Precalculus Examples

$x - y^{2} = 0$ , $y - x^{2} = 0$

Step 1

Add $y^{2}$ to both sides of the equation.

$x = y^{2}$

$y - x^{2} = 0$

Step 2

Replace all occurrences of $x$ with $y^{2}$ in each equation.

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Step 2.1

Replace all occurrences of $x$ in $y - x^{2} = 0$ with $y^{2}$ .

$y - {(y^{2})}^{2} = 0$

$x = y^{2}$

Step 2.2

Simplify the left side.

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Step 2.2.1

Multiply the exponents in ${(y^{2})}^{2}$ .

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Step 2.2.1.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$y - y^{2 \cdot 2} = 0$

$x = y^{2}$

Step 2.2.1.2

Multiply $2$ by $2$ .

$y - y^{4} = 0$

$x = y^{2}$

$y - y^{4} = 0$

$x = y^{2}$

$y - y^{4} = 0$

$x = y^{2}$

$y - y^{4} = 0$

$x = y^{2}$

Step 3

Solve for $y$ in $y - y^{4} = 0$ .

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Step 3.1

Factor the left side of the equation.

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Step 3.1.1

Factor $y$ out of $y - y^{4}$ .

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Step 3.1.1.1

Raise $y$ to the power of $1$ .

$y - y^{4} = 0$

$x = y^{2}$

Step 3.1.1.2

Factor $y$ out of $y^{1}$ .

$y \cdot 1 - y^{4} = 0$

$x = y^{2}$

Step 3.1.1.3

Factor $y$ out of $- y^{4}$ .

$y \cdot 1 + y (- y^{3}) = 0$

$x = y^{2}$

Step 3.1.1.4

Factor $y$ out of $y \cdot 1 + y (- y^{3})$ .

$y \cdot (1 - y^{3}) = 0$

$x = y^{2}$

Step 3.1.1.5

Multiply $y$ by $1 - y^{3}$ .

$y (1 - y^{3}) = 0$

$x = y^{2}$

$y (1 - y^{3}) = 0$

$x = y^{2}$

Step 3.1.2

Rewrite $1$ as $1^{3}$ .

$y (1^{3} - y^{3}) = 0$

$x = y^{2}$

Step 3.1.3

Since both terms are perfect cubes, factor using the difference of cubes formula, $a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2})$ where $a = 1$ and $b = y$ .

$y ((1 - y) (1^{2} + 1 y + y^{2})) = 0$

$x = y^{2}$

Step 3.1.4

Factor.

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Step 3.1.4.1

Simplify.

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Step 3.1.4.1.1

One to any power is one.

$y ((1 - y) (1 + 1 y + y^{2})) = 0$

$x = y^{2}$

Step 3.1.4.1.2

Multiply $y$ by $1$ .

$y ((1 - y) (1 + y + y^{2})) = 0$

$x = y^{2}$

$y ((1 - y) (1 + y + y^{2})) = 0$

$x = y^{2}$

Step 3.1.4.2

Remove unnecessary parentheses.

$y (1 - y) (1 + y + y^{2}) = 0$

$x = y^{2}$

$y (1 - y) (1 + y + y^{2}) = 0$

$x = y^{2}$

$y (1 - y) (1 + y + y^{2}) = 0$

$x = y^{2}$

Step 3.2

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$y = 0$

$1 - y = 0$

$1 + y + y^{2} = 0$

$x = y^{2}$

Step 3.3

Set $y$ equal to $0$ .

$y = 0$

$x = y^{2}$

Step 3.4

Set $1 - y$ equal to $0$ and solve for $y$ .

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Step 3.4.1

Set $1 - y$ equal to $0$ .

$1 - y = 0$

$x = y^{2}$

Step 3.4.2

Solve $1 - y = 0$ for $y$ .

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Step 3.4.2.1

Subtract $1$ from both sides of the equation.

$- y = - 1$

$x = y^{2}$

Step 3.4.2.2

Divide each term in $- y = - 1$ by $- 1$ and simplify.

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Step 3.4.2.2.1

Divide each term in $- y = - 1$ by $- 1$ .

$\frac{- y}{- 1} = \frac{- 1}{- 1}$

$x = y^{2}$

Step 3.4.2.2.2

Simplify the left side.

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Step 3.4.2.2.2.1

Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{- 1}{- 1}$

$x = y^{2}$

Step 3.4.2.2.2.2

Divide $y$ by $1$ .

$y = \frac{- 1}{- 1}$

$x = y^{2}$

$y = \frac{- 1}{- 1}$

$x = y^{2}$

Step 3.4.2.2.3

Simplify the right side.

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Step 3.4.2.2.3.1

Divide $- 1$ by $- 1$ .

$y = 1$

$x = y^{2}$

$y = 1$

$x = y^{2}$

$y = 1$

$x = y^{2}$

$y = 1$

$x = y^{2}$

$y = 1$

$x = y^{2}$

Step 3.5

Set $1 + y + y^{2}$ equal to $0$ and solve for $y$ .

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Step 3.5.1

Set $1 + y + y^{2}$ equal to $0$ .

$1 + y + y^{2} = 0$

$x = y^{2}$

Step 3.5.2

Solve $1 + y + y^{2} = 0$ for $y$ .

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Step 3.5.2.1

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

$x = y^{2}$

Step 3.5.2.2

Substitute the values $a = 1$ , $b = 1$ , and $c = 1$ into the quadratic formula and solve for $y$ .

$\frac{- 1 \pm \sqrt{1^{2} - 4 \cdot (1 \cdot 1)}}{2 \cdot 1}$

$x = y^{2}$

Step 3.5.2.3

Simplify.

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Step 3.5.2.3.1

Simplify the numerator.

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Step 3.5.2.3.1.1

One to any power is one.

$y = \frac{- 1 \pm \sqrt{1 - 4 \cdot 1 \cdot 1}}{2 \cdot 1}$

$x = y^{2}$

Step 3.5.2.3.1.2

Multiply $- 4 \cdot 1 \cdot 1$ .

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Step 3.5.2.3.1.2.1

Multiply $- 4$ by $1$ .

$y = \frac{- 1 \pm \sqrt{1 - 4 \cdot 1}}{2 \cdot 1}$

$x = y^{2}$

Step 3.5.2.3.1.2.2

Multiply $- 4$ by $1$ .

$y = \frac{- 1 \pm \sqrt{1 - 4}}{2 \cdot 1}$

$x = y^{2}$

$y = \frac{- 1 \pm \sqrt{1 - 4}}{2 \cdot 1}$

$x = y^{2}$

Step 3.5.2.3.1.3

Subtract $4$ from $1$ .

$y = \frac{- 1 \pm \sqrt{- 3}}{2 \cdot 1}$

$x = y^{2}$

Step 3.5.2.3.1.4

Rewrite $- 3$ as $- 1 (3)$ .

$y = \frac{- 1 \pm \sqrt{- 1 \cdot 3}}{2 \cdot 1}$

$x = y^{2}$

Step 3.5.2.3.1.5

Rewrite $\sqrt{- 1 (3)}$ as $\sqrt{- 1} \cdot \sqrt{3}$ .

$y = \frac{- 1 \pm \sqrt{- 1} \cdot \sqrt{3}}{2 \cdot 1}$

$x = y^{2}$

Step 3.5.2.3.1.6

Rewrite $\sqrt{- 1}$ as $i$ .

$y = \frac{- 1 \pm i \sqrt{3}}{2 \cdot 1}$

$x = y^{2}$

$y = \frac{- 1 \pm i \sqrt{3}}{2 \cdot 1}$

$x = y^{2}$

Step 3.5.2.3.2

Multiply $2$ by $1$ .

$y = \frac{- 1 \pm i \sqrt{3}}{2}$

$x = y^{2}$

$y = \frac{- 1 \pm i \sqrt{3}}{2}$

$x = y^{2}$

Step 3.5.2.4

Simplify the expression to solve for the $+$ portion of the $\pm$ .

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Step 3.5.2.4.1

Simplify the numerator.

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Step 3.5.2.4.1.1

One to any power is one.

$y = \frac{- 1 \pm \sqrt{1 - 4 \cdot 1 \cdot 1}}{2 \cdot 1}$

$x = y^{2}$

Step 3.5.2.4.1.2

Multiply $- 4 \cdot 1 \cdot 1$ .

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Step 3.5.2.4.1.2.1

Multiply $- 4$ by $1$ .

$y = \frac{- 1 \pm \sqrt{1 - 4 \cdot 1}}{2 \cdot 1}$

$x = y^{2}$

Step 3.5.2.4.1.2.2

Multiply $- 4$ by $1$ .

$y = \frac{- 1 \pm \sqrt{1 - 4}}{2 \cdot 1}$

$x = y^{2}$

$y = \frac{- 1 \pm \sqrt{1 - 4}}{2 \cdot 1}$

$x = y^{2}$

Step 3.5.2.4.1.3

Subtract $4$ from $1$ .

$y = \frac{- 1 \pm \sqrt{- 3}}{2 \cdot 1}$

$x = y^{2}$

Step 3.5.2.4.1.4

Rewrite $- 3$ as $- 1 (3)$ .

$y = \frac{- 1 \pm \sqrt{- 1 \cdot 3}}{2 \cdot 1}$

$x = y^{2}$

Step 3.5.2.4.1.5

Rewrite $\sqrt{- 1 (3)}$ as $\sqrt{- 1} \cdot \sqrt{3}$ .

$y = \frac{- 1 \pm \sqrt{- 1} \cdot \sqrt{3}}{2 \cdot 1}$

$x = y^{2}$

Step 3.5.2.4.1.6

Rewrite $\sqrt{- 1}$ as $i$ .

$y = \frac{- 1 \pm i \sqrt{3}}{2 \cdot 1}$

$x = y^{2}$

$y = \frac{- 1 \pm i \sqrt{3}}{2 \cdot 1}$

$x = y^{2}$

Step 3.5.2.4.2

Multiply $2$ by $1$ .

$y = \frac{- 1 \pm i \sqrt{3}}{2}$

$x = y^{2}$

Step 3.5.2.4.3

Change the $\pm$ to $+$ .

$y = \frac{- 1 + i \sqrt{3}}{2}$

$x = y^{2}$

Step 3.5.2.4.4

Rewrite $- 1$ as $- 1 (1)$ .

$y = \frac{- 1 \cdot 1 + i \sqrt{3}}{2}$

$x = y^{2}$

Step 3.5.2.4.5

Factor $- 1$ out of $i \sqrt{3}$ .

$y = \frac{- 1 \cdot 1 - (- i \sqrt{3})}{2}$

$x = y^{2}$

Step 3.5.2.4.6

Factor $- 1$ out of $- 1 (1) - (- i \sqrt{3})$ .

$y = \frac{- 1 (1 - i \sqrt{3})}{2}$

$x = y^{2}$

Step 3.5.2.4.7

Move the negative in front of the fraction.

$y = - \frac{1 - i \sqrt{3}}{2}$

$x = y^{2}$

$y = - \frac{1 - i \sqrt{3}}{2}$

$x = y^{2}$

Step 3.5.2.5

Simplify the expression to solve for the $-$ portion of the $\pm$ .

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Step 3.5.2.5.1

Simplify the numerator.

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Step 3.5.2.5.1.1

One to any power is one.

$y = \frac{- 1 \pm \sqrt{1 - 4 \cdot 1 \cdot 1}}{2 \cdot 1}$

$x = y^{2}$

Step 3.5.2.5.1.2

Multiply $- 4 \cdot 1 \cdot 1$ .

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Step 3.5.2.5.1.2.1

Multiply $- 4$ by $1$ .

$y = \frac{- 1 \pm \sqrt{1 - 4 \cdot 1}}{2 \cdot 1}$

$x = y^{2}$

Step 3.5.2.5.1.2.2

Multiply $- 4$ by $1$ .

$y = \frac{- 1 \pm \sqrt{1 - 4}}{2 \cdot 1}$

$x = y^{2}$

$y = \frac{- 1 \pm \sqrt{1 - 4}}{2 \cdot 1}$

$x = y^{2}$

Step 3.5.2.5.1.3

Subtract $4$ from $1$ .

$y = \frac{- 1 \pm \sqrt{- 3}}{2 \cdot 1}$

$x = y^{2}$

Step 3.5.2.5.1.4

Rewrite $- 3$ as $- 1 (3)$ .

$y = \frac{- 1 \pm \sqrt{- 1 \cdot 3}}{2 \cdot 1}$

$x = y^{2}$

Step 3.5.2.5.1.5

Rewrite $\sqrt{- 1 (3)}$ as $\sqrt{- 1} \cdot \sqrt{3}$ .

$y = \frac{- 1 \pm \sqrt{- 1} \cdot \sqrt{3}}{2 \cdot 1}$

$x = y^{2}$

Step 3.5.2.5.1.6

Rewrite $\sqrt{- 1}$ as $i$ .

$y = \frac{- 1 \pm i \sqrt{3}}{2 \cdot 1}$

$x = y^{2}$

$y = \frac{- 1 \pm i \sqrt{3}}{2 \cdot 1}$

$x = y^{2}$

Step 3.5.2.5.2

Multiply $2$ by $1$ .

$y = \frac{- 1 \pm i \sqrt{3}}{2}$

$x = y^{2}$

Step 3.5.2.5.3

Change the $\pm$ to $-$ .

$y = \frac{- 1 - i \sqrt{3}}{2}$

$x = y^{2}$

Step 3.5.2.5.4

Rewrite $- 1$ as $- 1 (1)$ .

$y = \frac{- 1 \cdot 1 - i \sqrt{3}}{2}$

$x = y^{2}$

Step 3.5.2.5.5

Factor $- 1$ out of $- i \sqrt{3}$ .

$y = \frac{- 1 \cdot 1 - (i \sqrt{3})}{2}$

$x = y^{2}$

Step 3.5.2.5.6

Factor $- 1$ out of $- 1 (1) - (i \sqrt{3})$ .

$y = \frac{- 1 (1 + i \sqrt{3})}{2}$

$x = y^{2}$

Step 3.5.2.5.7

Move the negative in front of the fraction.

$y = - \frac{1 + i \sqrt{3}}{2}$

$x = y^{2}$

$y = - \frac{1 + i \sqrt{3}}{2}$

$x = y^{2}$

Step 3.5.2.6

The final answer is the combination of both solutions.

$y = - \frac{1 - i \sqrt{3}}{2}, - \frac{1 + i \sqrt{3}}{2}$

$x = y^{2}$

$y = - \frac{1 - i \sqrt{3}}{2}, - \frac{1 + i \sqrt{3}}{2}$

$x = y^{2}$

$y = - \frac{1 - i \sqrt{3}}{2}, - \frac{1 + i \sqrt{3}}{2}$

$x = y^{2}$

Step 3.6

The final solution is all the values that make $y (1 - y) (1 + y + y^{2}) = 0$ true.

$y = 0, 1, - \frac{1 - i \sqrt{3}}{2}, - \frac{1 + i \sqrt{3}}{2}$

$x = y^{2}$

$y = 0, 1, - \frac{1 - i \sqrt{3}}{2}, - \frac{1 + i \sqrt{3}}{2}$

$x = y^{2}$

Step 4

Replace all occurrences of $y$ with $0$ in each equation.

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Step 4.1

Replace all occurrences of $y$ in $x = y^{2}$ with $0$ .

$x = {(0)}^{2}$

$y = 0$

Step 4.2

Simplify the right side.

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Step 4.2.1

Raising $0$ to any positive power yields $0$ .

$x = 0$

$y = 0$

$x = 0$

$y = 0$

$x = 0$

$y = 0$

Step 5

Replace all occurrences of $y$ with $1$ in each equation.

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Step 5.1

Replace all occurrences of $y$ in $x = y^{2}$ with $1$ .

$x = {(1)}^{2}$

$y = 1$

Step 5.2

Simplify the right side.

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Step 5.2.1

One to any power is one.

$x = 1$

$y = 1$

$x = 1$

$y = 1$

$x = 1$

$y = 1$

Step 6

Replace all occurrences of $y$ with $0$ in each equation.

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Step 6.1

Replace all occurrences of $y$ in $x = y^{2}$ with $0$ .

$x = {(0)}^{2}$

$y = 0$

Step 6.2

Simplify the right side.

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Step 6.2.1

Raising $0$ to any positive power yields $0$ .

$x = 0$

$y = 0$

$x = 0$

$y = 0$

$x = 0$

$y = 0$

Step 7

Replace all occurrences of $y$ with $1$ in each equation.

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Step 7.1

Replace all occurrences of $y$ in $x = y^{2}$ with $1$ .

$x = {(1)}^{2}$

$y = 1$

Step 7.2

Simplify the right side.

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Step 7.2.1

One to any power is one.

$x = 1$

$y = 1$

$x = 1$

$y = 1$

$x = 1$

$y = 1$

Step 8

Replace all occurrences of $y$ with $- \frac{1 - i \sqrt{3}}{2}$ in each equation.

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Step 8.1

Replace all occurrences of $y$ in $x = y^{2}$ with $- \frac{1 - i \sqrt{3}}{2}$ .

$x = {(- \frac{1 - i \sqrt{3}}{2})}^{2}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2

Simplify the right side.

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Step 8.2.1

Simplify ${(- \frac{1 - i \sqrt{3}}{2})}^{2}$ .

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Step 8.2.1.1

Use the power rule ${(a b)}^{n} = a^{n} b^{n}$ to distribute the exponent.

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Step 8.2.1.1.1

Apply the product rule to $- \frac{1 - i \sqrt{3}}{2}$ .

$x = {(- 1)}^{2} {(\frac{1 - i \sqrt{3}}{2})}^{2}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.1.2

Apply the product rule to $\frac{1 - i \sqrt{3}}{2}$ .

$x = {(- 1)}^{2} (\frac{{(1 - i \sqrt{3})}^{2}}{2^{2}})$

$y = - \frac{1 - i \sqrt{3}}{2}$

$x = {(- 1)}^{2} (\frac{{(1 - i \sqrt{3})}^{2}}{2^{2}})$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.2

Simplify the expression.

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Step 8.2.1.2.1

Raise $- 1$ to the power of $2$ .

$x = 1 (\frac{{(1 - i \sqrt{3})}^{2}}{2^{2}})$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.2.2

Multiply $\frac{{(1 - i \sqrt{3})}^{2}}{2^{2}}$ by $1$ .

$x = \frac{{(1 - i \sqrt{3})}^{2}}{2^{2}}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.2.3

Raise $2$ to the power of $2$ .

$x = \frac{{(1 - i \sqrt{3})}^{2}}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.2.4

Rewrite ${(1 - i \sqrt{3})}^{2}$ as $(1 - i \sqrt{3}) (1 - i \sqrt{3})$ .

$x = \frac{(1 - i \sqrt{3}) (1 - i \sqrt{3})}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

$x = \frac{(1 - i \sqrt{3}) (1 - i \sqrt{3})}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.3

Expand $(1 - i \sqrt{3}) (1 - i \sqrt{3})$ using the FOIL Method.

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Step 8.2.1.3.1

Apply the distributive property.

$x = \frac{1 (1 - i \sqrt{3}) - i \sqrt{3} (1 - i \sqrt{3})}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.3.2

Apply the distributive property.

$x = \frac{1 \cdot 1 + 1 (- i \sqrt{3}) - i \sqrt{3} (1 - i \sqrt{3})}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.3.3

Apply the distributive property.

$x = \frac{1 \cdot 1 + 1 (- i \sqrt{3}) - i \sqrt{3} \cdot 1 - i \sqrt{3} (- i \sqrt{3})}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

$x = \frac{1 \cdot 1 + 1 (- i \sqrt{3}) - i \sqrt{3} \cdot 1 - i \sqrt{3} (- i \sqrt{3})}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.4

Simplify and combine like terms.

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Step 8.2.1.4.1

Simplify each term.

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Step 8.2.1.4.1.1

Multiply $1$ by $1$ .

$x = \frac{1 + 1 (- i \sqrt{3}) - i \sqrt{3} \cdot 1 - i \sqrt{3} (- i \sqrt{3})}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.4.1.2

Multiply $- i \sqrt{3}$ by $1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} \cdot 1 - i \sqrt{3} (- i \sqrt{3})}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.4.1.3

Multiply $- 1$ by $1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} - i \sqrt{3} (- i \sqrt{3})}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.4.1.4

Multiply $- i \sqrt{3} (- i \sqrt{3})$ .

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Step 8.2.1.4.1.4.1

Multiply $- 1$ by $- 1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + 1 i \sqrt{3} (i \sqrt{3})}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.4.1.4.2

Multiply $\sqrt{3}$ by $1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + \sqrt{3} i (i \sqrt{3})}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.4.1.4.3

Raise $\sqrt{3}$ to the power of $1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + \sqrt{3} \sqrt{3} i i}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.4.1.4.4

Raise $\sqrt{3}$ to the power of $1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + \sqrt{3} \sqrt{3} i i}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.4.1.4.5

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + {\sqrt{3}}^{1 + 1} i i}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.4.1.4.6

Add $1$ and $1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + {\sqrt{3}}^{2} i i}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.4.1.4.7

Raise $i$ to the power of $1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + {\sqrt{3}}^{2} (i i)}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.4.1.4.8

Raise $i$ to the power of $1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + {\sqrt{3}}^{2} (i i)}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.4.1.4.9

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + {\sqrt{3}}^{2} i^{1 + 1}}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.4.1.4.10

Add $1$ and $1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + {\sqrt{3}}^{2} i^{2}}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + {\sqrt{3}}^{2} i^{2}}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.4.1.5

Rewrite ${\sqrt{3}}^{2}$ as $3$ .

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Step 8.2.1.4.1.5.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{3}$ as $3^{\frac{1}{2}}$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + {(3^{\frac{1}{2}})}^{2} i^{2}}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.4.1.5.2

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + 3^{\frac{1}{2} \cdot 2} i^{2}}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.4.1.5.3

Combine $\frac{1}{2}$ and $2$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + 3^{\frac{2}{2}} i^{2}}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.4.1.5.4

Cancel the common factor of $2$ .

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Step 8.2.1.4.1.5.4.1

Cancel the common factor.

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + 3^{\frac{2}{2}} i^{2}}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.4.1.5.4.2

Rewrite the expression.

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + 3 i^{2}}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + 3 i^{2}}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.4.1.5.5

Evaluate the exponent.

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + 3 i^{2}}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + 3 i^{2}}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.4.1.6

Rewrite $i^{2}$ as $- 1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + 3 \cdot - 1}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.4.1.7

Multiply $3$ by $- 1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} - 3}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} - 3}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.4.2

Subtract $3$ from $1$ .

$x = \frac{- i \sqrt{3} - i \sqrt{3} - 2}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.4.3

Subtract $i \sqrt{3}$ from $- i \sqrt{3}$ .

$x = \frac{- 2 i \sqrt{3} - 2}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

$x = \frac{- 2 i \sqrt{3} - 2}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.5

Reorder $- 2 i \sqrt{3}$ and $- 2$ .

$x = \frac{- 2 - 2 i \sqrt{3}}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.6

Cancel the common factor of $- 2 - 2 i \sqrt{3}$ and $4$ .

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Step 8.2.1.6.1

Factor $2$ out of $- 2$ .

$x = \frac{2 (- 1) - 2 i \sqrt{3}}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.6.2

Factor $2$ out of $- 2 i \sqrt{3}$ .

$x = \frac{2 (- 1) + 2 (- i \sqrt{3})}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.6.3

Factor $2$ out of $2 (- 1) + 2 (- i \sqrt{3})$ .

$x = \frac{2 (- 1 - i \sqrt{3})}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.6.4

Cancel the common factors.

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Step 8.2.1.6.4.1

Factor $2$ out of $4$ .

$x = \frac{2 (- 1 - i \sqrt{3})}{2 \cdot 2}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.6.4.2

Cancel the common factor.

$x = \frac{2 (- 1 - i \sqrt{3})}{2 \cdot 2}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.6.4.3

Rewrite the expression.

$x = \frac{- 1 - i \sqrt{3}}{2}$

$y = - \frac{1 - i \sqrt{3}}{2}$

$x = \frac{- 1 - i \sqrt{3}}{2}$

$y = - \frac{1 - i \sqrt{3}}{2}$

$x = \frac{- 1 - i \sqrt{3}}{2}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.7

Rewrite $- 1$ as $- 1 (1)$ .

$x = \frac{- 1 \cdot 1 - i \sqrt{3}}{2}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.8

Factor $- 1$ out of $- i \sqrt{3}$ .

$x = \frac{- 1 \cdot 1 - (i \sqrt{3})}{2}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.9

Factor $- 1$ out of $- 1 (1) - (i \sqrt{3})$ .

$x = \frac{- 1 (1 + i \sqrt{3})}{2}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 8.2.1.10

Move the negative in front of the fraction.

$x = - \frac{1 + i \sqrt{3}}{2}$

$y = - \frac{1 - i \sqrt{3}}{2}$

$x = - \frac{1 + i \sqrt{3}}{2}$

$y = - \frac{1 - i \sqrt{3}}{2}$

$x = - \frac{1 + i \sqrt{3}}{2}$

$y = - \frac{1 - i \sqrt{3}}{2}$

$x = - \frac{1 + i \sqrt{3}}{2}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 9

Replace all occurrences of $y$ with $0$ in each equation.

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Step 9.1

Replace all occurrences of $y$ in $x = y^{2}$ with $0$ .

$x = {(0)}^{2}$

$y = 0$

Step 9.2

Simplify the right side.

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Step 9.2.1

Raising $0$ to any positive power yields $0$ .

$x = 0$

$y = 0$

$x = 0$

$y = 0$

$x = 0$

$y = 0$

Step 10

Replace all occurrences of $y$ with $1$ in each equation.

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Step 10.1

Replace all occurrences of $y$ in $x = y^{2}$ with $1$ .

$x = {(1)}^{2}$

$y = 1$

Step 10.2

Simplify the right side.

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Step 10.2.1

One to any power is one.

$x = 1$

$y = 1$

$x = 1$

$y = 1$

$x = 1$

$y = 1$

Step 11

Replace all occurrences of $y$ with $- \frac{1 - i \sqrt{3}}{2}$ in each equation.

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Step 11.1

Replace all occurrences of $y$ in $x = y^{2}$ with $- \frac{1 - i \sqrt{3}}{2}$ .

$x = {(- \frac{1 - i \sqrt{3}}{2})}^{2}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2

Simplify the right side.

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Step 11.2.1

Simplify ${(- \frac{1 - i \sqrt{3}}{2})}^{2}$ .

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Step 11.2.1.1

Use the power rule ${(a b)}^{n} = a^{n} b^{n}$ to distribute the exponent.

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Step 11.2.1.1.1

Apply the product rule to $- \frac{1 - i \sqrt{3}}{2}$ .

$x = {(- 1)}^{2} {(\frac{1 - i \sqrt{3}}{2})}^{2}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.1.2

Apply the product rule to $\frac{1 - i \sqrt{3}}{2}$ .

$x = {(- 1)}^{2} (\frac{{(1 - i \sqrt{3})}^{2}}{2^{2}})$

$y = - \frac{1 - i \sqrt{3}}{2}$

$x = {(- 1)}^{2} (\frac{{(1 - i \sqrt{3})}^{2}}{2^{2}})$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.2

Simplify the expression.

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Step 11.2.1.2.1

Raise $- 1$ to the power of $2$ .

$x = 1 (\frac{{(1 - i \sqrt{3})}^{2}}{2^{2}})$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.2.2

Multiply $\frac{{(1 - i \sqrt{3})}^{2}}{2^{2}}$ by $1$ .

$x = \frac{{(1 - i \sqrt{3})}^{2}}{2^{2}}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.2.3

Raise $2$ to the power of $2$ .

$x = \frac{{(1 - i \sqrt{3})}^{2}}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.2.4

Rewrite ${(1 - i \sqrt{3})}^{2}$ as $(1 - i \sqrt{3}) (1 - i \sqrt{3})$ .

$x = \frac{(1 - i \sqrt{3}) (1 - i \sqrt{3})}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

$x = \frac{(1 - i \sqrt{3}) (1 - i \sqrt{3})}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.3

Expand $(1 - i \sqrt{3}) (1 - i \sqrt{3})$ using the FOIL Method.

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Step 11.2.1.3.1

Apply the distributive property.

$x = \frac{1 (1 - i \sqrt{3}) - i \sqrt{3} (1 - i \sqrt{3})}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.3.2

Apply the distributive property.

$x = \frac{1 \cdot 1 + 1 (- i \sqrt{3}) - i \sqrt{3} (1 - i \sqrt{3})}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.3.3

Apply the distributive property.

$x = \frac{1 \cdot 1 + 1 (- i \sqrt{3}) - i \sqrt{3} \cdot 1 - i \sqrt{3} (- i \sqrt{3})}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

$x = \frac{1 \cdot 1 + 1 (- i \sqrt{3}) - i \sqrt{3} \cdot 1 - i \sqrt{3} (- i \sqrt{3})}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.4

Simplify and combine like terms.

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Step 11.2.1.4.1

Simplify each term.

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Step 11.2.1.4.1.1

Multiply $1$ by $1$ .

$x = \frac{1 + 1 (- i \sqrt{3}) - i \sqrt{3} \cdot 1 - i \sqrt{3} (- i \sqrt{3})}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.4.1.2

Multiply $- i \sqrt{3}$ by $1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} \cdot 1 - i \sqrt{3} (- i \sqrt{3})}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.4.1.3

Multiply $- 1$ by $1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} - i \sqrt{3} (- i \sqrt{3})}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.4.1.4

Multiply $- i \sqrt{3} (- i \sqrt{3})$ .

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Step 11.2.1.4.1.4.1

Multiply $- 1$ by $- 1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + 1 i \sqrt{3} (i \sqrt{3})}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.4.1.4.2

Multiply $\sqrt{3}$ by $1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + \sqrt{3} i (i \sqrt{3})}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.4.1.4.3

Raise $\sqrt{3}$ to the power of $1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + \sqrt{3} \sqrt{3} i i}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.4.1.4.4

Raise $\sqrt{3}$ to the power of $1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + \sqrt{3} \sqrt{3} i i}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.4.1.4.5

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + {\sqrt{3}}^{1 + 1} i i}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.4.1.4.6

Add $1$ and $1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + {\sqrt{3}}^{2} i i}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.4.1.4.7

Raise $i$ to the power of $1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + {\sqrt{3}}^{2} (i i)}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.4.1.4.8

Raise $i$ to the power of $1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + {\sqrt{3}}^{2} (i i)}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.4.1.4.9

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + {\sqrt{3}}^{2} i^{1 + 1}}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.4.1.4.10

Add $1$ and $1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + {\sqrt{3}}^{2} i^{2}}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + {\sqrt{3}}^{2} i^{2}}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.4.1.5

Rewrite ${\sqrt{3}}^{2}$ as $3$ .

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Step 11.2.1.4.1.5.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{3}$ as $3^{\frac{1}{2}}$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + {(3^{\frac{1}{2}})}^{2} i^{2}}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.4.1.5.2

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + 3^{\frac{1}{2} \cdot 2} i^{2}}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.4.1.5.3

Combine $\frac{1}{2}$ and $2$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + 3^{\frac{2}{2}} i^{2}}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.4.1.5.4

Cancel the common factor of $2$ .

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Step 11.2.1.4.1.5.4.1

Cancel the common factor.

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + 3^{\frac{2}{2}} i^{2}}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.4.1.5.4.2

Rewrite the expression.

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + 3 i^{2}}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + 3 i^{2}}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.4.1.5.5

Evaluate the exponent.

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + 3 i^{2}}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + 3 i^{2}}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.4.1.6

Rewrite $i^{2}$ as $- 1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} + 3 \cdot - 1}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.4.1.7

Multiply $3$ by $- 1$ .

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} - 3}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

$x = \frac{1 - i \sqrt{3} - i \sqrt{3} - 3}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.4.2

Subtract $3$ from $1$ .

$x = \frac{- i \sqrt{3} - i \sqrt{3} - 2}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.4.3

Subtract $i \sqrt{3}$ from $- i \sqrt{3}$ .

$x = \frac{- 2 i \sqrt{3} - 2}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

$x = \frac{- 2 i \sqrt{3} - 2}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.5

Reorder $- 2 i \sqrt{3}$ and $- 2$ .

$x = \frac{- 2 - 2 i \sqrt{3}}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.6

Cancel the common factor of $- 2 - 2 i \sqrt{3}$ and $4$ .

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Step 11.2.1.6.1

Factor $2$ out of $- 2$ .

$x = \frac{2 (- 1) - 2 i \sqrt{3}}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.6.2

Factor $2$ out of $- 2 i \sqrt{3}$ .

$x = \frac{2 (- 1) + 2 (- i \sqrt{3})}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.6.3

Factor $2$ out of $2 (- 1) + 2 (- i \sqrt{3})$ .

$x = \frac{2 (- 1 - i \sqrt{3})}{4}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.6.4

Cancel the common factors.

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Step 11.2.1.6.4.1

Factor $2$ out of $4$ .

$x = \frac{2 (- 1 - i \sqrt{3})}{2 \cdot 2}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.6.4.2

Cancel the common factor.

$x = \frac{2 (- 1 - i \sqrt{3})}{2 \cdot 2}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.6.4.3

Rewrite the expression.

$x = \frac{- 1 - i \sqrt{3}}{2}$

$y = - \frac{1 - i \sqrt{3}}{2}$

$x = \frac{- 1 - i \sqrt{3}}{2}$

$y = - \frac{1 - i \sqrt{3}}{2}$

$x = \frac{- 1 - i \sqrt{3}}{2}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.7

Rewrite $- 1$ as $- 1 (1)$ .

$x = \frac{- 1 \cdot 1 - i \sqrt{3}}{2}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.8

Factor $- 1$ out of $- i \sqrt{3}$ .

$x = \frac{- 1 \cdot 1 - (i \sqrt{3})}{2}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.9

Factor $- 1$ out of $- 1 (1) - (i \sqrt{3})$ .

$x = \frac{- 1 (1 + i \sqrt{3})}{2}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 11.2.1.10

Move the negative in front of the fraction.

$x = - \frac{1 + i \sqrt{3}}{2}$

$y = - \frac{1 - i \sqrt{3}}{2}$

$x = - \frac{1 + i \sqrt{3}}{2}$

$y = - \frac{1 - i \sqrt{3}}{2}$

$x = - \frac{1 + i \sqrt{3}}{2}$

$y = - \frac{1 - i \sqrt{3}}{2}$

$x = - \frac{1 + i \sqrt{3}}{2}$

$y = - \frac{1 - i \sqrt{3}}{2}$

Step 12

Replace all occurrences of $y$ with $- \frac{1 + i \sqrt{3}}{2}$ in each equation.

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Step 12.1

Replace all occurrences of $y$ in $x = y^{2}$ with $- \frac{1 + i \sqrt{3}}{2}$ .

$x = {(- \frac{1 + i \sqrt{3}}{2})}^{2}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2

Simplify the right side.

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Step 12.2.1

Simplify ${(- \frac{1 + i \sqrt{3}}{2})}^{2}$ .

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Step 12.2.1.1

Use the power rule ${(a b)}^{n} = a^{n} b^{n}$ to distribute the exponent.

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Step 12.2.1.1.1

Apply the product rule to $- \frac{1 + i \sqrt{3}}{2}$ .

$x = {(- 1)}^{2} {(\frac{1 + i \sqrt{3}}{2})}^{2}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.1.2

Apply the product rule to $\frac{1 + i \sqrt{3}}{2}$ .

$x = {(- 1)}^{2} (\frac{{(1 + i \sqrt{3})}^{2}}{2^{2}})$

$y = - \frac{1 + i \sqrt{3}}{2}$

$x = {(- 1)}^{2} (\frac{{(1 + i \sqrt{3})}^{2}}{2^{2}})$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.2

Simplify the expression.

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Step 12.2.1.2.1

Raise $- 1$ to the power of $2$ .

$x = 1 (\frac{{(1 + i \sqrt{3})}^{2}}{2^{2}})$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.2.2

Multiply $\frac{{(1 + i \sqrt{3})}^{2}}{2^{2}}$ by $1$ .

$x = \frac{{(1 + i \sqrt{3})}^{2}}{2^{2}}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.2.3

Raise $2$ to the power of $2$ .

$x = \frac{{(1 + i \sqrt{3})}^{2}}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.2.4

Rewrite ${(1 + i \sqrt{3})}^{2}$ as $(1 + i \sqrt{3}) (1 + i \sqrt{3})$ .

$x = \frac{(1 + i \sqrt{3}) (1 + i \sqrt{3})}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

$x = \frac{(1 + i \sqrt{3}) (1 + i \sqrt{3})}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.3

Expand $(1 + i \sqrt{3}) (1 + i \sqrt{3})$ using the FOIL Method.

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Step 12.2.1.3.1

Apply the distributive property.

$x = \frac{1 (1 + i \sqrt{3}) + i \sqrt{3} (1 + i \sqrt{3})}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.3.2

Apply the distributive property.

$x = \frac{1 \cdot 1 + 1 (i \sqrt{3}) + i \sqrt{3} (1 + i \sqrt{3})}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.3.3

Apply the distributive property.

$x = \frac{1 \cdot 1 + 1 (i \sqrt{3}) + i \sqrt{3} \cdot 1 + i \sqrt{3} (i \sqrt{3})}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

$x = \frac{1 \cdot 1 + 1 (i \sqrt{3}) + i \sqrt{3} \cdot 1 + i \sqrt{3} (i \sqrt{3})}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.4

Simplify and combine like terms.

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Step 12.2.1.4.1

Simplify each term.

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Step 12.2.1.4.1.1

Multiply $1$ by $1$ .

$x = \frac{1 + 1 (i \sqrt{3}) + i \sqrt{3} \cdot 1 + i \sqrt{3} (i \sqrt{3})}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.4.1.2

Multiply $i \sqrt{3}$ by $1$ .

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} \cdot 1 + i \sqrt{3} (i \sqrt{3})}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.4.1.3

Multiply $i$ by $1$ .

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} + i \sqrt{3} (i \sqrt{3})}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.4.1.4

Multiply $i \sqrt{3} (i \sqrt{3})$ .

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Step 12.2.1.4.1.4.1

Raise $i$ to the power of $1$ .

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} + i i \sqrt{3} \sqrt{3}}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.4.1.4.2

Raise $i$ to the power of $1$ .

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} + i i \sqrt{3} \sqrt{3}}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.4.1.4.3

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} + i^{1 + 1} \sqrt{3} \sqrt{3}}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.4.1.4.4

Add $1$ and $1$ .

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} + i^{2} \sqrt{3} \sqrt{3}}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.4.1.4.5

Raise $\sqrt{3}$ to the power of $1$ .

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} + i^{2} (\sqrt{3} \sqrt{3})}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.4.1.4.6

Raise $\sqrt{3}$ to the power of $1$ .

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} + i^{2} (\sqrt{3} \sqrt{3})}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.4.1.4.7

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} + i^{2} {\sqrt{3}}^{1 + 1}}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.4.1.4.8

Add $1$ and $1$ .

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} + i^{2} {\sqrt{3}}^{2}}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} + i^{2} {\sqrt{3}}^{2}}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.4.1.5

Rewrite $i^{2}$ as $- 1$ .

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} - 1 {\sqrt{3}}^{2}}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.4.1.6

Rewrite ${\sqrt{3}}^{2}$ as $3$ .

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Step 12.2.1.4.1.6.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{3}$ as $3^{\frac{1}{2}}$ .

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} - 1 {(3^{\frac{1}{2}})}^{2}}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.4.1.6.2

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} - 1 \cdot 3^{\frac{1}{2} \cdot 2}}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.4.1.6.3

Combine $\frac{1}{2}$ and $2$ .

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} - 1 \cdot 3^{\frac{2}{2}}}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.4.1.6.4

Cancel the common factor of $2$ .

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Step 12.2.1.4.1.6.4.1

Cancel the common factor.

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} - 1 \cdot 3^{\frac{2}{2}}}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.4.1.6.4.2

Rewrite the expression.

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} - 1 \cdot 3}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} - 1 \cdot 3}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.4.1.6.5

Evaluate the exponent.

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} - 1 \cdot 3}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} - 1 \cdot 3}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.4.1.7

Multiply $- 1$ by $3$ .

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} - 3}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

$x = \frac{1 + i \sqrt{3} + i \sqrt{3} - 3}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.4.2

Subtract $3$ from $1$ .

$x = \frac{i \sqrt{3} + i \sqrt{3} - 2}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.4.3

Add $i \sqrt{3}$ and $i \sqrt{3}$ .

$x = \frac{2 i \sqrt{3} - 2}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

$x = \frac{2 i \sqrt{3} - 2}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.5

Reorder $2 i \sqrt{3}$ and $- 2$ .

$x = \frac{- 2 + 2 i \sqrt{3}}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.6

Cancel the common factor of $- 2 + 2 i \sqrt{3}$ and $4$ .

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Step 12.2.1.6.1

Factor $2$ out of $- 2$ .

$x = \frac{2 \cdot - 1 + 2 i \sqrt{3}}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.6.2

Factor $2$ out of $2 i \sqrt{3}$ .

$x = \frac{2 \cdot - 1 + 2 (i \sqrt{3})}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.6.3

Factor $2$ out of $2 \cdot - 1 + 2 (i \sqrt{3})$ .

$x = \frac{2 \cdot (- 1 + i \sqrt{3})}{4}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.6.4

Cancel the common factors.

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Step 12.2.1.6.4.1

Factor $2$ out of $4$ .

$x = \frac{2 \cdot (- 1 + i \sqrt{3})}{2 (2)}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.6.4.2

Cancel the common factor.

$x = \frac{2 \cdot (- 1 + i \sqrt{3})}{2 \cdot 2}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.6.4.3

Rewrite the expression.

$x = \frac{- 1 + i \sqrt{3}}{2}$

$y = - \frac{1 + i \sqrt{3}}{2}$

$x = \frac{- 1 + i \sqrt{3}}{2}$

$y = - \frac{1 + i \sqrt{3}}{2}$

$x = \frac{- 1 + i \sqrt{3}}{2}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.7

Rewrite $- 1$ as $- 1 (1)$ .

$x = \frac{- 1 \cdot 1 + i \sqrt{3}}{2}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.8

Factor $- 1$ out of $i \sqrt{3}$ .

$x = \frac{- 1 \cdot 1 - (- i \sqrt{3})}{2}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.9

Factor $- 1$ out of $- 1 (1) - (- i \sqrt{3})$ .

$x = \frac{- 1 (1 - i \sqrt{3})}{2}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 12.2.1.10

Move the negative in front of the fraction.

$x = - \frac{1 - i \sqrt{3}}{2}$

$y = - \frac{1 + i \sqrt{3}}{2}$

$x = - \frac{1 - i \sqrt{3}}{2}$

$y = - \frac{1 + i \sqrt{3}}{2}$

$x = - \frac{1 - i \sqrt{3}}{2}$

$y = - \frac{1 + i \sqrt{3}}{2}$

$x = - \frac{1 - i \sqrt{3}}{2}$

$y = - \frac{1 + i \sqrt{3}}{2}$

Step 13

List all of the solutions.

$x = 0, y = 0$

$x = 1, y = 1$

$x = - \frac{1 + i \sqrt{3}}{2}, y = - \frac{1 - i \sqrt{3}}{2}$

$x = - \frac{1 - i \sqrt{3}}{2}, y = - \frac{1 + i \sqrt{3}}{2}$

Step 14