Precalculus Examples

$\frac{x^{2}}{36} + \frac{y^{2}}{64} = 1$ , $\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1

Solve for $x$ in $\frac{x^{2}}{36} + \frac{y^{2}}{64} = 1$ .

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Step 1.1

Subtract $\frac{y^{2}}{64}$ from both sides of the equation.

$\frac{x^{2}}{36} = 1 - \frac{y^{2}}{64}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.2

Multiply both sides of the equation by $36$ .

$36 (\frac{x^{2}}{36}) = 36 (1 - \frac{y^{2}}{64})$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.3

Simplify both sides of the equation.

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Step 1.3.1

Simplify the left side.

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Step 1.3.1.1

Cancel the common factor of $36$ .

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Step 1.3.1.1.1

Cancel the common factor.

$36 (\frac{x^{2}}{36}) = 36 (1 - \frac{y^{2}}{64})$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.3.1.1.2

Rewrite the expression.

$x^{2} = 36 (1 - \frac{y^{2}}{64})$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

$x^{2} = 36 (1 - \frac{y^{2}}{64})$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

$x^{2} = 36 (1 - \frac{y^{2}}{64})$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.3.2

Simplify the right side.

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Step 1.3.2.1

Simplify $36 (1 - \frac{y^{2}}{64})$ .

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Step 1.3.2.1.1

Apply the distributive property.

$x^{2} = 36 \cdot 1 + 36 (- \frac{y^{2}}{64})$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.3.2.1.2

Multiply $36$ by $1$ .

$x^{2} = 36 + 36 (- \frac{y^{2}}{64})$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.3.2.1.3

Cancel the common factor of $4$ .

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Step 1.3.2.1.3.1

Move the leading negative in $- \frac{y^{2}}{64}$ into the numerator.

$x^{2} = 36 + 36 (\frac{- y^{2}}{64})$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.3.2.1.3.2

Factor $4$ out of $36$ .

$x^{2} = 36 + 4 (9) (\frac{- y^{2}}{64})$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.3.2.1.3.3

Factor $4$ out of $64$ .

$x^{2} = 36 + 4 \cdot (9 (\frac{- y^{2}}{4 \cdot 16}))$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.3.2.1.3.4

Cancel the common factor.

$x^{2} = 36 + 4 \cdot (9 (\frac{- y^{2}}{4 \cdot 16}))$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.3.2.1.3.5

Rewrite the expression.

$x^{2} = 36 + 9 (\frac{- y^{2}}{16})$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

$x^{2} = 36 + 9 (\frac{- y^{2}}{16})$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.3.2.1.4

Combine $9$ and $\frac{- y^{2}}{16}$ .

$x^{2} = 36 + \frac{9 (- y^{2})}{16}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.3.2.1.5

Simplify the expression.

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Step 1.3.2.1.5.1

Multiply $- 1$ by $9$ .

$x^{2} = 36 + \frac{- 9 y^{2}}{16}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.3.2.1.5.2

Move the negative in front of the fraction.

$x^{2} = 36 - \frac{9 y^{2}}{16}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

$x^{2} = 36 - \frac{9 y^{2}}{16}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

$x^{2} = 36 - \frac{9 y^{2}}{16}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

$x^{2} = 36 - \frac{9 y^{2}}{16}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

$x^{2} = 36 - \frac{9 y^{2}}{16}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.4

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{36 - \frac{9 y^{2}}{16}}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.5

Simplify $\pm \sqrt{36 - \frac{9 y^{2}}{16}}$ .

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Step 1.5.1

Write the expression using exponents.

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Step 1.5.1.1

Rewrite $36$ as $6^{2}$ .

$x = \pm \sqrt{6^{2} - \frac{9 y^{2}}{16}}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.5.1.2

Rewrite $\frac{9 y^{2}}{16}$ as ${(\frac{3 y}{4})}^{2}$ .

$x = \pm \sqrt{6^{2} - {(\frac{3 y}{4})}^{2}}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

$x = \pm \sqrt{6^{2} - {(\frac{3 y}{4})}^{2}}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.5.2

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 6$ and $b = \frac{3 y}{4}$ .

$x = \pm \sqrt{(6 + \frac{3 y}{4}) (6 - \frac{3 y}{4})}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.5.3

To write $6$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$x = \pm \sqrt{(6 \cdot \frac{4}{4} + \frac{3 y}{4}) (6 - \frac{3 y}{4})}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.5.4

Simplify terms.

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Step 1.5.4.1

Combine $6$ and $\frac{4}{4}$ .

$x = \pm \sqrt{(\frac{6 \cdot 4}{4} + \frac{3 y}{4}) (6 - \frac{3 y}{4})}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.5.4.2

Combine the numerators over the common denominator.

$x = \pm \sqrt{\frac{6 \cdot 4 + 3 y}{4} \cdot (6 - \frac{3 y}{4})}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

$x = \pm \sqrt{\frac{6 \cdot 4 + 3 y}{4} \cdot (6 - \frac{3 y}{4})}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.5.5

Simplify the numerator.

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Step 1.5.5.1

Factor $3$ out of $6 \cdot 4 + 3 y$ .

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Step 1.5.5.1.1

Factor $3$ out of $6 \cdot 4$ .

$x = \pm \sqrt{\frac{3 (2 \cdot 4) + 3 y}{4} \cdot (6 - \frac{3 y}{4})}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.5.5.1.2

Factor $3$ out of $3 y$ .

$x = \pm \sqrt{\frac{3 (2 \cdot 4) + 3 (y)}{4} \cdot (6 - \frac{3 y}{4})}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.5.5.1.3

Factor $3$ out of $3 (2 \cdot 4) + 3 (y)$ .

$x = \pm \sqrt{\frac{3 (2 \cdot 4 + y)}{4} \cdot (6 - \frac{3 y}{4})}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

$x = \pm \sqrt{\frac{3 (2 \cdot 4 + y)}{4} \cdot (6 - \frac{3 y}{4})}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.5.5.2

Multiply $2$ by $4$ .

$x = \pm \sqrt{\frac{3 (8 + y)}{4} \cdot (6 - \frac{3 y}{4})}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

$x = \pm \sqrt{\frac{3 (8 + y)}{4} \cdot (6 - \frac{3 y}{4})}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.5.6

To write $6$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$x = \pm \sqrt{\frac{3 (8 + y)}{4} \cdot (6 \cdot \frac{4}{4} - \frac{3 y}{4})}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.5.7

Simplify terms.

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Step 1.5.7.1

Combine $6$ and $\frac{4}{4}$ .

$x = \pm \sqrt{\frac{3 (8 + y)}{4} \cdot (\frac{6 \cdot 4}{4} - \frac{3 y}{4})}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.5.7.2

Combine the numerators over the common denominator.

$x = \pm \sqrt{\frac{3 (8 + y)}{4} \cdot \frac{6 \cdot 4 - 3 y}{4}}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

$x = \pm \sqrt{\frac{3 (8 + y)}{4} \cdot \frac{6 \cdot 4 - 3 y}{4}}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.5.8

Simplify the numerator.

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Step 1.5.8.1

Factor $3$ out of $6 \cdot 4 - 3 y$ .

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Step 1.5.8.1.1

Factor $3$ out of $6 \cdot 4$ .

$x = \pm \sqrt{\frac{3 (8 + y)}{4} \cdot \frac{3 (2 \cdot 4) - 3 y}{4}}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.5.8.1.2

Factor $3$ out of $- 3 y$ .

$x = \pm \sqrt{\frac{3 (8 + y)}{4} \cdot \frac{3 (2 \cdot 4) + 3 (- y)}{4}}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.5.8.1.3

Factor $3$ out of $3 (2 \cdot 4) + 3 (- y)$ .

$x = \pm \sqrt{\frac{3 (8 + y)}{4} \cdot \frac{3 (2 \cdot 4 - y)}{4}}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

$x = \pm \sqrt{\frac{3 (8 + y)}{4} \cdot \frac{3 (2 \cdot 4 - y)}{4}}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.5.8.2

Multiply $2$ by $4$ .

$x = \pm \sqrt{\frac{3 (8 + y)}{4} \cdot \frac{3 (8 - y)}{4}}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

$x = \pm \sqrt{\frac{3 (8 + y)}{4} \cdot \frac{3 (8 - y)}{4}}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.5.9

Combine fractions.

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Step 1.5.9.1

Multiply $\frac{3 (8 + y)}{4}$ by $\frac{3 (8 - y)}{4}$ .

$x = \pm \sqrt{\frac{3 (8 + y) (3 (8 - y))}{4 \cdot 4}}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.5.9.2

Multiply.

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Step 1.5.9.2.1

Multiply $3$ by $3$ .

$x = \pm \sqrt{\frac{9 (8 + y) (8 - y)}{4 \cdot 4}}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.5.9.2.2

Multiply $4$ by $4$ .

$x = \pm \sqrt{\frac{9 (8 + y) (8 - y)}{16}}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

$x = \pm \sqrt{\frac{9 (8 + y) (8 - y)}{16}}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

$x = \pm \sqrt{\frac{9 (8 + y) (8 - y)}{16}}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.5.10

Rewrite $\frac{9 (8 + y) (8 - y)}{16}$ as ${(\frac{3}{4})}^{2} ((8 + y) (8 - y))$ .

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Step 1.5.10.1

Factor the perfect power $3^{2}$ out of $9 (8 + y) (8 - y)$ .

$x = \pm \sqrt{\frac{3^{2} ((8 + y) (8 - y))}{16}}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.5.10.2

Factor the perfect power $4^{2}$ out of $16$ .

$x = \pm \sqrt{\frac{3^{2} ((8 + y) (8 - y))}{4^{2} \cdot 1}}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.5.10.3

Rearrange the fraction $\frac{3^{2} ((8 + y) (8 - y))}{4^{2} \cdot 1}$ .

$x = \pm \sqrt{{(\frac{3}{4})}^{2} ((8 + y) (8 - y))}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

$x = \pm \sqrt{{(\frac{3}{4})}^{2} ((8 + y) (8 - y))}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.5.11

Pull terms out from under the radical.

$x = \pm \frac{3}{4} \cdot \sqrt{(8 + y) (8 - y)}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.5.12

Combine $\frac{3}{4}$ and $\sqrt{(8 + y) (8 - y)}$ .

$x = \pm \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

$x = \pm \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.6

The complete solution is the result of both the positive and negative portions of the solution.

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Step 1.6.1

First, use the positive value of the $\pm$ to find the first solution.

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.6.2

Next, use the negative value of the $\pm$ to find the second solution.

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 1.6.3

The complete solution is the result of both the positive and negative portions of the solution.

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$

Step 2

Solve the system $x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}, \frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$ .

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Step 2.1

Replace all occurrences of $x$ with $\frac{3 \sqrt{(8 + y) (8 - y)}}{4}$ in each equation.

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Step 2.1.1

Replace all occurrences of $x$ in $\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$ with $\frac{3 \sqrt{(8 + y) (8 - y)}}{4}$ .

$\frac{{(\frac{3 \sqrt{(8 + y) (8 - y)}}{4})}^{2}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2

Simplify the left side.

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Step 2.1.2.1

Simplify $\frac{{(\frac{3 \sqrt{(8 + y) (8 - y)}}{4})}^{2}}{36} - \frac{y^{2}}{64}$ .

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Step 2.1.2.1.1

Simplify each term.

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Step 2.1.2.1.1.1

Simplify the numerator.

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Step 2.1.2.1.1.1.1

Apply the product rule to $\frac{3 \sqrt{(8 + y) (8 - y)}}{4}$ .

$\frac{\frac{{(3 \sqrt{(8 + y) (8 - y)})}^{2}}{4^{2}}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.1.1.2

Simplify the numerator.

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Step 2.1.2.1.1.1.2.1

Apply the product rule to $3 \sqrt{(8 + y) (8 - y)}$ .

$\frac{\frac{3^{2} {\sqrt{(8 + y) (8 - y)}}^{2}}{4^{2}}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.1.1.2.2

Raise $3$ to the power of $2$ .

$\frac{\frac{9 {\sqrt{(8 + y) (8 - y)}}^{2}}{4^{2}}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.1.1.2.3

Rewrite ${\sqrt{(8 + y) (8 - y)}}^{2}$ as $(8 + y) (8 - y)$ .

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Step 2.1.2.1.1.1.2.3.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{(8 + y) (8 - y)}$ as ${((8 + y) (8 - y))}^{\frac{1}{2}}$ .

$\frac{\frac{9 {({((8 + y) (8 - y))}^{\frac{1}{2}})}^{2}}{4^{2}}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.1.1.2.3.2

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{\frac{9 {((8 + y) (8 - y))}^{\frac{1}{2} \cdot 2}}{4^{2}}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.1.1.2.3.3

Combine $\frac{1}{2}$ and $2$ .

$\frac{\frac{9 {((8 + y) (8 - y))}^{\frac{2}{2}}}{4^{2}}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.1.1.2.3.4

Cancel the common factor of $2$ .

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Step 2.1.2.1.1.1.2.3.4.1

Cancel the common factor.

$\frac{\frac{9 {((8 + y) (8 - y))}^{\frac{2}{2}}}{4^{2}}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.1.1.2.3.4.2

Rewrite the expression.

$\frac{\frac{9 ((8 + y) (8 - y))}{4^{2}}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{\frac{9 ((8 + y) (8 - y))}{4^{2}}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.1.1.2.3.5

Simplify.

$\frac{\frac{9 ((8 + y) (8 - y))}{4^{2}}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{\frac{9 ((8 + y) (8 - y))}{4^{2}}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.1.1.2.4

Expand $(8 + y) (8 - y)$ using the FOIL Method.

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Step 2.1.2.1.1.1.2.4.1

Apply the distributive property.

$\frac{\frac{9 (8 (8 - y) + y (8 - y))}{4^{2}}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.1.1.2.4.2

Apply the distributive property.

$\frac{\frac{9 (8 \cdot 8 + 8 (- y) + y (8 - y))}{4^{2}}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.1.1.2.4.3

Apply the distributive property.

$\frac{\frac{9 (8 \cdot 8 + 8 (- y) + y \cdot 8 + y (- y))}{4^{2}}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{\frac{9 (8 \cdot 8 + 8 (- y) + y \cdot 8 + y (- y))}{4^{2}}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.1.1.2.5

Simplify and combine like terms.

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Step 2.1.2.1.1.1.2.5.1

Simplify each term.

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Step 2.1.2.1.1.1.2.5.1.1

Multiply $8$ by $8$ .

$\frac{\frac{9 (64 + 8 (- y) + y \cdot 8 + y (- y))}{4^{2}}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.1.1.2.5.1.2

Multiply $- 1$ by $8$ .

$\frac{\frac{9 (64 - 8 y + y \cdot 8 + y (- y))}{4^{2}}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.1.1.2.5.1.3

Move $8$ to the left of $y$ .

$\frac{\frac{9 (64 - 8 y + 8 \cdot y + y (- y))}{4^{2}}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.1.1.2.5.1.4

Rewrite using the commutative property of multiplication.

$\frac{\frac{9 (64 - 8 y + 8 y - y \cdot y)}{4^{2}}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.1.1.2.5.1.5

Multiply $y$ by $y$ by adding the exponents.

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Step 2.1.2.1.1.1.2.5.1.5.1

Move $y$ .

$\frac{\frac{9 (64 - 8 y + 8 y - (y \cdot y))}{4^{2}}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.1.1.2.5.1.5.2

Multiply $y$ by $y$ .

$\frac{\frac{9 (64 - 8 y + 8 y - y^{2})}{4^{2}}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{\frac{9 (64 - 8 y + 8 y - y^{2})}{4^{2}}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{\frac{9 (64 - 8 y + 8 y - y^{2})}{4^{2}}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.1.1.2.5.2

Add $- 8 y$ and $8 y$ .

$\frac{\frac{9 (64 + 0 - y^{2})}{4^{2}}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.1.1.2.5.3

Add $64$ and $0$ .

$\frac{\frac{9 (64 - y^{2})}{4^{2}}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{\frac{9 (64 - y^{2})}{4^{2}}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.1.1.2.6

Rewrite $64$ as $8^{2}$ .

$\frac{\frac{9 (8^{2} - y^{2})}{4^{2}}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.1.1.2.7

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 8$ and $b = y$ .

$\frac{\frac{9 (8 + y) (8 - y)}{4^{2}}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{\frac{9 (8 + y) (8 - y)}{4^{2}}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.1.1.3

Raise $4$ to the power of $2$ .

$\frac{\frac{9 (8 + y) (8 - y)}{16}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{\frac{9 (8 + y) (8 - y)}{16}}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.1.2

Multiply the numerator by the reciprocal of the denominator.

$\frac{9 (8 + y) (8 - y)}{16} \cdot \frac{1}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.1.3

Cancel the common factor of $9$ .

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Step 2.1.2.1.1.3.1

Factor $9$ out of $9 (8 + y) (8 - y)$ .

$\frac{9 ((8 + y) (8 - y))}{16} \cdot \frac{1}{36} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.1.3.2

Factor $9$ out of $36$ .

$\frac{9 ((8 + y) (8 - y))}{16} \cdot \frac{1}{9 (4)} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.1.3.3

Cancel the common factor.

$\frac{9 ((8 + y) (8 - y))}{16} \cdot \frac{1}{9 \cdot 4} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.1.3.4

Rewrite the expression.

$\frac{(8 + y) (8 - y)}{16} \cdot \frac{1}{4} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{(8 + y) (8 - y)}{16} \cdot \frac{1}{4} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.1.4

Multiply $\frac{(8 + y) (8 - y)}{16}$ by $\frac{1}{4}$ .

$\frac{(8 + y) (8 - y)}{16 \cdot 4} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.1.5

Multiply $16$ by $4$ .

$\frac{(8 + y) (8 - y)}{64} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{(8 + y) (8 - y)}{64} - \frac{y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.2

Combine the numerators over the common denominator.

$\frac{(8 + y) (8 - y) - y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.3

Simplify each term.

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Step 2.1.2.1.3.1

Expand $(8 + y) (8 - y)$ using the FOIL Method.

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Step 2.1.2.1.3.1.1

Apply the distributive property.

$\frac{8 (8 - y) + y (8 - y) - y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.3.1.2

Apply the distributive property.

$\frac{8 \cdot 8 + 8 (- y) + y (8 - y) - y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.3.1.3

Apply the distributive property.

$\frac{8 \cdot 8 + 8 (- y) + y \cdot 8 + y (- y) - y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{8 \cdot 8 + 8 (- y) + y \cdot 8 + y (- y) - y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.3.2

Simplify and combine like terms.

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Step 2.1.2.1.3.2.1

Simplify each term.

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Step 2.1.2.1.3.2.1.1

Multiply $8$ by $8$ .

$\frac{64 + 8 (- y) + y \cdot 8 + y (- y) - y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.3.2.1.2

Multiply $- 1$ by $8$ .

$\frac{64 - 8 y + y \cdot 8 + y (- y) - y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.3.2.1.3

Move $8$ to the left of $y$ .

$\frac{64 - 8 y + 8 \cdot y + y (- y) - y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.3.2.1.4

Rewrite using the commutative property of multiplication.

$\frac{64 - 8 y + 8 y - y \cdot y - y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.3.2.1.5

Multiply $y$ by $y$ by adding the exponents.

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Step 2.1.2.1.3.2.1.5.1

Move $y$ .

$\frac{64 - 8 y + 8 y - (y \cdot y) - y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.3.2.1.5.2

Multiply $y$ by $y$ .

$\frac{64 - 8 y + 8 y - y^{2} - y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{64 - 8 y + 8 y - y^{2} - y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{64 - 8 y + 8 y - y^{2} - y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.3.2.2

Add $- 8 y$ and $8 y$ .

$\frac{64 + 0 - y^{2} - y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.3.2.3

Add $64$ and $0$ .

$\frac{64 - y^{2} - y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{64 - y^{2} - y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{64 - y^{2} - y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.4

Simplify terms.

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Step 2.1.2.1.4.1

Subtract $y^{2}$ from $- y^{2}$ .

$\frac{64 - 2 y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.4.2

Cancel the common factor of $64 - 2 y^{2}$ and $64$ .

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Step 2.1.2.1.4.2.1

Factor $2$ out of $64$ .

$\frac{2 (32) - 2 y^{2}}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.4.2.2

Factor $2$ out of $- 2 y^{2}$ .

$\frac{2 (32) + 2 (- y^{2})}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.4.2.3

Factor $2$ out of $2 (32) + 2 (- y^{2})$ .

$\frac{2 (32 - y^{2})}{64} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.4.2.4

Cancel the common factors.

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Step 2.1.2.1.4.2.4.1

Factor $2$ out of $64$ .

$\frac{2 (32 - y^{2})}{2 \cdot 32} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.4.2.4.2

Cancel the common factor.

$\frac{2 (32 - y^{2})}{2 \cdot 32} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.1.2.1.4.2.4.3

Rewrite the expression.

$\frac{32 - y^{2}}{32} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{32 - y^{2}}{32} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{32 - y^{2}}{32} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{32 - y^{2}}{32} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{32 - y^{2}}{32} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{32 - y^{2}}{32} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{32 - y^{2}}{32} = 1$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.2

Solve for $y$ in $\frac{32 - y^{2}}{32} = 1$ .

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Step 2.2.1

Multiply both sides by $32$ .

$\frac{32 - y^{2}}{32} \cdot 32 = 1 \cdot 32$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.2.2

Simplify.

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Step 2.2.2.1

Simplify the left side.

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Step 2.2.2.1.1

Simplify $\frac{32 - y^{2}}{32} \cdot 32$ .

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Step 2.2.2.1.1.1

Cancel the common factor of $32$ .

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Step 2.2.2.1.1.1.1

Cancel the common factor.

$\frac{32 - y^{2}}{32} \cdot 32 = 1 \cdot 32$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.2.2.1.1.1.2

Rewrite the expression.

$32 - y^{2} = 1 \cdot 32$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$32 - y^{2} = 1 \cdot 32$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.2.2.1.1.2

Reorder $32$ and $- y^{2}$ .

$- y^{2} + 32 = 1 \cdot 32$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$- y^{2} + 32 = 1 \cdot 32$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$- y^{2} + 32 = 1 \cdot 32$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.2.2.2

Simplify the right side.

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Step 2.2.2.2.1

Multiply $32$ by $1$ .

$- y^{2} + 32 = 32$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$- y^{2} + 32 = 32$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$- y^{2} + 32 = 32$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.2.3

Solve for $y$ .

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Step 2.2.3.1

Move all terms not containing $y$ to the right side of the equation.

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Step 2.2.3.1.1

Subtract $32$ from both sides of the equation.

$- y^{2} = 32 - 32$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.2.3.1.2

Subtract $32$ from $32$ .

$- y^{2} = 0$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$- y^{2} = 0$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.2.3.2

Divide each term in $- y^{2} = 0$ by $- 1$ and simplify.

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Step 2.2.3.2.1

Divide each term in $- y^{2} = 0$ by $- 1$ .

$\frac{- y^{2}}{- 1} = \frac{0}{- 1}$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.2.3.2.2

Simplify the left side.

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Step 2.2.3.2.2.1

Dividing two negative values results in a positive value.

$\frac{y^{2}}{1} = \frac{0}{- 1}$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.2.3.2.2.2

Divide $y^{2}$ by $1$ .

$y^{2} = \frac{0}{- 1}$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$y^{2} = \frac{0}{- 1}$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.2.3.2.3

Simplify the right side.

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Step 2.2.3.2.3.1

Divide $0$ by $- 1$ .

$y^{2} = 0$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$y^{2} = 0$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$y^{2} = 0$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.2.3.3

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$y = \pm \sqrt{0}$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.2.3.4

Simplify $\pm \sqrt{0}$ .

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Step 2.2.3.4.1

Rewrite $0$ as $0^{2}$ .

$y = \pm \sqrt{0^{2}}$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.2.3.4.2

Pull terms out from under the radical, assuming positive real numbers.

$y = \pm 0$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.2.3.4.3

Plus or minus $0$ is $0$ .

$y = 0$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$y = 0$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$y = 0$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$y = 0$

$x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 2.3

Replace all occurrences of $y$ with $0$ in each equation.

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Step 2.3.1

Replace all occurrences of $y$ in $x = \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$ with $0$ .

$x = \frac{3 \sqrt{(8 + 0) (8 - (0))}}{4}$

$y = 0$

Step 2.3.2

Simplify $x = \frac{3 \sqrt{(8 + 0) (8 - (0))}}{4}$ .

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Step 2.3.2.1

Simplify the left side.

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Step 2.3.2.1.1

Remove parentheses.

$x = \frac{3 \sqrt{(8 + 0) (8 - (0))}}{4}$

$y = 0$

$x = \frac{3 \sqrt{(8 + 0) (8 - (0))}}{4}$

$y = 0$

Step 2.3.2.2

Simplify the right side.

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Step 2.3.2.2.1

Simplify $\frac{3 \sqrt{(8 + 0) (8 - (0))}}{4}$ .

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Step 2.3.2.2.1.1

Simplify the numerator.

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Step 2.3.2.2.1.1.1

Add $8$ and $0$ .

$x = \frac{3 \sqrt{8 (8 - (0))}}{4}$

$y = 0$

Step 2.3.2.2.1.1.2

Multiply $- 1$ by $0$ .

$x = \frac{3 \sqrt{8 (8 + 0)}}{4}$

$y = 0$

Step 2.3.2.2.1.1.3

Add $8$ and $0$ .

$x = \frac{3 \sqrt{8 \cdot 8}}{4}$

$y = 0$

Step 2.3.2.2.1.1.4

Multiply $8$ by $8$ .

$x = \frac{3 \sqrt{64}}{4}$

$y = 0$

Step 2.3.2.2.1.1.5

Rewrite $64$ as $8^{2}$ .

$x = \frac{3 \sqrt{8^{2}}}{4}$

$y = 0$

Step 2.3.2.2.1.1.6

Pull terms out from under the radical, assuming positive real numbers.

$x = \frac{3 \cdot 8}{4}$

$y = 0$

$x = \frac{3 \cdot 8}{4}$

$y = 0$

Step 2.3.2.2.1.2

Simplify the expression.

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Step 2.3.2.2.1.2.1

Multiply $3$ by $8$ .

$x = \frac{24}{4}$

$y = 0$

Step 2.3.2.2.1.2.2

Divide $24$ by $4$ .

$x = 6$

$y = 0$

$x = 6$

$y = 0$

$x = 6$

$y = 0$

$x = 6$

$y = 0$

$x = 6$

$y = 0$

$x = 6$

$y = 0$

$x = 6$

$y = 0$

Step 3

Solve the system $x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}, \frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$ .

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Step 3.1

Replace all occurrences of $x$ with $- \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$ in each equation.

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Step 3.1.1

Replace all occurrences of $x$ in $\frac{x^{2}}{36} - \frac{y^{2}}{64} = 1$ with $- \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$ .

$\frac{{(- \frac{3 \sqrt{(8 + y) (8 - y)}}{4})}^{2}}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2

Simplify the left side.

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Step 3.1.2.1

Simplify $\frac{{(- \frac{3 \sqrt{(8 + y) (8 - y)}}{4})}^{2}}{36} - \frac{y^{2}}{64}$ .

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Step 3.1.2.1.1

Simplify each term.

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Step 3.1.2.1.1.1

Simplify the numerator.

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Step 3.1.2.1.1.1.1

Apply the product rule to $- \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$ .

$\frac{{(- 1)}^{2} {(\frac{3 \sqrt{(8 + y) (8 - y)}}{4})}^{2}}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.1.2

Raise $- 1$ to the power of $2$ .

$\frac{1 {(\frac{3 \sqrt{(8 + y) (8 - y)}}{4})}^{2}}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.1.3

Use the power rule ${(a b)}^{n} = a^{n} b^{n}$ to distribute the exponent.

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Step 3.1.2.1.1.1.3.1

Apply the product rule to $\frac{3 \sqrt{(8 + y) (8 - y)}}{4}$ .

$\frac{1 (\frac{{(3 \sqrt{(8 + y) (8 - y)})}^{2}}{4^{2}})}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.1.3.2

Apply the product rule to $3 \sqrt{(8 + y) (8 - y)}$ .

$\frac{1 (\frac{3^{2} {\sqrt{(8 + y) (8 - y)}}^{2}}{4^{2}})}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{1 (\frac{3^{2} {\sqrt{(8 + y) (8 - y)}}^{2}}{4^{2}})}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.1.4

Simplify the numerator.

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Step 3.1.2.1.1.1.4.1

Raise $3$ to the power of $2$ .

$\frac{1 (\frac{9 {\sqrt{(8 + y) (8 - y)}}^{2}}{4^{2}})}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.1.4.2

Rewrite ${\sqrt{(8 + y) (8 - y)}}^{2}$ as $(8 + y) (8 - y)$ .

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Step 3.1.2.1.1.1.4.2.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{(8 + y) (8 - y)}$ as ${((8 + y) (8 - y))}^{\frac{1}{2}}$ .

$\frac{1 (\frac{9 {({((8 + y) (8 - y))}^{\frac{1}{2}})}^{2}}{4^{2}})}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.1.4.2.2

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{1 (\frac{9 {((8 + y) (8 - y))}^{\frac{1}{2} \cdot 2}}{4^{2}})}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.1.4.2.3

Combine $\frac{1}{2}$ and $2$ .

$\frac{1 (\frac{9 {((8 + y) (8 - y))}^{\frac{2}{2}}}{4^{2}})}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.1.4.2.4

Cancel the common factor of $2$ .

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Step 3.1.2.1.1.1.4.2.4.1

Cancel the common factor.

$\frac{1 (\frac{9 {((8 + y) (8 - y))}^{\frac{2}{2}}}{4^{2}})}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.1.4.2.4.2

Rewrite the expression.

$\frac{1 (\frac{9 ((8 + y) (8 - y))}{4^{2}})}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{1 (\frac{9 ((8 + y) (8 - y))}{4^{2}})}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.1.4.2.5

Simplify.

$\frac{1 (\frac{9 ((8 + y) (8 - y))}{4^{2}})}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{1 (\frac{9 ((8 + y) (8 - y))}{4^{2}})}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.1.4.3

Expand $(8 + y) (8 - y)$ using the FOIL Method.

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Step 3.1.2.1.1.1.4.3.1

Apply the distributive property.

$\frac{1 (\frac{9 (8 (8 - y) + y (8 - y))}{4^{2}})}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.1.4.3.2

Apply the distributive property.

$\frac{1 (\frac{9 (8 \cdot 8 + 8 (- y) + y (8 - y))}{4^{2}})}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.1.4.3.3

Apply the distributive property.

$\frac{1 (\frac{9 (8 \cdot 8 + 8 (- y) + y \cdot 8 + y (- y))}{4^{2}})}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{1 (\frac{9 (8 \cdot 8 + 8 (- y) + y \cdot 8 + y (- y))}{4^{2}})}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.1.4.4

Simplify and combine like terms.

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Step 3.1.2.1.1.1.4.4.1

Simplify each term.

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Step 3.1.2.1.1.1.4.4.1.1

Multiply $8$ by $8$ .

$\frac{1 (\frac{9 (64 + 8 (- y) + y \cdot 8 + y (- y))}{4^{2}})}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.1.4.4.1.2

Multiply $- 1$ by $8$ .

$\frac{1 (\frac{9 (64 - 8 y + y \cdot 8 + y (- y))}{4^{2}})}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.1.4.4.1.3

Move $8$ to the left of $y$ .

$\frac{1 (\frac{9 (64 - 8 y + 8 \cdot y + y (- y))}{4^{2}})}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.1.4.4.1.4

Rewrite using the commutative property of multiplication.

$\frac{1 (\frac{9 (64 - 8 y + 8 y - y \cdot y)}{4^{2}})}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.1.4.4.1.5

Multiply $y$ by $y$ by adding the exponents.

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Step 3.1.2.1.1.1.4.4.1.5.1

Move $y$ .

$\frac{1 (\frac{9 (64 - 8 y + 8 y - (y \cdot y))}{4^{2}})}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.1.4.4.1.5.2

Multiply $y$ by $y$ .

$\frac{1 (\frac{9 (64 - 8 y + 8 y - y^{2})}{4^{2}})}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{1 (\frac{9 (64 - 8 y + 8 y - y^{2})}{4^{2}})}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{1 (\frac{9 (64 - 8 y + 8 y - y^{2})}{4^{2}})}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.1.4.4.2

Add $- 8 y$ and $8 y$ .

$\frac{1 (\frac{9 (64 + 0 - y^{2})}{4^{2}})}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.1.4.4.3

Add $64$ and $0$ .

$\frac{1 (\frac{9 (64 - y^{2})}{4^{2}})}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{1 (\frac{9 (64 - y^{2})}{4^{2}})}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.1.4.5

Rewrite $64$ as $8^{2}$ .

$\frac{1 (\frac{9 (8^{2} - y^{2})}{4^{2}})}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.1.4.6

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 8$ and $b = y$ .

$\frac{1 (\frac{9 (8 + y) (8 - y)}{4^{2}})}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{1 (\frac{9 (8 + y) (8 - y)}{4^{2}})}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.1.5

Raise $4$ to the power of $2$ .

$\frac{1 (\frac{9 (8 + y) (8 - y)}{16})}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.1.6

Multiply $\frac{9 (8 + y) (8 - y)}{16}$ by $1$ .

$\frac{\frac{9 (8 + y) (8 - y)}{16}}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{\frac{9 (8 + y) (8 - y)}{16}}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.2

Multiply the numerator by the reciprocal of the denominator.

$\frac{9 (8 + y) (8 - y)}{16} \cdot \frac{1}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.3

Cancel the common factor of $9$ .

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Step 3.1.2.1.1.3.1

Factor $9$ out of $9 (8 + y) (8 - y)$ .

$\frac{9 ((8 + y) (8 - y))}{16} \cdot \frac{1}{36} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.3.2

Factor $9$ out of $36$ .

$\frac{9 ((8 + y) (8 - y))}{16} \cdot \frac{1}{9 (4)} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.3.3

Cancel the common factor.

$\frac{9 ((8 + y) (8 - y))}{16} \cdot \frac{1}{9 \cdot 4} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.3.4

Rewrite the expression.

$\frac{(8 + y) (8 - y)}{16} \cdot \frac{1}{4} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{(8 + y) (8 - y)}{16} \cdot \frac{1}{4} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.4

Multiply $\frac{(8 + y) (8 - y)}{16}$ by $\frac{1}{4}$ .

$\frac{(8 + y) (8 - y)}{16 \cdot 4} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.1.5

Multiply $16$ by $4$ .

$\frac{(8 + y) (8 - y)}{64} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{(8 + y) (8 - y)}{64} - \frac{y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.2

Combine the numerators over the common denominator.

$\frac{(8 + y) (8 - y) - y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.3

Simplify each term.

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Step 3.1.2.1.3.1

Expand $(8 + y) (8 - y)$ using the FOIL Method.

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Step 3.1.2.1.3.1.1

Apply the distributive property.

$\frac{8 (8 - y) + y (8 - y) - y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.3.1.2

Apply the distributive property.

$\frac{8 \cdot 8 + 8 (- y) + y (8 - y) - y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.3.1.3

Apply the distributive property.

$\frac{8 \cdot 8 + 8 (- y) + y \cdot 8 + y (- y) - y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{8 \cdot 8 + 8 (- y) + y \cdot 8 + y (- y) - y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.3.2

Simplify and combine like terms.

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Step 3.1.2.1.3.2.1

Simplify each term.

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Step 3.1.2.1.3.2.1.1

Multiply $8$ by $8$ .

$\frac{64 + 8 (- y) + y \cdot 8 + y (- y) - y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.3.2.1.2

Multiply $- 1$ by $8$ .

$\frac{64 - 8 y + y \cdot 8 + y (- y) - y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.3.2.1.3

Move $8$ to the left of $y$ .

$\frac{64 - 8 y + 8 \cdot y + y (- y) - y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.3.2.1.4

Rewrite using the commutative property of multiplication.

$\frac{64 - 8 y + 8 y - y \cdot y - y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.3.2.1.5

Multiply $y$ by $y$ by adding the exponents.

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Step 3.1.2.1.3.2.1.5.1

Move $y$ .

$\frac{64 - 8 y + 8 y - (y \cdot y) - y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.3.2.1.5.2

Multiply $y$ by $y$ .

$\frac{64 - 8 y + 8 y - y^{2} - y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{64 - 8 y + 8 y - y^{2} - y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{64 - 8 y + 8 y - y^{2} - y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.3.2.2

Add $- 8 y$ and $8 y$ .

$\frac{64 + 0 - y^{2} - y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.3.2.3

Add $64$ and $0$ .

$\frac{64 - y^{2} - y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{64 - y^{2} - y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{64 - y^{2} - y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.4

Simplify terms.

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Step 3.1.2.1.4.1

Subtract $y^{2}$ from $- y^{2}$ .

$\frac{64 - 2 y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.4.2

Cancel the common factor of $64 - 2 y^{2}$ and $64$ .

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Step 3.1.2.1.4.2.1

Factor $2$ out of $64$ .

$\frac{2 (32) - 2 y^{2}}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.4.2.2

Factor $2$ out of $- 2 y^{2}$ .

$\frac{2 (32) + 2 (- y^{2})}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.4.2.3

Factor $2$ out of $2 (32) + 2 (- y^{2})$ .

$\frac{2 (32 - y^{2})}{64} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.4.2.4

Cancel the common factors.

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Step 3.1.2.1.4.2.4.1

Factor $2$ out of $64$ .

$\frac{2 (32 - y^{2})}{2 \cdot 32} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.4.2.4.2

Cancel the common factor.

$\frac{2 (32 - y^{2})}{2 \cdot 32} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.1.2.1.4.2.4.3

Rewrite the expression.

$\frac{32 - y^{2}}{32} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{32 - y^{2}}{32} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{32 - y^{2}}{32} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{32 - y^{2}}{32} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{32 - y^{2}}{32} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{32 - y^{2}}{32} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$\frac{32 - y^{2}}{32} = 1$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.2

Solve for $y$ in $\frac{32 - y^{2}}{32} = 1$ .

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Step 3.2.1

Multiply both sides by $32$ .

$\frac{32 - y^{2}}{32} \cdot 32 = 1 \cdot 32$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.2.2

Simplify.

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Step 3.2.2.1

Simplify the left side.

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Step 3.2.2.1.1

Simplify $\frac{32 - y^{2}}{32} \cdot 32$ .

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Step 3.2.2.1.1.1

Cancel the common factor of $32$ .

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Step 3.2.2.1.1.1.1

Cancel the common factor.

$\frac{32 - y^{2}}{32} \cdot 32 = 1 \cdot 32$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.2.2.1.1.1.2

Rewrite the expression.

$32 - y^{2} = 1 \cdot 32$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$32 - y^{2} = 1 \cdot 32$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.2.2.1.1.2

Reorder $32$ and $- y^{2}$ .

$- y^{2} + 32 = 1 \cdot 32$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$- y^{2} + 32 = 1 \cdot 32$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$- y^{2} + 32 = 1 \cdot 32$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.2.2.2

Simplify the right side.

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Step 3.2.2.2.1

Multiply $32$ by $1$ .

$- y^{2} + 32 = 32$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$- y^{2} + 32 = 32$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$- y^{2} + 32 = 32$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.2.3

Solve for $y$ .

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Step 3.2.3.1

Move all terms not containing $y$ to the right side of the equation.

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Step 3.2.3.1.1

Subtract $32$ from both sides of the equation.

$- y^{2} = 32 - 32$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.2.3.1.2

Subtract $32$ from $32$ .

$- y^{2} = 0$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$- y^{2} = 0$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.2.3.2

Divide each term in $- y^{2} = 0$ by $- 1$ and simplify.

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Step 3.2.3.2.1

Divide each term in $- y^{2} = 0$ by $- 1$ .

$\frac{- y^{2}}{- 1} = \frac{0}{- 1}$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.2.3.2.2

Simplify the left side.

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Step 3.2.3.2.2.1

Dividing two negative values results in a positive value.

$\frac{y^{2}}{1} = \frac{0}{- 1}$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.2.3.2.2.2

Divide $y^{2}$ by $1$ .

$y^{2} = \frac{0}{- 1}$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$y^{2} = \frac{0}{- 1}$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.2.3.2.3

Simplify the right side.

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Step 3.2.3.2.3.1

Divide $0$ by $- 1$ .

$y^{2} = 0$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$y^{2} = 0$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$y^{2} = 0$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.2.3.3

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$y = \pm \sqrt{0}$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.2.3.4

Simplify $\pm \sqrt{0}$ .

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Step 3.2.3.4.1

Rewrite $0$ as $0^{2}$ .

$y = \pm \sqrt{0^{2}}$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.2.3.4.2

Pull terms out from under the radical, assuming positive real numbers.

$y = \pm 0$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.2.3.4.3

Plus or minus $0$ is $0$ .

$y = 0$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$y = 0$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$y = 0$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

$y = 0$

$x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$

Step 3.3

Replace all occurrences of $y$ with $0$ in each equation.

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Step 3.3.1

Replace all occurrences of $y$ in $x = - \frac{3 \sqrt{(8 + y) (8 - y)}}{4}$ with $0$ .

$x = - \frac{3 \sqrt{(8 + 0) (8 - (0))}}{4}$

$y = 0$

Step 3.3.2

Simplify $x = - \frac{3 \sqrt{(8 + 0) (8 - (0))}}{4}$ .

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Step 3.3.2.1

Simplify the left side.

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Step 3.3.2.1.1

Remove parentheses.

$x = - \frac{3 \sqrt{(8 + 0) (8 - (0))}}{4}$

$y = 0$

$x = - \frac{3 \sqrt{(8 + 0) (8 - (0))}}{4}$

$y = 0$

Step 3.3.2.2

Simplify the right side.

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Step 3.3.2.2.1

Simplify $- \frac{3 \sqrt{(8 + 0) (8 - (0))}}{4}$ .

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Step 3.3.2.2.1.1

Simplify the numerator.

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Step 3.3.2.2.1.1.1

Add $8$ and $0$ .

$x = - \frac{3 \sqrt{8 (8 - (0))}}{4}$

$y = 0$

Step 3.3.2.2.1.1.2

Multiply $- 1$ by $0$ .

$x = - \frac{3 \sqrt{8 (8 + 0)}}{4}$

$y = 0$

Step 3.3.2.2.1.1.3

Add $8$ and $0$ .

$x = - \frac{3 \sqrt{8 \cdot 8}}{4}$

$y = 0$

Step 3.3.2.2.1.1.4

Multiply $8$ by $8$ .

$x = - \frac{3 \sqrt{64}}{4}$

$y = 0$

Step 3.3.2.2.1.1.5

Rewrite $64$ as $8^{2}$ .

$x = - \frac{3 \sqrt{8^{2}}}{4}$

$y = 0$

Step 3.3.2.2.1.1.6

Pull terms out from under the radical, assuming positive real numbers.

$x = - \frac{3 \cdot 8}{4}$

$y = 0$

$x = - \frac{3 \cdot 8}{4}$

$y = 0$

Step 3.3.2.2.1.2

Simplify the expression.

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Step 3.3.2.2.1.2.1

Multiply $3$ by $8$ .

$x = - \frac{24}{4}$

$y = 0$

Step 3.3.2.2.1.2.2

Divide $24$ by $4$ .

$x = - 1 \cdot 6$

$y = 0$

Step 3.3.2.2.1.2.3

Multiply $- 1$ by $6$ .

$x = - 6$

$y = 0$

$x = - 6$

$y = 0$

$x = - 6$

$y = 0$

$x = - 6$

$y = 0$

$x = - 6$

$y = 0$

$x = - 6$

$y = 0$

$x = - 6$

$y = 0$

Step 4

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(6, 0)$

$(- 6, 0)$

Step 5

The result can be shown in multiple forms.

Point Form:

$(6, 0), (- 6, 0)$

Equation Form:

$x = 6, y = 0$

$x = - 6, y = 0$

Step 6