Precalculus Examples

$2 x^{2} + 4 x - 6 = 0$

Step 1

Add $6$ to both sides of the equation.

$2 x^{2} + 4 x = 6$

Step 2

Divide each term in $2 x^{2} + 4 x = 6$ by $2$ and simplify.

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Step 2.1

Divide each term in $2 x^{2} + 4 x = 6$ by $2$ .

$\frac{2 x^{2}}{2} + \frac{4 x}{2} = \frac{6}{2}$

Step 2.2

Simplify the left side.

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Step 2.2.1

Simplify each term.

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Step 2.2.1.1

Cancel the common factor of $2$ .

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Step 2.2.1.1.1

Cancel the common factor.

$\frac{2 x^{2}}{2} + \frac{4 x}{2} = \frac{6}{2}$

Step 2.2.1.1.2

Divide $x^{2}$ by $1$ .

$x^{2} + \frac{4 x}{2} = \frac{6}{2}$

Step 2.2.1.2

Cancel the common factor of $4$ and $2$ .

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Step 2.2.1.2.1

Factor $2$ out of $4 x$ .

$x^{2} + \frac{2 (2 x)}{2} = \frac{6}{2}$

Step 2.2.1.2.2

Cancel the common factors.

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Step 2.2.1.2.2.1

Factor $2$ out of $2$ .

$x^{2} + \frac{2 (2 x)}{2 (1)} = \frac{6}{2}$

Step 2.2.1.2.2.2

Cancel the common factor.

$x^{2} + \frac{2 (2 x)}{2 \cdot 1} = \frac{6}{2}$

Step 2.2.1.2.2.3

Rewrite the expression.

$x^{2} + \frac{2 x}{1} = \frac{6}{2}$

Step 2.2.1.2.2.4

Divide $2 x$ by $1$ .

$x^{2} + 2 x = \frac{6}{2}$

Step 2.3

Simplify the right side.

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Step 2.3.1

Divide $6$ by $2$ .

$x^{2} + 2 x = 3$

Step 3

To create a trinomial square on the left side of the equation, find a value that is equal to the square of half of $b$ .

${(\frac{b}{2})}^{2} = {(1)}^{2}$

Step 4

Add the term to each side of the equation.

$x^{2} + 2 x + {(1)}^{2} = 3 + {(1)}^{2}$

Step 5

Simplify the equation.

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Step 5.1

Simplify the left side.

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Step 5.1.1

One to any power is one.

$x^{2} + 2 x + 1 = 3 + {(1)}^{2}$

Step 5.2

Simplify the right side.

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Step 5.2.1

Simplify $3 + {(1)}^{2}$ .

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Step 5.2.1.1

One to any power is one.

$x^{2} + 2 x + 1 = 3 + 1$

Step 5.2.1.2

Add $3$ and $1$ .

$x^{2} + 2 x + 1 = 4$

Step 6

Factor the perfect trinomial square into ${(x + 1)}^{2}$ .

${(x + 1)}^{2} = 4$

Step 7

Solve the equation for $x$ .

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Step 7.1

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x + 1 = \pm \sqrt{4}$

Step 7.2

Simplify $\pm \sqrt{4}$ .

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Step 7.2.1

Rewrite $4$ as $2^{2}$ .

$x + 1 = \pm \sqrt{2^{2}}$

Step 7.2.2

Pull terms out from under the radical, assuming positive real numbers.

$x + 1 = \pm 2$

Step 7.3

The complete solution is the result of both the positive and negative portions of the solution.

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Step 7.3.1

First, use the positive value of the $\pm$ to find the first solution.

$x + 1 = 2$

Step 7.3.2

Move all terms not containing $x$ to the right side of the equation.

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Step 7.3.2.1

Subtract $1$ from both sides of the equation.

$x = 2 - 1$

Step 7.3.2.2

Subtract $1$ from $2$ .

$x = 1$

Step 7.3.3

Next, use the negative value of the $\pm$ to find the second solution.

$x + 1 = - 2$

Step 7.3.4

Move all terms not containing $x$ to the right side of the equation.

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Step 7.3.4.1

Subtract $1$ from both sides of the equation.

$x = - 2 - 1$

Step 7.3.4.2

Subtract $1$ from $- 2$ .

$x = - 3$

Step 7.3.5

The complete solution is the result of both the positive and negative portions of the solution.

$x = 1, - 3$