Precalculus Examples

$a = - 5$ , $a n + 1 = a n + 2$

Step 1

Replace all occurrences of $a$ with $- 5$ in each equation.

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Step 1.1

Replace all occurrences of $a$ in $a n + 1 = a n + 2$ with $- 5$ .

$(- 5) \cdot n + 1 = (- 5) \cdot n + 2$

$a = - 5$

Step 1.2

Simplify $(- 5) \cdot n + 1 = (- 5) \cdot n + 2$ .

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Step 1.2.1

Simplify the left side.

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Step 1.2.1.1

Multiply $- 5$ by $n$ .

$- 5 n + 1 = (- 5) \cdot n + 2$

$a = - 5$

$- 5 n + 1 = (- 5) \cdot n + 2$

$a = - 5$

Step 1.2.2

Simplify the right side.

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Step 1.2.2.1

Multiply $- 5$ by $n$ .

$- 5 n + 1 = - 5 n + 2$

$a = - 5$

$- 5 n + 1 = - 5 n + 2$

$a = - 5$

$- 5 n + 1 = - 5 n + 2$

$a = - 5$

$- 5 n + 1 = - 5 n + 2$

$a = - 5$

Step 2

Solve for $n$ in $- 5 n + 1 = - 5 n + 2$ .

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Step 2.1

Move all terms containing $n$ to the left side of the equation.

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Step 2.1.1

Add $5 n$ to both sides of the equation.

$- 5 n + 1 + 5 n = 2$

$a = - 5$

Step 2.1.2

Combine the opposite terms in $- 5 n + 1 + 5 n$ .

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Step 2.1.2.1

Add $- 5 n$ and $5 n$ .

$0 + 1 = 2$

$a = - 5$

Step 2.1.2.2

Add $0$ and $1$ .

$1 = 2$

$a = - 5$

$1 = 2$

$a = - 5$

$1 = 2$

$a = - 5$

Step 2.2

Since $1 \neq 2$ , there are no solutions.

No solution

$a = - 5$

No solution