Precalculus Examples

$f (x) = 2 \sqrt{x + 5} - 2$

Step 1

Set the radicand in $\sqrt{x + 5}$ greater than or equal to $0$ to find where the expression is defined.

$x + 5 \geq 0$

Step 2

Subtract $5$ from both sides of the inequality.

$x \geq - 5$

Step 3

The domain is all values of $x$ that make the expression defined.

Interval Notation:

$[- 5, \infty)$

Set-Builder Notation:

${x | x \geq - 5}$

Step 4