Precalculus Examples

$\frac{\sqrt[3]{6} {(2)}^{\frac{1}{4}} {(3)}^{\frac{1}{6}}}{{(6 \sqrt[4]{8} \sqrt{3})}^{\frac{1}{3}}}$

Step 1

Multiply $6 \sqrt[4]{8} \sqrt{3}$ .

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Step 1.1

Rewrite the expression using the least common index of $4$ .

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Step 1.1.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{3}$ as $3^{\frac{1}{2}}$ .

$\frac{\sqrt[3]{6} \cdot 2^{\frac{1}{4}} \cdot 3^{\frac{1}{6}}}{{(6 (3^{\frac{1}{2}} \sqrt[4]{8}))}^{\frac{1}{3}}}$

Step 1.1.2

Rewrite $3^{\frac{1}{2}}$ as $3^{\frac{2}{4}}$ .

$\frac{\sqrt[3]{6} \cdot 2^{\frac{1}{4}} \cdot 3^{\frac{1}{6}}}{{(6 (3^{\frac{2}{4}} \sqrt[4]{8}))}^{\frac{1}{3}}}$

Step 1.1.3

Rewrite $3^{\frac{2}{4}}$ as $\sqrt[4]{3^{2}}$ .

$\frac{\sqrt[3]{6} \cdot 2^{\frac{1}{4}} \cdot 3^{\frac{1}{6}}}{{(6 (\sqrt[4]{3^{2}} \sqrt[4]{8}))}^{\frac{1}{3}}}$

Step 1.2

Combine using the product rule for radicals.

$\frac{\sqrt[3]{6} \cdot 2^{\frac{1}{4}} \cdot 3^{\frac{1}{6}}}{{(6 \sqrt[4]{3^{2} \cdot 8})}^{\frac{1}{3}}}$

Step 1.3

Raise $3$ to the power of $2$ .

$\frac{\sqrt[3]{6} \cdot 2^{\frac{1}{4}} \cdot 3^{\frac{1}{6}}}{{(6 \sqrt[4]{9 \cdot 8})}^{\frac{1}{3}}}$

Step 1.4

Multiply $9$ by $8$ .

$\frac{\sqrt[3]{6} \cdot 2^{\frac{1}{4}} \cdot 3^{\frac{1}{6}}}{{(6 \sqrt[4]{72})}^{\frac{1}{3}}}$

Step 2

Apply the product rule to $6 \sqrt[4]{72}$ .

$\frac{\sqrt[3]{6} \cdot 2^{\frac{1}{4}} \cdot 3^{\frac{1}{6}}}{6^{\frac{1}{3}} {\sqrt[4]{72}}^{\frac{1}{3}}}$

Step 3

The result can be shown in multiple forms.

Exact Form:

$\frac{\sqrt[3]{6} \cdot 2^{\frac{1}{4}} \cdot 3^{\frac{1}{6}}}{6^{\frac{1}{3}} {\sqrt[4]{72}}^{\frac{1}{3}}}$

Decimal Form:

$1$