Precalculus Examples

$2.5 x + 4.9 y = 2279$ , $x + y = 710$

Step 1

Subtract $2.5 x$ from both sides of the equation.

$4.9 y = 2279 - 2.5 x$

$x + y = 710$

Step 2

Divide each term in $4.9 y = 2279 - 2.5 x$ by $4.9$ and simplify.

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Step 2.1

Divide each term in $4.9 y = 2279 - 2.5 x$ by $4.9$ .

$\frac{4.9 y}{4.9} = \frac{2279}{4.9} + \frac{- 2.5 x}{4.9}$

$x + y = 710$

Step 2.2

Simplify the left side.

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Step 2.2.1

Cancel the common factor of $4.9$ .

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Step 2.2.1.1

Cancel the common factor.

$\frac{4.9 y}{4.9} = \frac{2279}{4.9} + \frac{- 2.5 x}{4.9}$

$x + y = 710$

Step 2.2.1.2

Divide $y$ by $1$ .

$y = \frac{2279}{4.9} + \frac{- 2.5 x}{4.9}$

$x + y = 710$

$y = \frac{2279}{4.9} + \frac{- 2.5 x}{4.9}$

$x + y = 710$

$y = \frac{2279}{4.9} + \frac{- 2.5 x}{4.9}$

$x + y = 710$

Step 2.3

Simplify the right side.

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Step 2.3.1

Simplify each term.

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Step 2.3.1.1

Divide $2279$ by $4.9$ .

$y = 465.10204081 + \frac{- 2.5 x}{4.9}$

$x + y = 710$

Step 2.3.1.2

Move the negative in front of the fraction.

$y = 465.10204081 - \frac{2.5 x}{4.9}$

$x + y = 710$

Step 2.3.1.3

Factor $2.5$ out of $2.5 x$ .

$y = 465.10204081 - \frac{2.5 (x)}{4.9}$

$x + y = 710$

Step 2.3.1.4

Factor $4.9$ out of $4.9$ .

$y = 465.10204081 - \frac{2.5 (x)}{4.9 (1)}$

$x + y = 710$

Step 2.3.1.5

Separate fractions.

$y = 465.10204081 - (\frac{2.5}{4.9} \cdot \frac{x}{1})$

$x + y = 710$

Step 2.3.1.6

Divide $2.5$ by $4.9$ .

$y = 465.10204081 - (0.51020408 (\frac{x}{1}))$

$x + y = 710$

Step 2.3.1.7

Divide $x$ by $1$ .

$y = 465.10204081 - (0.51020408 x)$

$x + y = 710$

Step 2.3.1.8

Multiply $0.51020408$ by $- 1$ .