x) + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.12.2

Add $- 5 x^{2}$ and $5 x^{2}$ .

$6 x + 5 = A x^{2} - 25 A + B (x^{3} + 0 - 25 x) + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.12.3

Add $x^{3}$ and $0$ .

$6 x + 5 = A x^{2} - 25 A + B (x^{3} - 25 x) + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.13

Apply the distributive property.

$6 x + 5 = A x^{2} - 25 A + B x^{3} + B (- 25 x) + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.14

Rewrite using the commutative property of multiplication.

$6 x + 5 = A x^{2} - 25 A + B x^{3} - 25 B x + \frac{(C) (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.15

Cancel the common factor of $x + 5$ .

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Step 1.8.15.1

Cancel the common factor.

$6 x + 5 = A x^{2} - 25 A + B x^{3} - 25 B x + \frac{C (x^{2} (x + 5) (x - 5))}{x + 5} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.15.2

Divide $(C) (x^{2} (x - 5))$ by $1$ .

$6 x + 5 = A x^{2} - 25 A + B x^{3} - 25 B x + (C) (x^{2} (x - 5)) + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.16

Apply the distributive property.

$6 x + 5 = A x^{2} - 25 A + B x^{3} - 25 B x + C (x^{2} x + x^{2} \cdot - 5) + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.17

Multiply $x^{2}$ by $x$ by adding the exponents.

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Step 1.8.17.1

Multiply $x^{2}$ by $x$ .

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Step 1.8.17.1.1

Raise $x$ to the power of $1$ .

$6 x + 5 = A x^{2} - 25 A + B x^{3} - 25 B x + C (x^{2} x + x^{2} \cdot - 5) + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.17.1.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$6 x + 5 = A x^{2} - 25 A + B x^{3} - 25 B x + C (x^{2 + 1} + x^{2} \cdot - 5) + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.17.2

Add $2$ and $1$ .

$6 x + 5 = A x^{2} - 25 A + B x^{3} - 25 B x + C (x^{3} + x^{2} \cdot - 5) + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.18

Move $- 5$ to the left of $x^{2}$ .

$6 x + 5 = A x^{2} - 25 A + B x^{3} - 25 B x + C (x^{3} - 5 \cdot x^{2}) + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.19

Apply the distributive property.

$6 x + 5 = A x^{2} - 25 A + B x^{3} - 25 B x + C x^{3} + C (- 5 x^{2}) + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.20

Rewrite using the commutative property of multiplication.

$6 x + 5 = A x^{2} - 25 A + B x^{3} - 25 B x + C x^{3} - 5 C x^{2} + \frac{(D) (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.21

Cancel the common factor of $x - 5$ .

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Step 1.8.21.1

Cancel the common factor.

$6 x + 5 = A x^{2} - 25 A + B x^{3} - 25 B x + C x^{3} - 5 C x^{2} + \frac{D (x^{2} (x + 5) (x - 5))}{x - 5}$

Step 1.8.21.2

Divide $(D) (x^{2} (x + 5))$ by $1$ .

$6 x + 5 = A x^{2} - 25 A + B x^{3} - 25 B x + C x^{3} - 5 C x^{2} + (D) (x^{2} (x + 5))$

Step 1.8.22

Apply the distributive property.

$6 x + 5 = A x^{2} - 25 A + B x^{3} - 25 B x + C x^{3} - 5 C x^{2} + D (x^{2} x + x^{2} \cdot 5)$

Step 1.8.23

Multiply $x^{2}$ by $x$ by adding the exponents.

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Step 1.8.23.1

Multiply $x^{2}$ by $x$ .

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Step 1.8.23.1.1

Raise $x$ to the power of $1$ .

$6 x + 5 = A x^{2} - 25 A + B x^{3} - 25 B x + C x^{3} - 5 C x^{2} + D (x^{2} x + x^{2} \cdot 5)$

Step 1.8.23.1.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$6 x + 5 = A x^{2} - 25 A + B x^{3} - 25 B x + C x^{3} - 5 C x^{2} + D (x^{2 + 1} + x^{2} \cdot 5)$

Step 1.8.23.2

Add $2$ and $1$ .

$6 x + 5 = A x^{2} - 25 A + B x^{3} - 25 B x + C x^{3} - 5 C x^{2} + D (x^{3} + x^{2} \cdot 5)$

Step 1.8.24

Move $5$ to the left of $x^{2}$ .

$6 x + 5 = A x^{2} - 25 A + B x^{3} - 25 B x + C x^{3} - 5 C x^{2} + D (x^{3} + 5 \cdot x^{2})$

Step 1.8.25

Apply the distributive property.

$6 x + 5 = A x^{2} - 25 A + B x^{3} - 25 B x + C x^{3} - 5 C x^{2} + D x^{3} + D (5 x^{2})$

Step 1.8.26

Rewrite using the commutative property of multiplication.

$6 x + 5 = A x^{2} - 25 A + B x^{3} - 25 B x + C x^{3} - 5 C x^{2} + D x^{3} + 5 D x^{2}$

Step 1.9

Simplify the expression.

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Step 1.9.1

Move $B$ .

$6 x + 5 = A x^{2} - 25 A + B x^{3} - 25 x B + C x^{3} - 5 C x^{2} + D x^{3} + 5 D x^{2}$

Step 1.9.2

Move $- 25 A$ .

$6 x + 5 = A x^{2} + B x^{3} - 25 x B + C x^{3} - 5 C x^{2} + D x^{3} + 5 D x^{2} - 25 A$

Step 1.9.3

Move $- 25 x B$ .

$6 x + 5 = A x^{2} + B x^{3} + C x^{3} - 5 C x^{2} + D x^{3} + 5 D x^{2} - 25 x B - 25 A$

Step 1.9.4

Move $- 5 C x^{2}$ .

$6 x + 5 = A x^{2} + B x^{3} + C x^{3} + D x^{3} - 5 C x^{2} + 5 D x^{2} - 25 x B - 25 A$

Step 1.9.5

Move $A x^{2}$ .

$6 x + 5 = B x^{3} + C x^{3} + D x^{3} + A x^{2} - 5 C x^{2} + 5 D x^{2} - 25 x B - 25 A$

Step 2

Create equations for the partial fraction variables and use them to set up a system of equations.

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Step 2.1

Create an equation for the partial fraction variables by equating the coefficients of $x^{3}$ from each side of the equation. For the equation to be equal, the equivalent coefficients on each side of the equation must be equal.

$0 = B + C + D$

Step 2.2

Create an equation for the partial fraction variables by equating the coefficients of $x^{2}$ from each side of the equation. For the equation to be equal, the equivalent coefficients on each side of the equation must be equal.

$0 = A - 5 C + 5 D$

Step 2.3

Create an equation for the partial fraction variables by equating the coefficients of $x$ from each side of the equation. For the equation to be equal, the equivalent coefficients on each side of the equation must be equal.

$6 = - 25 B$

Step 2.4

Create an equation for the partial fraction variables by equating the coefficients of the terms not containing $x$ . For the equation to be equal, the equivalent coefficients on each side of the equation must be equal.

$5 = - 25 A$

Step 2.5

Set up the system of equations to find the coefficients of the partial fractions.

$0 = B + C + D$

$0 = A - 5 C + 5 D$

$6 = - 25 B$

$5 = - 25 A$

$0 = B + C + D$

$0 = A - 5 C + 5 D$

$6 = - 25 B$

$5 = - 25 A$

Step 3

Solve the system of equations.

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Step 3.1

Solve for $B$ in $6 = - 25 B$ .

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Step 3.1.1

Rewrite the equation as $- 25 B = 6$ .

$- 25 B = 6$

$0 = B + C + D$

$0 = A - 5 C + 5 D$

$5 = - 25 A$

Step 3.1.2

Divide each term in $- 25 B = 6$ by $- 25$ and simplify.

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Step 3.1.2.1

Divide each term in $- 25 B = 6$ by $- 25$ .

$\frac{- 25 B}{- 25} = \frac{6}{- 25}$

$0 = B + C + D$

$0 = A - 5 C + 5 D$

$5 = - 25 A$

Step 3.1.2.2

Simplify the left side.

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Step 3.1.2.2.1

Cancel the common factor of $- 25$ .

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Step 3.1.2.2.1.1

Cancel the common factor.

$\frac{- 25 B}{- 25} = \frac{6}{- 25}$

$0 = B + C + D$

$0 = A - 5 C + 5 D$

$5 = - 25 A$

Step 3.1.2.2.1.2

Divide $B$ by $1$ .

$B = \frac{6}{- 25}$

$0 = B + C + D$

$0 = A - 5 C + 5 D$

$5 = - 25 A$

$B = \frac{6}{- 25}$

$0 = B + C + D$

$0 = A - 5 C + 5 D$

$5 = - 25 A$

$B = \frac{6}{- 25}$

$0 = B + C + D$

$0 = A - 5 C + 5 D$

$5 = - 25 A$

Step 3.1.2.3

Simplify the right side.

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Step 3.1.2.3.1

Move the negative in front of the fraction.

$B = - \frac{6}{25}$

$0 = B + C + D$

$0 = A - 5 C + 5 D$

$5 = - 25 A$

$B = - \frac{6}{25}$

$0 = B + C + D$

$0 = A - 5 C + 5 D$

$5 = - 25 A$

$B = - \frac{6}{25}$

$0 = B + C + D$

$0 = A - 5 C + 5 D$

$5 = - 25 A$

$B = - \frac{6}{25}$

$0 = B + C + D$

$0 = A - 5 C + 5 D$

$5 = - 25 A$

Step 3.2

Replace all occurrences of $B$ with $- \frac{6}{25}$ in each equation.

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Step 3.2.1

Replace all occurrences of $B$ in $0 = B + C + D$ with $- \frac{6}{25}$ .

$0 = (- \frac{6}{25}) + C + D$

$B = - \frac{6}{25}$

$0 = A - 5 C + 5 D$

$5 = - 25 A$

Step 3.2.2

Simplify the right side.

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Step 3.2.2.1

Remove parentheses.

$0 = - \frac{6}{25} + C + D$

$B = - \frac{6}{25}$

$0 = A - 5 C + 5 D$

$5 = - 25 A$

$0 = - \frac{6}{25} + C + D$

$B = - \frac{6}{25}$

$0 = A - 5 C + 5 D$

$5 = - 25 A$

Step 3.2.3

Rewrite the equation as $- 25 A = 5$ .

$- 25 A = 5$

$0 = - \frac{6}{25} + C + D$

$B = - \frac{6}{25}$

$0 = A - 5 C + 5 D$

Step 3.2.4

Divide each term in $- 25 A = 5$ by $- 25$ and simplify.

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Step 3.2.4.1

Divide each term in $- 25 A = 5$ by $- 25$ .

$\frac{- 25 A}{- 25} = \frac{5}{- 25}$

$0 = - \frac{6}{25} + C + D$

$B = - \frac{6}{25}$

$0 = A - 5 C + 5 D$

Step 3.2.4.2

Simplify the left side.

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Step 3.2.4.2.1

Cancel the common factor of $- 25$ .

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Step 3.2.4.2.1.1

Cancel the common factor.

$\frac{- 25 A}{- 25} = \frac{5}{- 25}$

$0 = - \frac{6}{25} + C + D$

$B = - \frac{6}{25}$

$0 = A - 5 C + 5 D$

Step 3.2.4.2.1.2

Divide $A$ by $1$ .

$A = \frac{5}{- 25}$

$0 = - \frac{6}{25} + C + D$

$B = - \frac{6}{25}$

$0 = A - 5 C + 5 D$

$A = \frac{5}{- 25}$

$0 = - \frac{6}{25} + C + D$

$B = - \frac{6}{25}$

$0 = A - 5 C + 5 D$

$A = \frac{5}{- 25}$

$0 = - \frac{6}{25} + C + D$

$B = - \frac{6}{25}$

$0 = A - 5 C + 5 D$

Step 3.2.4.3

Simplify the right side.

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Step 3.2.4.3.1

Cancel the common factor of $5$ and $- 25$ .

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Step 3.2.4.3.1.1

Factor $5$ out of $5$ .

$A = \frac{5 (1)}{- 25}$

$0 = - \frac{6}{25} + C + D$

$B = - \frac{6}{25}$

$0 = A - 5 C + 5 D$

Step 3.2.4.3.1.2

Cancel the common factors.

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Step 3.2.4.3.1.2.1

Factor $5$ out of $- 25$ .

$A = \frac{5 \cdot 1}{5 \cdot - 5}$

$0 = - \frac{6}{25} + C + D$

$B = - \frac{6}{25}$

$0 = A - 5 C + 5 D$

Step 3.2.4.3.1.2.2

Cancel the common factor.

$A = \frac{5 \cdot 1}{5 \cdot - 5}$

$0 = - \frac{6}{25} + C + D$

$B = - \frac{6}{25}$

$0 = A - 5 C + 5 D$

Step 3.2.4.3.1.2.3

Rewrite the expression.

$A = \frac{1}{- 5}$

$0 = - \frac{6}{25} + C + D$

$B = - \frac{6}{25}$

$0 = A - 5 C + 5 D$

$A = \frac{1}{- 5}$

$0 = - \frac{6}{25} + C + D$

$B = - \frac{6}{25}$

$0 = A - 5 C + 5 D$

$A = \frac{1}{- 5}$

$0 = - \frac{6}{25} + C + D$

$B = - \frac{6}{25}$

$0 = A - 5 C + 5 D$

Step 3.2.4.3.2

Move the negative in front of the fraction.

$A = - \frac{1}{5}$

$0 = - \frac{6}{25} + C + D$

$B = - \frac{6}{25}$

$0 = A - 5 C + 5 D$

$A = - \frac{1}{5}$

$0 = - \frac{6}{25} + C + D$

$B = - \frac{6}{25}$

$0 = A - 5 C + 5 D$

$A = - \frac{1}{5}$

$0 = - \frac{6}{25} + C + D$

$B = - \frac{6}{25}$

$0 = A - 5 C + 5 D$

$A = - \frac{1}{5}$

$0 = - \frac{6}{25} + C + D$

$B = - \frac{6}{25}$

$0 = A - 5 C + 5 D$

Step 3.3

Replace all occurrences of $A$ with $- \frac{1}{5}$ in each equation.

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Step 3.3.1

Replace all occurrences of $A$ in $0 = A - 5 C + 5 D$ with $- \frac{1}{5}$ .

$0 = (- \frac{1}{5}) - 5 C + 5 D$

$A = - \frac{1}{5}$

$0 = - \frac{6}{25} + C + D$

$B = - \frac{6}{25}$

Step 3.3.2

Simplify the right side.

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Step 3.3.2.1

Remove parentheses.

$0 = - \frac{1}{5} - 5 C + 5 D$

$A = - \frac{1}{5}$

$0 = - \frac{6}{25} + C + D$

$B = - \frac{6}{25}$

$0 = - \frac{1}{5} - 5 C + 5 D$

$A = - \frac{1}{5}$

$0 = - \frac{6}{25} + C + D$

$B = - \frac{6}{25}$

$0 = - \frac{1}{5} - 5 C + 5 D$

$A = - \frac{1}{5}$

$0 = - \frac{6}{25} + C + D$

$B = - \frac{6}{25}$

Step 3.4

Solve for $C$ in $0 = - \frac{6}{25} + C + D$ .

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Step 3.4.1

Rewrite the equation as $- \frac{6}{25} + C + D = 0$ .

$- \frac{6}{25} + C + D = 0$

$0 = - \frac{1}{5} - 5 C + 5 D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.4.2

Move all terms not containing $C$ to the right side of the equation.

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Step 3.4.2.1

Add $\frac{6}{25}$ to both sides of the equation.

$C + D = \frac{6}{25}$

$0 = - \frac{1}{5} - 5 C + 5 D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.4.2.2

Subtract $D$ from both sides of the equation.

$C = \frac{6}{25} - D$

$0 = - \frac{1}{5} - 5 C + 5 D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

$C = \frac{6}{25} - D$

$0 = - \frac{1}{5} - 5 C + 5 D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

$C = \frac{6}{25} - D$

$0 = - \frac{1}{5} - 5 C + 5 D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.5

Replace all occurrences of $C$ with $\frac{6}{25} - D$ in each equation.

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Step 3.5.1

Replace all occurrences of $C$ in $0 = - \frac{1}{5} - 5 C + 5 D$ with $\frac{6}{25} - D$ .

$0 = - \frac{1}{5} - 5 (\frac{6}{25} - D) + 5 D$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.5.2

Simplify the right side.

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Step 3.5.2.1

Simplify $- \frac{1}{5} - 5 (\frac{6}{25} - D) + 5 D$ .

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Step 3.5.2.1.1

Find the common denominator.

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Step 3.5.2.1.1.1

Write $- 5 (\frac{6}{25} - D)$ as a fraction with denominator $1$ .

$0 = - \frac{1}{5} + \frac{- 5 (\frac{6}{25} - D)}{1} + 5 D$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.5.2.1.1.2

Multiply $\frac{- 5 (\frac{6}{25} - D)}{1}$ by $\frac{5}{5}$ .

$0 = - \frac{1}{5} + \frac{- 5 (\frac{6}{25} - D)}{1} \cdot \frac{5}{5} + 5 D$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.5.2.1.1.3

Multiply $\frac{- 5 (\frac{6}{25} - D)}{1}$ by $\frac{5}{5}$ .

$0 = - \frac{1}{5} + \frac{- 5 (\frac{6}{25} - D) \cdot 5}{5} + 5 D$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.5.2.1.1.4

Write $5 D$ as a fraction with denominator $1$ .

$0 = - \frac{1}{5} + \frac{- 5 (\frac{6}{25} - D) \cdot 5}{5} + \frac{5 D}{1}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.5.2.1.1.5

Multiply $\frac{5 D}{1}$ by $\frac{5}{5}$ .

$0 = - \frac{1}{5} + \frac{- 5 (\frac{6}{25} - D) \cdot 5}{5} + \frac{5 D}{1} \cdot \frac{5}{5}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.5.2.1.1.6

Multiply $\frac{5 D}{1}$ by $\frac{5}{5}$ .

$0 = - \frac{1}{5} + \frac{- 5 (\frac{6}{25} - D) \cdot 5}{5} + \frac{5 D \cdot 5}{5}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

$0 = - \frac{1}{5} + \frac{- 5 (\frac{6}{25} - D) \cdot 5}{5} + \frac{5 D \cdot 5}{5}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.5.2.1.2

Combine the numerators over the common denominator.

$0 = \frac{- 1 - 5 (\frac{6}{25} - D) \cdot 5 + 5 D \cdot 5}{5}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.5.2.1.3

Simplify each term.

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Step 3.5.2.1.3.1

Apply the distributive property.

$0 = \frac{- 1 + (- 5 (\frac{6}{25}) - 5 (- D)) \cdot 5 + 5 D \cdot 5}{5}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.5.2.1.3.2

Cancel the common factor of $5$ .

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Step 3.5.2.1.3.2.1

Factor $5$ out of $- 5$ .

$0 = \frac{- 1 + (5 (- 1) (\frac{6}{25}) - 5 (- D)) \cdot 5 + 5 D \cdot 5}{5}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.5.2.1.3.2.2

Factor $5$ out of $25$ .

$0 = \frac{- 1 + (5 \cdot (- 1 \frac{6}{5 \cdot 5}) - 5 (- D)) \cdot 5 + 5 D \cdot 5}{5}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.5.2.1.3.2.3

Cancel the common factor.

$0 = \frac{- 1 + (5 \cdot (- 1 \frac{6}{5 \cdot 5}) - 5 (- D)) \cdot 5 + 5 D \cdot 5}{5}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.5.2.1.3.2.4

Rewrite the expression.

$0 = \frac{- 1 + (- 1 (\frac{6}{5}) - 5 (- D)) \cdot 5 + 5 D \cdot 5}{5}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

$0 = \frac{- 1 + (- 1 (\frac{6}{5}) - 5 (- D)) \cdot 5 + 5 D \cdot 5}{5}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.5.2.1.3.3

Multiply $- 1$ by $- 5$ .

$0 = \frac{- 1 + (- 1 (\frac{6}{5}) + 5 D) \cdot 5 + 5 D \cdot 5}{5}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.5.2.1.3.4

Rewrite $- 1 (\frac{6}{5})$ as $- (\frac{6}{5})$ .

$0 = \frac{- 1 + (- \frac{6}{5} + 5 D) \cdot 5 + 5 D \cdot 5}{5}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.5.2.1.3.5

Apply the distributive property.

$0 = \frac{- 1 - \frac{6}{5} \cdot 5 + 5 D \cdot 5 + 5 D \cdot 5}{5}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.5.2.1.3.6

Cancel the common factor of $5$ .

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Step 3.5.2.1.3.6.1

Move the leading negative in $- \frac{6}{5}$ into the numerator.

$0 = \frac{- 1 + \frac{- 6}{5} \cdot 5 + 5 D \cdot 5 + 5 D \cdot 5}{5}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.5.2.1.3.6.2

Cancel the common factor.

$0 = \frac{- 1 + \frac{- 6}{5} \cdot 5 + 5 D \cdot 5 + 5 D \cdot 5}{5}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.5.2.1.3.6.3

Rewrite the expression.

$0 = \frac{- 1 - 6 + 5 D \cdot 5 + 5 D \cdot 5}{5}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

$0 = \frac{- 1 - 6 + 5 D \cdot 5 + 5 D \cdot 5}{5}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.5.2.1.3.7

Multiply $5$ by $5$ .

$0 = \frac{- 1 - 6 + 25 D + 5 D \cdot 5}{5}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.5.2.1.3.8

Multiply $5$ by $5$ .

$0 = \frac{- 1 - 6 + 25 D + 25 D}{5}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

$0 = \frac{- 1 - 6 + 25 D + 25 D}{5}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.5.2.1.4

Simplify terms.

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Step 3.5.2.1.4.1

Subtract $6$ from $- 1$ .

$0 = \frac{- 7 + 25 D + 25 D}{5}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.5.2.1.4.2

Add $25 D$ and $25 D$ .

$0 = \frac{- 7 + 50 D}{5}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.5.2.1.4.3

Rewrite $- 7$ as $- 1 (7)$ .

$0 = \frac{- 1 \cdot 7 + 50 D}{5}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.5.2.1.4.4

Factor $- 1$ out of $50 D$ .

$0 = \frac{- 1 \cdot 7 - (- 50 D)}{5}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.5.2.1.4.5

Factor $- 1$ out of $- 1 (7) - (- 50 D)$ .

$0 = \frac{- 1 (7 - 50 D)}{5}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.5.2.1.4.6

Move the negative in front of the fraction.

$0 = - \frac{7 - 50 D}{5}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

$0 = - \frac{7 - 50 D}{5}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

$0 = - \frac{7 - 50 D}{5}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

$0 = - \frac{7 - 50 D}{5}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

$0 = - \frac{7 - 50 D}{5}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.6

Solve for $D$ in $0 = - \frac{7 - 50 D}{5}$ .

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Step 3.6.1

Set the numerator equal to zero.

$7 - 50 D = 0$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.6.2

Solve the equation for $D$ .

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Step 3.6.2.1

Subtract $7$ from both sides of the equation.

$- 50 D = - 7$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.6.2.2

Divide each term in $- 50 D = - 7$ by $- 50$ and simplify.

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Step 3.6.2.2.1

Divide each term in $- 50 D = - 7$ by $- 50$ .

$\frac{- 50 D}{- 50} = \frac{- 7}{- 50}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.6.2.2.2

Simplify the left side.

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Step 3.6.2.2.2.1

Cancel the common factor of $- 50$ .

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Step 3.6.2.2.2.1.1

Cancel the common factor.

$\frac{- 50 D}{- 50} = \frac{- 7}{- 50}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.6.2.2.2.1.2

Divide $D$ by $1$ .

$D = \frac{- 7}{- 50}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

$D = \frac{- 7}{- 50}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

$D = \frac{- 7}{- 50}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.6.2.2.3

Simplify the right side.

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Step 3.6.2.2.3.1

Dividing two negative values results in a positive value.

$D = \frac{7}{50}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

$D = \frac{7}{50}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

$D = \frac{7}{50}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

$D = \frac{7}{50}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

$D = \frac{7}{50}$

$C = \frac{6}{25} - D$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.7

Replace all occurrences of $D$ with $\frac{7}{50}$ in each equation.

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Step 3.7.1

Replace all occurrences of $D$ in $C = \frac{6}{25} - D$ with $\frac{7}{50}$ .

$C = \frac{6}{25} - (\frac{7}{50})$

$D = \frac{7}{50}$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.7.2

Simplify the right side.

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Step 3.7.2.1

Simplify $\frac{6}{25} - (\frac{7}{50})$ .

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Step 3.7.2.1.1

To write $\frac{6}{25}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$C = \frac{6}{25} \cdot \frac{2}{2} - \frac{7}{50}$

$D = \frac{7}{50}$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.7.2.1.2

Write each expression with a common denominator of $50$ , by multiplying each by an appropriate factor of $1$ .

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Step 3.7.2.1.2.1

Multiply $\frac{6}{25}$ by $\frac{2}{2}$ .

$C = \frac{6 \cdot 2}{25 \cdot 2} - \frac{7}{50}$

$D = \frac{7}{50}$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.7.2.1.2.2

Multiply $25$ by $2$ .

$C = \frac{6 \cdot 2}{50} - \frac{7}{50}$

$D = \frac{7}{50}$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

$C = \frac{6 \cdot 2}{50} - \frac{7}{50}$

$D = \frac{7}{50}$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.7.2.1.3

Combine the numerators over the common denominator.

$C = \frac{6 \cdot 2 - 7}{50}$

$D = \frac{7}{50}$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.7.2.1.4

Simplify the numerator.

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Step 3.7.2.1.4.1

Multiply $6$ by $2$ .

$C = \frac{12 - 7}{50}$

$D = \frac{7}{50}$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.7.2.1.4.2

Subtract $7$ from $12$ .

$C = \frac{5}{50}$

$D = \frac{7}{50}$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

$C = \frac{5}{50}$

$D = \frac{7}{50}$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.7.2.1.5

Cancel the common factor of $5$ and $50$ .

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Step 3.7.2.1.5.1

Factor $5$ out of $5$ .

$C = \frac{5 (1)}{50}$

$D = \frac{7}{50}$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.7.2.1.5.2

Cancel the common factors.

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Step 3.7.2.1.5.2.1

Factor $5$ out of $50$ .

$C = \frac{5 \cdot 1}{5 \cdot 10}$

$D = \frac{7}{50}$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.7.2.1.5.2.2

Cancel the common factor.

$C = \frac{5 \cdot 1}{5 \cdot 10}$

$D = \frac{7}{50}$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.7.2.1.5.2.3

Rewrite the expression.

$C = \frac{1}{10}$

$D = \frac{7}{50}$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

$C = \frac{1}{10}$

$D = \frac{7}{50}$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

$C = \frac{1}{10}$

$D = \frac{7}{50}$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

$C = \frac{1}{10}$

$D = \frac{7}{50}$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

$C = \frac{1}{10}$

$D = \frac{7}{50}$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

$C = \frac{1}{10}$

$D = \frac{7}{50}$

$A = - \frac{1}{5}$

$B = - \frac{6}{25}$

Step 3.8

List all of the solutions.

$C = \frac{1}{10}, D = \frac{7}{50}, A = - \frac{1}{5}, B = - \frac{6}{25}$

Step 4

Replace each of the partial fraction coefficients in $\frac{A}{x^{2}} + \frac{B}{x} + \frac{C}{x + 5} + \frac{D}{x - 5}$ with the values found for $A$ , $B$ , $C$ , and $D$ .

$- \frac{\frac{1}{5}}{x^{2}} - \frac{\frac{6}{25}}{x} + \frac{\frac{1}{10}}{x + 5} + \frac{\frac{7}{50}}{x - 5}$