Precalculus Examples

$(2 x^{6} - x^{\frac{1}{2}} - x) \cdot (x^{\frac{1}{2}} - 3 x)$

Step 1

Apply the rule $x^{\frac{m}{n}} = \sqrt[n]{x^{m}}$ to rewrite the exponentiation as a radical.

$(2 x^{6} - \sqrt{x^{1}} - x) \cdot (x^{\frac{1}{2}} - 3 x)$

Step 2

Apply the rule $x^{\frac{m}{n}} = \sqrt[n]{x^{m}}$ to rewrite the exponentiation as a radical.

$(2 x^{6} - \sqrt{x^{1}} - x) \cdot (\sqrt{x^{1}} - 3 x)$

Step 3

Anything raised to $1$ is the base itself.

$(2 x^{6} - \sqrt{x} - x) \cdot (\sqrt{x^{1}} - 3 x)$

Step 4

Anything raised to $1$ is the base itself.

$(2 x^{6} - \sqrt{x} - x) \cdot (\sqrt{x} - 3 x)$