Precalculus Examples

$f (x) = \frac{6 x + 5}{3 x - 1}$

Step 1

Write $f (x) = \frac{6 x + 5}{3 x - 1}$ as an equation.

$y = \frac{6 x + 5}{3 x - 1}$

Step 2

Interchange the variables.

$x = \frac{6 y + 5}{3 y - 1}$

Step 3

Solve for $y$ .

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Step 3.1

Multiply the equation by $3 y - 1$ .

$(3 y - 1) (x) = (\frac{6 y + 5}{3 y - 1}) (3 y - 1)$

Step 3.2

Simplify the left side.

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Step 3.2.1

Simplify $(3 y - 1) (x)$ .

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Step 3.2.1.1

Apply the distributive property.

$3 y x - 1 x = (\frac{6 y + 5}{3 y - 1}) (3 y - 1)$

Step 3.2.1.2

Rewrite $- 1 x$ as $- x$ .

$3 y x - x = (\frac{6 y + 5}{3 y - 1}) (3 y - 1)$

Step 3.3

Simplify the right side.

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Step 3.3.1

Cancel the common factor of $3 y - 1$ .

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Step 3.3.1.1

Cancel the common factor.

$3 y x - x = \frac{6 y + 5}{3 y - 1} (3 y - 1)$

Step 3.3.1.2

Rewrite the expression.

$3 y x - x = 6 y + 5$

Step 3.4

Solve for $y$ .

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Step 3.4.1

Subtract $6 y$ from both sides of the equation.

$3 y x - x - 6 y = 5$

Step 3.4.2

Add $x$ to both sides of the equation.

$3 y x - 6 y = 5 + x$

Step 3.4.3

Factor $3 y$ out of $3 y x - 6 y$ .

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Step 3.4.3.1

Factor $3 y$ out of $3 y x$ .

$3 y (x) - 6 y = 5 + x$

Step 3.4.3.2

Factor $3 y$ out of $- 6 y$ .

$3 y (x) + 3 y (- 2) = 5 + x$

Step 3.4.3.3

Factor $3 y$ out of $3 y (x) + 3 y (- 2)$ .

$3 y (x - 2) = 5 + x$

Step 3.4.4

Divide each term in $3 y (x - 2) = 5 + x$ by $3 (x - 2)$ and simplify.

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Step 3.4.4.1

Divide each term in $3 y (x - 2) = 5 + x$ by $3 (x - 2)$ .

$\frac{3 y (x - 2)}{3 (x - 2)} = \frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}$

Step 3.4.4.2

Simplify the left side.

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Step 3.4.4.2.1

Cancel the common factor of $3$ .

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Step 3.4.4.2.1.1

Cancel the common factor.

$\frac{3 y (x - 2)}{3 (x - 2)} = \frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}$

Step 3.4.4.2.1.2

Rewrite the expression.

$\frac{y (x - 2)}{x - 2} = \frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}$

Step 3.4.4.2.2

Cancel the common factor of $x - 2$ .

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Step 3.4.4.2.2.1

Cancel the common factor.

$\frac{y (x - 2)}{x - 2} = \frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}$

Step 3.4.4.2.2.2

Divide $y$ by $1$ .

$y = \frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}$

Step 4

Replace $y$ with $f^{- 1} (x)$ to show the final answer.

$f^{- 1} (x) = \frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}$

Step 5

Verify if $f^{- 1} (x) = \frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}$ is the inverse of $f (x) = \frac{6 x + 5}{3 x - 1}$ .

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Step 5.1

To verify the inverse, check if $f^{- 1} (f (x)) = x$ and $f (f^{- 1} (x)) = x$ .

Step 5.2

Evaluate $f^{- 1} (f (x))$ .

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Step 5.2.1

Set up the composite result function.

$f^{- 1} (f (x))$

Step 5.2.2

Evaluate $f^{- 1} (\frac{6 x + 5}{3 x - 1})$ by substituting in the value of $f$ into $f^{- 1}$ .

$f^{- 1} (\frac{6 x + 5}{3 x - 1}) = \frac{5}{3 ((\frac{6 x + 5}{3 x - 1}) - 2)} + \frac{\frac{6 x + 5}{3 x - 1}}{3 ((\frac{6 x + 5}{3 x - 1}) - 2)}$

Step 5.2.3

Combine the numerators over the common denominator.

$f^{- 1} (\frac{6 x + 5}{3 x - 1}) = \frac{5 + \frac{6 x + 5}{3 x - 1}}{3 ((\frac{6 x + 5}{3 x - 1}) - 2)}$

Step 5.2.4

To write $5$ as a fraction with a common denominator, multiply by $\frac{3 x - 1}{3 x - 1}$ .

$f^{- 1} (\frac{6 x + 5}{3 x - 1}) = \frac{\frac{5 (3 x - 1)}{3 x - 1} + \frac{6 x + 5}{3 x - 1}}{3 ((\frac{6 x + 5}{3 x - 1}) - 2)}$

Step 5.2.5

Combine the numerators over the common denominator.

$f^{- 1} (\frac{6 x + 5}{3 x - 1}) = \frac{\frac{5 (3 x - 1) + 6 x + 5}{3 x - 1}}{3 ((\frac{6 x + 5}{3 x - 1}) - 2)}$

Step 5.2.6

Simplify the numerator.

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Step 5.2.6.1

Apply the distributive property.

$f^{- 1} (\frac{6 x + 5}{3 x - 1}) = \frac{\frac{5 (3 x) + 5 \cdot - 1 + 6 x + 5}{3 x - 1}}{3 ((\frac{6 x + 5}{3 x - 1}) - 2)}$

Step 5.2.6.2

Multiply $3$ by $5$ .

$f^{- 1} (\frac{6 x + 5}{3 x - 1}) = \frac{\frac{15 x + 5 \cdot - 1 + 6 x + 5}{3 x - 1}}{3 ((\frac{6 x + 5}{3 x - 1}) - 2)}$

Step 5.2.6.3

Multiply $5$ by $- 1$ .

$f^{- 1} (\frac{6 x + 5}{3 x - 1}) = \frac{\frac{15 x - 5 + 6 x + 5}{3 x - 1}}{3 ((\frac{6 x + 5}{3 x - 1}) - 2)}$

Step 5.2.6.4

Add $15 x$ and $6 x$ .

$f^{- 1} (\frac{6 x + 5}{3 x - 1}) = \frac{\frac{21 x - 5 + 5}{3 x - 1}}{3 ((\frac{6 x + 5}{3 x - 1}) - 2)}$

Step 5.2.6.5

Add $- 5$ and $5$ .

$f^{- 1} (\frac{6 x + 5}{3 x - 1}) = \frac{\frac{21 x + 0}{3 x - 1}}{3 ((\frac{6 x + 5}{3 x - 1}) - 2)}$

Step 5.2.6.6

Add $21 x$ and $0$ .

$f^{- 1} (\frac{6 x + 5}{3 x - 1}) = \frac{\frac{21 x}{3 x - 1}}{3 ((\frac{6 x + 5}{3 x - 1}) - 2)}$

Step 5.2.7

Multiply the numerator by the reciprocal of the denominator.

$f^{- 1} (\frac{6 x + 5}{3 x - 1}) = \frac{21 x}{3 x - 1} \cdot \frac{1}{3 (\frac{6 x + 5}{3 x - 1} - 2)}$

Step 5.2.8

Simplify terms.

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Step 5.2.8.1

Cancel the common factor of $3$ .

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Step 5.2.8.1.1

Factor $3$ out of $21 x$ .

$f^{- 1} (\frac{6 x + 5}{3 x - 1}) = \frac{3 (7 x)}{3 x - 1} \cdot \frac{1}{3 (\frac{6 x + 5}{3 x - 1} - 2)}$

Step 5.2.8.1.2

Cancel the common factor.

$f^{- 1} (\frac{6 x + 5}{3 x - 1}) = \frac{3 (7 x)}{3 x - 1} \cdot \frac{1}{3 (\frac{6 x + 5}{3 x - 1} - 2)}$

Step 5.2.8.1.3

Rewrite the expression.

$f^{- 1} (\frac{6 x + 5}{3 x - 1}) = \frac{7 x}{3 x - 1} \cdot \frac{1}{\frac{6 x + 5}{3 x - 1} - 2}$

Step 5.2.8.2

Multiply $\frac{7 x}{3 x - 1}$ by $\frac{1}{\frac{6 x + 5}{3 x - 1} - 2}$ .

$f^{- 1} (\frac{6 x + 5}{3 x - 1}) = \frac{7 x}{(3 x - 1) (\frac{6 x + 5}{3 x - 1} - 2)}$

Step 5.2.9

Simplify the denominator.

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Step 5.2.9.1

To write $- 2$ as a fraction with a common denominator, multiply by $\frac{3 x - 1}{3 x - 1}$ .

$f^{- 1} (\frac{6 x + 5}{3 x - 1}) = \frac{7 x}{(3 x - 1) (\frac{6 x + 5}{3 x - 1} - 2 \cdot \frac{3 x - 1}{3 x - 1})}$

Step 5.2.9.2

Combine $- 2$ and $\frac{3 x - 1}{3 x - 1}$ .

$f^{- 1} (\frac{6 x + 5}{3 x - 1}) = \frac{7 x}{(3 x - 1) (\frac{6 x + 5}{3 x - 1} + \frac{- 2 (3 x - 1)}{3 x - 1})}$

Step 5.2.9.3

Combine the numerators over the common denominator.

$f^{- 1} (\frac{6 x + 5}{3 x - 1}) = \frac{7 x}{(3 x - 1) (\frac{6 x + 5 - 2 (3 x - 1)}{3 x - 1})}$

Step 5.2.9.4

Rewrite $\frac{6 x + 5 - 2 (3 x - 1)}{3 x - 1}$ in a factored form.

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Step 5.2.9.4.1

Apply the distributive property.

$f^{- 1} (\frac{6 x + 5}{3 x - 1}) = \frac{7 x}{(3 x - 1) (\frac{6 x + 5 - 2 (3 x) - 2 \cdot - 1}{3 x - 1})}$

Step 5.2.9.4.2

Multiply $3$ by $- 2$ .

$f^{- 1} (\frac{6 x + 5}{3 x - 1}) = \frac{7 x}{(3 x - 1) (\frac{6 x + 5 - 6 x - 2 \cdot - 1}{3 x - 1})}$

Step 5.2.9.4.3

Multiply $- 2$ by $- 1$ .

$f^{- 1} (\frac{6 x + 5}{3 x - 1}) = \frac{7 x}{(3 x - 1) (\frac{6 x + 5 - 6 x + 2}{3 x - 1})}$

Step 5.2.9.4.4

Subtract $6 x$ from $6 x$ .

$f^{- 1} (\frac{6 x + 5}{3 x - 1}) = \frac{7 x}{(3 x - 1) (\frac{0 + 5 + 2}{3 x - 1})}$

Step 5.2.9.4.5

Add $0$ and $5$ .

$f^{- 1} (\frac{6 x + 5}{3 x - 1}) = \frac{7 x}{(3 x - 1) (\frac{5 + 2}{3 x - 1})}$

Step 5.2.9.4.6

Add $5$ and $2$ .

$f^{- 1} (\frac{6 x + 5}{3 x - 1}) = \frac{7 x}{(3 x - 1) (\frac{7}{3 x - 1})}$

Step 5.2.10

Factor $\frac{7}{3 x - 1}$ out of $\frac{7 x}{(3 x - 1) \frac{7}{3 x - 1}}$ .

$f^{- 1} (\frac{6 x + 5}{3 x - 1}) = \frac{3 x - 1}{7} \cdot \frac{7 x}{3 x - 1}$

Step 5.2.11

Cancel the common factor of $3 x - 1$ .

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Step 5.2.11.1

Cancel the common factor.

$f^{- 1} (\frac{6 x + 5}{3 x - 1}) = \frac{3 x - 1}{7} \cdot \frac{7 x}{3 x - 1}$

Step 5.2.11.2

Rewrite the expression.

$f^{- 1} (\frac{6 x + 5}{3 x - 1}) = \frac{1}{7} \cdot (7 x)$

Step 5.2.12

Cancel the common factor of $7$ .

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Step 5.2.12.1

Factor $7$ out of $7 x$ .

$f^{- 1} (\frac{6 x + 5}{3 x - 1}) = \frac{1}{7} \cdot (7 (x))$

Step 5.2.12.2

Cancel the common factor.

$f^{- 1} (\frac{6 x + 5}{3 x - 1}) = \frac{1}{7} \cdot (7 x)$

Step 5.2.12.3

Rewrite the expression.

$f^{- 1} (\frac{6 x + 5}{3 x - 1}) = x$

Step 5.3

Evaluate $f (f^{- 1} (x))$ .

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Step 5.3.1

Set up the composite result function.

$f (f^{- 1} (x))$

Step 5.3.2

Evaluate $f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)})$ by substituting in the value of $f^{- 1}$ into $f$ .

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{6 (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) + 5}{3 (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) - 1}$

Step 5.3.3

Simplify the numerator.

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Step 5.3.3.1

Apply the distributive property.

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{6 (\frac{5}{3 (x - 2)}) + 6 (\frac{x}{3 (x - 2)}) + 5}{3 (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) - 1}$

Step 5.3.3.2

Cancel the common factor of $3$ .

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Step 5.3.3.2.1

Factor $3$ out of $6$ .

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{3 (2) (\frac{5}{3 (x - 2)}) + 6 (\frac{x}{3 (x - 2)}) + 5}{3 (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) - 1}$

Step 5.3.3.2.2

Cancel the common factor.

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{3 \cdot (2 (\frac{5}{3 (x - 2)})) + 6 (\frac{x}{3 (x - 2)}) + 5}{3 (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) - 1}$

Step 5.3.3.2.3

Rewrite the expression.

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{2 (\frac{5}{x - 2}) + 6 (\frac{x}{3 (x - 2)}) + 5}{3 (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) - 1}$

Step 5.3.3.3

Combine $2$ and $\frac{5}{x - 2}$ .

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{2 \cdot 5}{x - 2} + 6 (\frac{x}{3 (x - 2)}) + 5}{3 (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) - 1}$

Step 5.3.3.4

Multiply $2$ by $5$ .

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{10}{x - 2} + 6 (\frac{x}{3 (x - 2)}) + 5}{3 (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) - 1}$

Step 5.3.3.5

Cancel the common factor of $3$ .

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Step 5.3.3.5.1

Factor $3$ out of $6$ .

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{10}{x - 2} + 3 (2) (\frac{x}{3 (x - 2)}) + 5}{3 (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) - 1}$

Step 5.3.3.5.2

Cancel the common factor.

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{10}{x - 2} + 3 \cdot (2 (\frac{x}{3 (x - 2)})) + 5}{3 (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) - 1}$

Step 5.3.3.5.3

Rewrite the expression.

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{10}{x - 2} + 2 (\frac{x}{x - 2}) + 5}{3 (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) - 1}$

Step 5.3.3.6

Combine $2$ and $\frac{x}{x - 2}$ .

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{10}{x - 2} + \frac{2 x}{x - 2} + 5}{3 (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) - 1}$

Step 5.3.3.7

Combine the numerators over the common denominator.

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{10 + 2 x}{x - 2} + 5}{3 (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) - 1}$

Step 5.3.3.8

Reorder $10$ and $2 x$ .

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{2 x + 10}{x - 2} + 5}{3 (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) - 1}$

Step 5.3.3.9

Factor $2$ out of $2 x + 10$ .

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Step 5.3.3.9.1

Factor $2$ out of $2 x$ .

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{2 (x) + 10}{x - 2} + 5}{3 (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) - 1}$

Step 5.3.3.9.2

Factor $2$ out of $10$ .

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{2 x + 2 \cdot 5}{x - 2} + 5}{3 (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) - 1}$

Step 5.3.3.9.3

Factor $2$ out of $2 x + 2 \cdot 5$ .

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{2 (x + 5)}{x - 2} + 5}{3 (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) - 1}$

Step 5.3.3.10

To write $5$ as a fraction with a common denominator, multiply by $\frac{x - 2}{x - 2}$ .

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{2 (x + 5)}{x - 2} + \frac{5 (x - 2)}{x - 2}}{3 (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) - 1}$

Step 5.3.3.11

Combine the numerators over the common denominator.

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{2 (x + 5) + 5 (x - 2)}{x - 2}}{3 (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) - 1}$

Step 5.3.3.12

Reorder terms.

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{5 (x - 2) + 2 (x + 5)}{x - 2}}{3 (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) - 1}$

Step 5.3.3.13

Rewrite $\frac{5 (x - 2) + 2 (x + 5)}{x - 2}$ in a factored form.

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Step 5.3.3.13.1

Apply the distributive property.

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{5 x + 5 \cdot - 2 + 2 (x + 5)}{x - 2}}{3 (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) - 1}$

Step 5.3.3.13.2

Multiply $5$ by $- 2$ .

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{5 x - 10 + 2 (x + 5)}{x - 2}}{3 (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) - 1}$

Step 5.3.3.13.3

Apply the distributive property.

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{5 x - 10 + 2 x + 2 \cdot 5}{x - 2}}{3 (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) - 1}$

Step 5.3.3.13.4

Multiply $2$ by $5$ .

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{5 x - 10 + 2 x + 10}{x - 2}}{3 (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) - 1}$

Step 5.3.3.13.5

Add $5 x$ and $2 x$ .

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{7 x - 10 + 10}{x - 2}}{3 (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) - 1}$

Step 5.3.3.13.6

Add $- 10$ and $10$ .

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{7 x + 0}{x - 2}}{3 (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) - 1}$

Step 5.3.3.13.7

Add $7 x$ and $0$ .

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{7 x}{x - 2}}{3 (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) - 1}$

Step 5.3.4

Simplify the denominator.

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Step 5.3.4.1

Apply the distributive property.

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{7 x}{x - 2}}{3 (\frac{5}{3 (x - 2)}) + 3 (\frac{x}{3 (x - 2)}) - 1}$

Step 5.3.4.2

Cancel the common factor of $3$ .

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Step 5.3.4.2.1

Cancel the common factor.

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{7 x}{x - 2}}{3 (\frac{5}{3 (x - 2)}) + 3 (\frac{x}{3 (x - 2)}) - 1}$

Step 5.3.4.2.2

Rewrite the expression.

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{7 x}{x - 2}}{\frac{5}{x - 2} + 3 (\frac{x}{3 (x - 2)}) - 1}$

Step 5.3.4.3

Cancel the common factor of $3$ .

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Step 5.3.4.3.1

Cancel the common factor.

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{7 x}{x - 2}}{\frac{5}{x - 2} + 3 (\frac{x}{3 (x - 2)}) - 1}$

Step 5.3.4.3.2

Rewrite the expression.

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{7 x}{x - 2}}{\frac{5}{x - 2} + \frac{x}{x - 2} - 1}$

Step 5.3.4.4

Combine the numerators over the common denominator.

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{7 x}{x - 2}}{\frac{5 + x}{x - 2} - 1}$

Step 5.3.4.5

Reorder $5$ and $x$ .

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{7 x}{x - 2}}{\frac{x + 5}{x - 2} - 1}$

Step 5.3.4.6

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{x - 2}{x - 2}$ .

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{7 x}{x - 2}}{\frac{x + 5}{x - 2} - 1 \cdot \frac{x - 2}{x - 2}}$

Step 5.3.4.7

Combine $- 1$ and $\frac{x - 2}{x - 2}$ .

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{7 x}{x - 2}}{\frac{x + 5}{x - 2} + \frac{- (x - 2)}{x - 2}}$

Step 5.3.4.8

Combine the numerators over the common denominator.

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{7 x}{x - 2}}{\frac{x + 5 - (x - 2)}{x - 2}}$

Step 5.3.4.9

Rewrite $\frac{x + 5 - (x - 2)}{x - 2}$ in a factored form.

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Step 5.3.4.9.1

Apply the distributive property.

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{7 x}{x - 2}}{\frac{x + 5 - x + 2}{x - 2}}$

Step 5.3.4.9.2

Multiply $- 1$ by $- 2$ .

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{7 x}{x - 2}}{\frac{x + 5 - x + 2}{x - 2}}$

Step 5.3.4.9.3

Subtract $x$ from $x$ .

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{7 x}{x - 2}}{\frac{0 + 5 + 2}{x - 2}}$

Step 5.3.4.9.4

Add $0$ and $5$ .

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{7 x}{x - 2}}{\frac{5 + 2}{x - 2}}$

Step 5.3.4.9.5

Add $5$ and $2$ .

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{\frac{7 x}{x - 2}}{\frac{7}{x - 2}}$

Step 5.3.5

Multiply the numerator by the reciprocal of the denominator.

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{7 x}{x - 2} \cdot \frac{x - 2}{7}$

Step 5.3.6

Cancel the common factor of $7$ .

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Step 5.3.6.1

Factor $7$ out of $7 x$ .

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{7 (x)}{x - 2} \cdot \frac{x - 2}{7}$

Step 5.3.6.2

Cancel the common factor.

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{7 x}{x - 2} \cdot \frac{x - 2}{7}$

Step 5.3.6.3

Rewrite the expression.

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{x}{x - 2} \cdot (x - 2)$

Step 5.3.7

Cancel the common factor of $x - 2$ .

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Step 5.3.7.1

Cancel the common factor.

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = \frac{x}{x - 2} \cdot (x - 2)$

Step 5.3.7.2

Rewrite the expression.

$f (\frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}) = x$

Step 5.4

Since $f^{- 1} (f (x)) = x$ and $f (f^{- 1} (x)) = x$ , then $f^{- 1} (x) = \frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}$ is the inverse of $f (x) = \frac{6 x + 5}{3 x - 1}$ .

$f^{- 1} (x) = \frac{5}{3 (x - 2)} + \frac{x}{3 (x - 2)}$