Precalculus Examples

$x^{4} - 6 x^{3} + 16 x^{2} - 24 x \cdot x + 16$

Step 1

Simplify $x^{4} - 6 x^{3} + 16 x^{2} - 24 x \cdot x + 16$ .

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Step 1.1

Multiply $x$ by $x$ by adding the exponents.

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Step 1.1.1

Move $x$ .

$y = x^{4} - 6 x^{3} + 16 x^{2} - 24 (x \cdot x) + 16$

Step 1.1.2

Multiply $x$ by $x$ .

$y = x^{4} - 6 x^{3} + 16 x^{2} - 24 x^{2} + 16$

Step 1.2

Subtract $24 x^{2}$ from $16 x^{2}$ .

$y = x^{4} - 6 x^{3} - 8 x^{2} + 16$

Step 2

Simplify $x^{4} - 6 x^{3} + 16 x^{2} - 24 x \cdot x + 16$ .

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Step 2.1

Multiply $x$ by $x$ by adding the exponents.

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Step 2.1.1

Move $x$ .

$x^{4} - 6 x^{3} + 16 x^{2} - 24 (x \cdot x) + 16 = 0$

Step 2.1.2

Multiply $x$ by $x$ .

$x^{4} - 6 x^{3} + 16 x^{2} - 24 x^{2} + 16 = 0$

Step 2.2

Subtract $24 x^{2}$ from $16 x^{2}$ .

$x^{4} - 6 x^{3} - 8 x^{2} + 16 = 0$

Step 3

Graph each side of the equation. The solution is the x-value of the point of intersection.

$x \approx 1.09405018, 7.08426135$

Step 4