Precalculus Examples

$\frac{x + 6}{x^{3} - 3 x^{2} - 4 x + 12}$

Step 1

Decompose the fraction and multiply through by the common denominator.

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Step 1.1

Factor the fraction.

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Step 1.1.1

Factor out the greatest common factor from each group.

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Step 1.1.1.1

Group the first two terms and the last two terms.

$\frac{x + 6}{(x^{3} - 3 x^{2}) - 4 x + 12}$

Step 1.1.1.2

Factor out the greatest common factor (GCF) from each group.

$\frac{x + 6}{x^{2} (x - 3) - 4 (x - 3)}$

Step 1.1.2

Factor the polynomial by factoring out the greatest common factor, $x - 3$ .

$\frac{x + 6}{(x - 3) (x^{2} - 4)}$

Step 1.1.3

Rewrite $4$ as $2^{2}$ .

$\frac{x + 6}{(x - 3) (x^{2} - 2^{2})}$

Step 1.1.4

Factor.

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Step 1.1.4.1

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x$ and $b = 2$ .

$\frac{x + 6}{(x - 3) ((x + 2) (x - 2))}$

Step 1.1.4.2

Remove unnecessary parentheses.

$\frac{x + 6}{(x - 3) (x + 2) (x - 2)}$

Step 1.2

For each factor in the denominator, create a new fraction using the factor as the denominator, and an unknown value as the numerator. Since the factor in the denominator is linear, put a single variable in its place $A$ .

$\frac{A}{x - 3}$

Step 1.3

$\frac{A}{x - 3} + \frac{B}{x + 2}$

Step 1.4

$\frac{A}{x - 3} + \frac{B}{x + 2} + \frac{C}{x - 2}$

Step 1.5

Multiply each fraction in the equation by the denominator of the original expression. In this case, the denominator is $(x - 3) (x + 2) (x - 2)$ .

$\frac{(x + 6) (x - 3) (x + 2) (x - 2)}{(x - 3) (x + 2) (x - 2)} = \frac{(A) (x - 3) (x + 2) (x - 2)}{x - 3} + \frac{(B) (x - 3) (x + 2) (x - 2)}{x + 2} + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.6

Cancel the common factor of $x - 3$ .

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Step 1.6.1

Cancel the common factor.

$\frac{(x + 6) (x - 3) (x + 2) (x - 2)}{(x - 3) (x + 2) (x - 2)} = \frac{(A) (x - 3) (x + 2) (x - 2)}{x - 3} + \frac{(B) (x - 3) (x + 2) (x - 2)}{x + 2} + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.6.2

Rewrite the expression.

$\frac{((x + 6) (x + 2)) (x - 2)}{(x + 2) (x - 2)} = \frac{(A) (x - 3) (x + 2) (x - 2)}{x - 3} + \frac{(B) (x - 3) (x + 2) (x - 2)}{x + 2} + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.7

Cancel the common factor of $x + 2$ .

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Step 1.7.1

Cancel the common factor.

$\frac{(x + 6) (x + 2) (x - 2)}{(x + 2) (x - 2)} = \frac{(A) (x - 3) (x + 2) (x - 2)}{x - 3} + \frac{(B) (x - 3) (x + 2) (x - 2)}{x + 2} + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.7.2

Rewrite the expression.

$\frac{(x + 6) (x - 2)}{x - 2} = \frac{(A) (x - 3) (x + 2) (x - 2)}{x - 3} + \frac{(B) (x - 3) (x + 2) (x - 2)}{x + 2} + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.8

Cancel the common factor of $x - 2$ .

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Step 1.8.1

Cancel the common factor.

$\frac{(x + 6) (x - 2)}{x - 2} = \frac{(A) (x - 3) (x + 2) (x - 2)}{x - 3} + \frac{(B) (x - 3) (x + 2) (x - 2)}{x + 2} + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.8.2

Divide $x + 6$ by $1$ .

$x + 6 = \frac{(A) (x - 3) (x + 2) (x - 2)}{x - 3} + \frac{(B) (x - 3) (x + 2) (x - 2)}{x + 2} + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.9

Simplify each term.

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Step 1.9.1

Cancel the common factor of $x - 3$ .

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Step 1.9.1.1

Cancel the common factor.

$x + 6 = \frac{A (x - 3) (x + 2) (x - 2)}{x - 3} + \frac{(B) (x - 3) (x + 2) (x - 2)}{x + 2} + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.9.1.2

Divide $((A) (x + 2)) (x - 2)$ by $1$ .

$x + 6 = ((A) (x + 2)) (x - 2) + \frac{(B) (x - 3) (x + 2) (x - 2)}{x + 2} + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.9.2

Apply the distributive property.

$x + 6 = (A x + A \cdot 2) (x - 2) + \frac{(B) (x - 3) (x + 2) (x - 2)}{x + 2} + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.9.3

Move $2$ to the left of $A$ .

$x + 6 = (A x + 2 \cdot A) (x - 2) + \frac{(B) (x - 3) (x + 2) (x - 2)}{x + 2} + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.9.4

Expand $(A x + 2 A) (x - 2)$ using the FOIL Method.

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Step 1.9.4.1

Apply the distributive property.

$x + 6 = A x (x - 2) + 2 A (x - 2) + \frac{(B) (x - 3) (x + 2) (x - 2)}{x + 2} + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.9.4.2

Apply the distributive property.

$x + 6 = A x \cdot x + A x \cdot - 2 + 2 A (x - 2) + \frac{(B) (x - 3) (x + 2) (x - 2)}{x + 2} + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.9.4.3

Apply the distributive property.

$x + 6 = A x \cdot x + A x \cdot - 2 + 2 A x + 2 A \cdot - 2 + \frac{(B) (x - 3) (x + 2) (x - 2)}{x + 2} + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.9.5

Combine the opposite terms in $A x \cdot x + A x \cdot - 2 + 2 A x + 2 A \cdot - 2$ .

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Step 1.9.5.1

Reorder the factors in the terms $A x \cdot - 2$ and $2 A x$ .

$x + 6 = A x \cdot x - 2 A x + 2 A x + 2 A \cdot - 2 + \frac{(B) (x - 3) (x + 2) (x - 2)}{x + 2} + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.9.5.2

Add $- 2 A x$ and $2 A x$ .

$x + 6 = A x \cdot x + 0 + 2 A \cdot - 2 + \frac{(B) (x - 3) (x + 2) (x - 2)}{x + 2} + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.9.5.3

Add $A x \cdot x$ and $0$ .

$x + 6 = A x \cdot x + 2 A \cdot - 2 + \frac{(B) (x - 3) (x + 2) (x - 2)}{x + 2} + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.9.6

Simplify each term.

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Step 1.9.6.1

Multiply $x$ by $x$ by adding the exponents.

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Step 1.9.6.1.1

Move $x$ .

$x + 6 = A (x \cdot x) + 2 A \cdot - 2 + \frac{(B) (x - 3) (x + 2) (x - 2)}{x + 2} + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.9.6.1.2

Multiply $x$ by $x$ .

$x + 6 = A x^{2} + 2 A \cdot - 2 + \frac{(B) (x - 3) (x + 2) (x - 2)}{x + 2} + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.9.6.2

Multiply $- 2$ by $2$ .

$x + 6 = A x^{2} - 4 A + \frac{(B) (x - 3) (x + 2) (x - 2)}{x + 2} + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.9.7

Cancel the common factor of $x + 2$ .

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Step 1.9.7.1

Cancel the common factor.

$x + 6 = A x^{2} - 4 A + \frac{(B) (x - 3) (x + 2) (x - 2)}{x + 2} + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.9.7.2

Divide $(B) (x - 3) (x - 2)$ by $1$ .

$x + 6 = A x^{2} - 4 A + (B) (x - 3) (x - 2) + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.9.8

Apply the distributive property.

$x + 6 = A x^{2} - 4 A + (B x + B \cdot - 3) (x - 2) + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.9.9

Move $- 3$ to the left of $B$ .

$x + 6 = A x^{2} - 4 A + (B x - 3 \cdot B) (x - 2) + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.9.10

Expand $(B x - 3 B) (x - 2)$ using the FOIL Method.

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Step 1.9.10.1

Apply the distributive property.

$x + 6 = A x^{2} - 4 A + B x (x - 2) - 3 B (x - 2) + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.9.10.2

Apply the distributive property.

$x + 6 = A x^{2} - 4 A + B x \cdot x + B x \cdot - 2 - 3 B (x - 2) + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.9.10.3

Apply the distributive property.

$x + 6 = A x^{2} - 4 A + B x \cdot x + B x \cdot - 2 - 3 B x - 3 B \cdot - 2 + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.9.11

Simplify and combine like terms.

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Step 1.9.11.1

Simplify each term.

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Step 1.9.11.1.1

Multiply $x$ by $x$ by adding the exponents.

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Step 1.9.11.1.1.1

Move $x$ .

$x + 6 = A x^{2} - 4 A + B (x \cdot x) + B x \cdot - 2 - 3 B x - 3 B \cdot - 2 + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.9.11.1.1.2

Multiply $x$ by $x$ .

$x + 6 = A x^{2} - 4 A + B x^{2} + B x \cdot - 2 - 3 B x - 3 B \cdot - 2 + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.9.11.1.2

Move $- 2$ to the left of $B x$ .

$x + 6 = A x^{2} - 4 A + B x^{2} - 2 \cdot (B x) - 3 B x - 3 B \cdot - 2 + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.9.11.1.3

Multiply $- 2$ by $- 3$ .

$x + 6 = A x^{2} - 4 A + B x^{2} - 2 B x - 3 B x + 6 B + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.9.11.2

Subtract $3 B x$ from $- 2 B x$ .

$x + 6 = A x^{2} - 4 A + B x^{2} - 5 B x + 6 B + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.9.12

Cancel the common factor of $x - 2$ .

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Step 1.9.12.1

Cancel the common factor.

$x + 6 = A x^{2} - 4 A + B x^{2} - 5 B x + 6 B + \frac{(C) (x - 3) (x + 2) (x - 2)}{x - 2}$

Step 1.9.12.2

Divide $(C) (x - 3) (x + 2)$ by $1$ .

$x + 6 = A x^{2} - 4 A + B x^{2} - 5 B x + 6 B + (C) (x - 3) (x + 2)$

Step 1.9.13

Apply the distributive property.

$x + 6 = A x^{2} - 4 A + B x^{2} - 5 B x + 6 B + (C x + C \cdot - 3) (x + 2)$

Step 1.9.14

Move $- 3$ to the left of $C$ .

$x + 6 = A x^{2} - 4 A + B x^{2} - 5 B x + 6 B + (C x - 3 \cdot C) (x + 2)$

Step 1.9.15

Expand $(C x - 3 C) (x + 2)$ using the FOIL Method.

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Step 1.9.15.1

Apply the distributive property.

$x + 6 = A x^{2} - 4 A + B x^{2} - 5 B x + 6 B + C x (x + 2) - 3 C (x + 2)$

Step 1.9.15.2

Apply the distributive property.

$x + 6 = A x^{2} - 4 A + B x^{2} - 5 B x + 6 B + C x \cdot x + C x \cdot 2 - 3 C (x + 2)$

Step 1.9.15.3

Apply the distributive property.

$x + 6 = A x^{2} - 4 A + B x^{2} - 5 B x + 6 B + C x \cdot x + C x \cdot 2 - 3 C x - 3 C \cdot 2$

Step 1.9.16

Simplify and combine like terms.

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Step 1.9.16.1

Simplify each term.

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Step 1.9.16.1.1

Multiply $x$ by $x$ by adding the exponents.

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Step 1.9.16.1.1.1

Move $x$ .

$x + 6 = A x^{2} - 4 A + B x^{2} - 5 B x + 6 B + C (x \cdot x) + C x \cdot 2 - 3 C x - 3 C \cdot 2$

Step 1.9.16.1.1.2

Multiply $x$ by $x$ .

$x + 6 = A x^{2} - 4 A + B x^{2} - 5 B x + 6 B + C x^{2} + C x \cdot 2 - 3 C x - 3 C \cdot 2$

Step 1.9.16.1.2

Move $2$ to the left of $C x$ .

$x + 6 = A x^{2} - 4 A + B x^{2} - 5 B x + 6 B + C x^{2} + 2 \cdot (C x) - 3 C x - 3 C \cdot 2$

Step 1.9.16.1.3

Multiply $2$ by $- 3$ .

$x + 6 = A x^{2} - 4 A + B x^{2} - 5 B x + 6 B + C x^{2} + 2 C x - 3 C x - 6 C$

Step 1.9.16.2

Subtract $3 C x$ from $2 C x$ .

$x + 6 = A x^{2} - 4 A + B x^{2} - 5 B x + 6 B + C x^{2} - C x - 6 C$

Step 1.10

Simplify the expression.

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Step 1.10.1

Move $B$ .

$x + 6 = A x^{2} - 4 A + B x^{2} - 5 x B + 6 B + C x^{2} - C x - 6 C$

Step 1.10.2

Move $6 B$ .

$x + 6 = A x^{2} - 4 A + B x^{2} - 5 x B + C x^{2} - C x + 6 B - 6 C$

Step 1.10.3

Move $- 4 A$ .

$x + 6 = A x^{2} + B x^{2} - 5 x B + C x^{2} - C x - 4 A + 6 B - 6 C$

Step 1.10.4

Move $- 5 x B$ .

$x + 6 = A x^{2} + B x^{2} + C x^{2} - 5 x B - C x - 4 A + 6 B - 6 C$

Step 2

Create equations for the partial fraction variables and use them to set up a system of equations.

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Step 2.1

Create an equation for the partial fraction variables by equating the coefficients of $x^{2}$ from each side of the equation. For the equation to be equal, the equivalent coefficients on each side of the equation must be equal.

$0 = A + B + C$

Step 2.2

Create an equation for the partial fraction variables by equating the coefficients of $x$ from each side of the equation. For the equation to be equal, the equivalent coefficients on each side of the equation must be equal.

$1 = - 5 B - 1 C$

Step 2.3

Create an equation for the partial fraction variables by equating the coefficients of the terms not containing $x$ . For the equation to be equal, the equivalent coefficients on each side of the equation must be equal.

$6 = - 4 A + 6 B - 6 C$

Step 2.4

Set up the system of equations to find the coefficients of the partial fractions.

$0 = A + B + C$

$1 = - 5 B - 1 C$

$6 = - 4 A + 6 B - 6 C$

$0 = A + B + C$

$1 = - 5 B - 1 C$

$6 = - 4 A + 6 B - 6 C$

Step 3

Solve the system of equations.

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Step 3.1

Solve for $A$ in $0 = A + B + C$ .

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Step 3.1.1

Rewrite the equation as $A + B + C = 0$ .

$A + B + C = 0$

$1 = - 5 B - 1 C$

$6 = - 4 A + 6 B - 6 C$

Step 3.1.2

Move all terms not containing $A$ to the right side of the equation.

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Step 3.1.2.1

Subtract $B$ from both sides of the equation.

$A + C = - B$

$1 = - 5 B - 1 C$

$6 = - 4 A + 6 B - 6 C$

Step 3.1.2.2

Subtract $C$ from both sides of the equation.

$A = - B - C$

$1 = - 5 B - 1 C$

$6 = - 4 A + 6 B - 6 C$

$A = - B - C$

$1 = - 5 B - 1 C$

$6 = - 4 A + 6 B - 6 C$

$A = - B - C$

$1 = - 5 B - 1 C$

$6 = - 4 A + 6 B - 6 C$

Step 3.2

Replace all occurrences of $A$ with $- B - C$ in each equation.

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Step 3.2.1

Replace all occurrences of $A$ in $6 = - 4 A + 6 B - 6 C$ with $- B - C$ .

$6 = - 4 (- B - C) + 6 B - 6 C$

$A = - B - C$

$1 = - 5 B - 1 C$

Step 3.2.2

Simplify the right side.

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Step 3.2.2.1

Simplify $- 4 (- B - C) + 6 B - 6 C$ .

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Step 3.2.2.1.1

Simplify each term.

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Step 3.2.2.1.1.1

Apply the distributive property.

$6 = - 4 (- B) - 4 (- C) + 6 B - 6 C$

$A = - B - C$

$1 = - 5 B - 1 C$

Step 3.2.2.1.1.2

Multiply $- 1$ by $- 4$ .

$6 = 4 B - 4 (- C) + 6 B - 6 C$

$A = - B - C$

$1 = - 5 B - 1 C$

Step 3.2.2.1.1.3

Multiply $- 1$ by $- 4$ .

$6 = 4 B + 4 C + 6 B - 6 C$

$A = - B - C$

$1 = - 5 B - 1 C$

$6 = 4 B + 4 C + 6 B - 6 C$

$A = - B - C$

$1 = - 5 B - 1 C$

Step 3.2.2.1.2

Simplify by adding terms.

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Step 3.2.2.1.2.1

Add $4 B$ and $6 B$ .

$6 = 10 B + 4 C - 6 C$

$A = - B - C$

$1 = - 5 B - 1 C$

Step 3.2.2.1.2.2

Subtract $6 C$ from $4 C$ .

$6 = 10 B - 2 C$

$A = - B - C$

$1 = - 5 B - 1 C$

$6 = 10 B - 2 C$

$A = - B - C$

$1 = - 5 B - 1 C$

$6 = 10 B - 2 C$

$A = - B - C$

$1 = - 5 B - 1 C$

$6 = 10 B - 2 C$

$A = - B - C$

$1 = - 5 B - 1 C$

$6 = 10 B - 2 C$

$A = - B - C$

$1 = - 5 B - 1 C$

Step 3.3

Solve for $B$ in $6 = 10 B - 2 C$ .

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Step 3.3.1

Rewrite the equation as $10 B - 2 C = 6$ .

$10 B - 2 C = 6$

$A = - B - C$

$1 = - 5 B - 1 C$

Step 3.3.2

Add $2 C$ to both sides of the equation.

$10 B = 6 + 2 C$

$A = - B - C$

$1 = - 5 B - 1 C$

Step 3.3.3

Divide each term in $10 B = 6 + 2 C$ by $10$ and simplify.

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Step 3.3.3.1

Divide each term in $10 B = 6 + 2 C$ by $10$ .

$\frac{10 B}{10} = \frac{6}{10} + \frac{2 C}{10}$

$A = - B - C$

$1 = - 5 B - 1 C$

Step 3.3.3.2

Simplify the left side.

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Step 3.3.3.2.1

Cancel the common factor of $10$ .

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Step 3.3.3.2.1.1

Cancel the common factor.

$\frac{10 B}{10} = \frac{6}{10} + \frac{2 C}{10}$

$A = - B - C$

$1 = - 5 B - 1 C$

Step 3.3.3.2.1.2

Divide $B$ by $1$ .

$B = \frac{6}{10} + \frac{2 C}{10}$

$A = - B - C$

$1 = - 5 B - 1 C$

$B = \frac{6}{10} + \frac{2 C}{10}$

$A = - B - C$

$1 = - 5 B - 1 C$

$B = \frac{6}{10} + \frac{2 C}{10}$

$A = - B - C$

$1 = - 5 B - 1 C$

Step 3.3.3.3

Simplify the right side.

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Step 3.3.3.3.1

Simplify each term.

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Step 3.3.3.3.1.1

Cancel the common factor of $6$ and $10$ .

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Step 3.3.3.3.1.1.1

Factor $2$ out of $6$ .

$B = \frac{2 (3)}{10} + \frac{2 C}{10}$

$A = - B - C$

$1 = - 5 B - 1 C$

Step 3.3.3.3.1.1.2

Cancel the common factors.

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Step 3.3.3.3.1.1.2.1

Factor $2$ out of $10$ .

$B = \frac{2 \cdot 3}{2 \cdot 5} + \frac{2 C}{10}$

$A = - B - C$

$1 = - 5 B - 1 C$

Step 3.3.3.3.1.1.2.2

Cancel the common factor.

$B = \frac{2 \cdot 3}{2 \cdot 5} + \frac{2 C}{10}$

$A = - B - C$

$1 = - 5 B - 1 C$

Step 3.3.3.3.1.1.2.3

Rewrite the expression.

$B = \frac{3}{5} + \frac{2 C}{10}$

$A = - B - C$

$1 = - 5 B - 1 C$

$B = \frac{3}{5} + \frac{2 C}{10}$

$A = - B - C$

$1 = - 5 B - 1 C$

$B = \frac{3}{5} + \frac{2 C}{10}$

$A = - B - C$

$1 = - 5 B - 1 C$

Step 3.3.3.3.1.2

Cancel the common factor of $2$ and $10$ .

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Step 3.3.3.3.1.2.1

Factor $2$ out of $2 C$ .

$B = \frac{3}{5} + \frac{2 (C)}{10}$

$A = - B - C$

$1 = - 5 B - 1 C$

Step 3.3.3.3.1.2.2

Cancel the common factors.

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Step 3.3.3.3.1.2.2.1

Factor $2$ out of $10$ .

$B = \frac{3}{5} + \frac{2 C}{2 \cdot 5}$

$A = - B - C$

$1 = - 5 B - 1 C$

Step 3.3.3.3.1.2.2.2

Cancel the common factor.

$B = \frac{3}{5} + \frac{2 C}{2 \cdot 5}$

$A = - B - C$

$1 = - 5 B - 1 C$

Step 3.3.3.3.1.2.2.3

Rewrite the expression.

$B = \frac{3}{5} + \frac{C}{5}$

$A = - B - C$

$1 = - 5 B - 1 C$

$B = \frac{3}{5} + \frac{C}{5}$

$A = - B - C$

$1 = - 5 B - 1 C$

$B = \frac{3}{5} + \frac{C}{5}$

$A = - B - C$

$1 = - 5 B - 1 C$

$B = \frac{3}{5} + \frac{C}{5}$

$A = - B - C$

$1 = - 5 B - 1 C$

$B = \frac{3}{5} + \frac{C}{5}$

$A = - B - C$

$1 = - 5 B - 1 C$

$B = \frac{3}{5} + \frac{C}{5}$

$A = - B - C$

$1 = - 5 B - 1 C$

$B = \frac{3}{5} + \frac{C}{5}$

$A = - B - C$

$1 = - 5 B - 1 C$

Step 3.4

Replace all occurrences of $B$ with $\frac{3}{5} + \frac{C}{5}$ in each equation.

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Step 3.4.1

Replace all occurrences of $B$ in $A = - B - C$ with $\frac{3}{5} + \frac{C}{5}$ .

$A = - (\frac{3}{5} + \frac{C}{5}) - C$

$B = \frac{3}{5} + \frac{C}{5}$

$1 = - 5 B - 1 C$

Step 3.4.2

Simplify the right side.

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Step 3.4.2.1

Simplify $- (\frac{3}{5} + \frac{C}{5}) - C$ .

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Step 3.4.2.1.1

Apply the distributive property.

$A = - \frac{3}{5} - \frac{C}{5} - C$

$B = \frac{3}{5} + \frac{C}{5}$

$1 = - 5 B - 1 C$

Step 3.4.2.1.2

To write $- C$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$A = - \frac{3}{5} - \frac{C}{5} - C \cdot \frac{5}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

$1 = - 5 B - 1 C$

Step 3.4.2.1.3

Combine $- C$ and $\frac{5}{5}$ .

$A = - \frac{3}{5} - \frac{C}{5} + \frac{- C \cdot 5}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

$1 = - 5 B - 1 C$

Step 3.4.2.1.4

Combine the numerators over the common denominator.

$A = - \frac{3}{5} + \frac{- C - C \cdot 5}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

$1 = - 5 B - 1 C$

Step 3.4.2.1.5

Combine the numerators over the common denominator.

$A = \frac{- 3 - C - C \cdot 5}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

$1 = - 5 B - 1 C$

Step 3.4.2.1.6

Multiply $5$ by $- 1$ .

$A = \frac{- 3 - C - 5 C}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

$1 = - 5 B - 1 C$

Step 3.4.2.1.7

Subtract $5 C$ from $- C$ .

$A = \frac{- 3 - 6 C}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

$1 = - 5 B - 1 C$

Step 3.4.2.1.8

Factor $3$ out of $- 3 - 6 C$ .

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Step 3.4.2.1.8.1

Factor $3$ out of $- 3$ .

$A = \frac{3 (- 1) - 6 C}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

$1 = - 5 B - 1 C$

Step 3.4.2.1.8.2

Factor $3$ out of $- 6 C$ .

$A = \frac{3 (- 1) + 3 (- 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

$1 = - 5 B - 1 C$

Step 3.4.2.1.8.3

Factor $3$ out of $3 (- 1) + 3 (- 2 C)$ .

$A = \frac{3 (- 1 - 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

$1 = - 5 B - 1 C$

$A = \frac{3 (- 1 - 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

$1 = - 5 B - 1 C$

Step 3.4.2.1.9

Rewrite $- 1$ as $- 1 (1)$ .

$A = \frac{3 (- 1 \cdot 1 - 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

$1 = - 5 B - 1 C$

Step 3.4.2.1.10

Factor $- 1$ out of $- 2 C$ .

$A = \frac{3 (- 1 \cdot 1 - (2 C))}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

$1 = - 5 B - 1 C$

Step 3.4.2.1.11

Factor $- 1$ out of $- 1 (1) - (2 C)$ .

$A = \frac{3 (- 1 (1 + 2 C))}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

$1 = - 5 B - 1 C$

Step 3.4.2.1.12

Move the negative in front of the fraction.

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

$1 = - 5 B - 1 C$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

$1 = - 5 B - 1 C$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

$1 = - 5 B - 1 C$

Step 3.4.3

Replace all occurrences of $B$ in $1 = - 5 B - 1 C$ with $\frac{3}{5} + \frac{C}{5}$ .

$1 = - 5 (\frac{3}{5} + \frac{C}{5}) - 1 C$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

Step 3.4.4

Simplify the right side.

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Step 3.4.4.1

Simplify $- 5 (\frac{3}{5} + \frac{C}{5}) - 1 C$ .

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Step 3.4.4.1.1

Simplify each term.

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Step 3.4.4.1.1.1

Apply the distributive property.

$1 = - 5 (\frac{3}{5}) - 5 \frac{C}{5} - 1 C$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

Step 3.4.4.1.1.2

Cancel the common factor of $5$ .

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Step 3.4.4.1.1.2.1

Factor $5$ out of $- 5$ .

$1 = 5 (- 1) (\frac{3}{5}) - 5 \frac{C}{5} - 1 C$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

Step 3.4.4.1.1.2.2

Cancel the common factor.

$1 = 5 \cdot (- 1 (\frac{3}{5})) - 5 \frac{C}{5} - 1 C$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

Step 3.4.4.1.1.2.3

Rewrite the expression.

$1 = - 1 \cdot 3 - 5 \frac{C}{5} - 1 C$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

$1 = - 1 \cdot 3 - 5 \frac{C}{5} - 1 C$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

Step 3.4.4.1.1.3

Multiply $- 1$ by $3$ .

$1 = - 3 - 5 \frac{C}{5} - 1 C$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

Step 3.4.4.1.1.4

Cancel the common factor of $5$ .

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Step 3.4.4.1.1.4.1

Factor $5$ out of $- 5$ .

$1 = - 3 + 5 (- 1) (\frac{C}{5}) - 1 C$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

Step 3.4.4.1.1.4.2

Cancel the common factor.

$1 = - 3 + 5 \cdot (- 1 \frac{C}{5}) - 1 C$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

Step 3.4.4.1.1.4.3

Rewrite the expression.

$1 = - 3 - 1 C - 1 C$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

$1 = - 3 - 1 C - 1 C$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

Step 3.4.4.1.1.5

Rewrite $- 1 C$ as $- C$ .

$1 = - 3 - C - 1 C$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

Step 3.4.4.1.1.6

Rewrite $- 1 C$ as $- C$ .

$1 = - 3 - C - C$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

$1 = - 3 - C - C$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

Step 3.4.4.1.2

Subtract $C$ from $- C$ .

$1 = - 3 - 2 C$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

$1 = - 3 - 2 C$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

$1 = - 3 - 2 C$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

$1 = - 3 - 2 C$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

Step 3.5

Solve for $C$ in $1 = - 3 - 2 C$ .

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Step 3.5.1

Rewrite the equation as $- 3 - 2 C = 1$ .

$- 3 - 2 C = 1$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

Step 3.5.2

Move all terms not containing $C$ to the right side of the equation.

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Step 3.5.2.1

Add $3$ to both sides of the equation.

$- 2 C = 1 + 3$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

Step 3.5.2.2

Add $1$ and $3$ .

$- 2 C = 4$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

$- 2 C = 4$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

Step 3.5.3

Divide each term in $- 2 C = 4$ by $- 2$ and simplify.

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Step 3.5.3.1

Divide each term in $- 2 C = 4$ by $- 2$ .

$\frac{- 2 C}{- 2} = \frac{4}{- 2}$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

Step 3.5.3.2

Simplify the left side.

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Step 3.5.3.2.1

Cancel the common factor of $- 2$ .

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Step 3.5.3.2.1.1

Cancel the common factor.

$\frac{- 2 C}{- 2} = \frac{4}{- 2}$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

Step 3.5.3.2.1.2

Divide $C$ by $1$ .

$C = \frac{4}{- 2}$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

$C = \frac{4}{- 2}$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

$C = \frac{4}{- 2}$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

Step 3.5.3.3

Simplify the right side.

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Step 3.5.3.3.1

Divide $4$ by $- 2$ .

$C = - 2$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

$C = - 2$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

$C = - 2$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

$C = - 2$

$A = - \frac{3 (1 + 2 C)}{5}$

$B = \frac{3}{5} + \frac{C}{5}$

Step 3.6

Replace all occurrences of $C$ with $- 2$ in each equation.

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Step 3.6.1

Replace all occurrences of $C$ in $A = - \frac{3 (1 + 2 C)}{5}$ with $- 2$ .

$A = - \frac{3 (1 + 2 (- 2))}{5}$

$C = - 2$

$B = \frac{3}{5} + \frac{C}{5}$

Step 3.6.2

Simplify the right side.

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Step 3.6.2.1

Simplify $- \frac{3 (1 + 2 (- 2))}{5}$ .

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Step 3.6.2.1.1

Simplify the numerator.

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Step 3.6.2.1.1.1

Multiply $2$ by $- 2$ .

$A = - \frac{3 (1 - 4)}{5}$

$C = - 2$

$B = \frac{3}{5} + \frac{C}{5}$

Step 3.6.2.1.1.2

Subtract $4$ from $1$ .

$A = - \frac{3 \cdot - 3}{5}$

$C = - 2$

$B = \frac{3}{5} + \frac{C}{5}$

$A = - \frac{3 \cdot - 3}{5}$

$C = - 2$

$B = \frac{3}{5} + \frac{C}{5}$

Step 3.6.2.1.2

Simplify the expression.

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Step 3.6.2.1.2.1

Multiply $3$ by $- 3$ .

$A = - \frac{- 9}{5}$

$C = - 2$

$B = \frac{3}{5} + \frac{C}{5}$

Step 3.6.2.1.2.2

Move the negative in front of the fraction.

$A = \frac{9}{5}$

$C = - 2$

$B = \frac{3}{5} + \frac{C}{5}$

$A = \frac{9}{5}$

$C = - 2$

$B = \frac{3}{5} + \frac{C}{5}$

Step 3.6.2.1.3

Multiply $- - \frac{9}{5}$ .

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Step 3.6.2.1.3.1

Multiply $- 1$ by $- 1$ .

$A = 1 (\frac{9}{5})$

$C = - 2$

$B = \frac{3}{5} + \frac{C}{5}$

Step 3.6.2.1.3.2

Multiply $\frac{9}{5}$ by $1$ .

$A = \frac{9}{5}$

$C = - 2$

$B = \frac{3}{5} + \frac{C}{5}$

$A = \frac{9}{5}$

$C = - 2$

$B = \frac{3}{5} + \frac{C}{5}$

$A = \frac{9}{5}$

$C = - 2$

$B = \frac{3}{5} + \frac{C}{5}$

$A = \frac{9}{5}$

$C = - 2$

$B = \frac{3}{5} + \frac{C}{5}$

Step 3.6.3

Replace all occurrences of $C$ in $B = \frac{3}{5} + \frac{C}{5}$ with $- 2$ .

$B = \frac{3}{5} + \frac{- 2}{5}$

$A = \frac{9}{5}$

$C = - 2$

Step 3.6.4

Simplify the right side.

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Step 3.6.4.1

Simplify $\frac{3}{5} + \frac{- 2}{5}$ .

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Step 3.6.4.1.1

Combine the numerators over the common denominator.

$B = \frac{3 - 2}{5}$

$A = \frac{9}{5}$

$C = - 2$

Step 3.6.4.1.2

Subtract $2$ from $3$ .

$B = \frac{1}{5}$

$A = \frac{9}{5}$

$C = - 2$

$B = \frac{1}{5}$

$A = \frac{9}{5}$

$C = - 2$

$B = \frac{1}{5}$

$A = \frac{9}{5}$

$C = - 2$

$B = \frac{1}{5}$

$A = \frac{9}{5}$

$C = - 2$

Step 3.7

List all of the solutions.

$B = \frac{1}{5}, A = \frac{9}{5}, C = - 2$

Step 4

Replace each of the partial fraction coefficients in $\frac{A}{x - 3} + \frac{B}{x + 2} + \frac{C}{x - 2}$ with the values found for $A$ , $B$ , and $C$ .

$\frac{\frac{9}{5}}{x - 3} + \frac{\frac{1}{5}}{x + 2} + \frac{- 2}{x - 2}$