Precalculus Examples

$y^{2} + 6 y - 2 x + 13 = 0$

Step 1

Isolate $x$ to the left side of the equation.

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Step 1.1

Move all terms not containing $x$ to the right side of the equation.

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Step 1.1.1

Subtract $y^{2}$ from both sides of the equation.

$6 y - 2 x + 13 = - y^{2}$

Step 1.1.2

Subtract $6 y$ from both sides of the equation.

$- 2 x + 13 = - y^{2} - 6 y$

Step 1.1.3

Subtract $13$ from both sides of the equation.

$- 2 x = - y^{2} - 6 y - 13$

Step 1.2

Divide each term in $- 2 x = - y^{2} - 6 y - 13$ by $- 2$ and simplify.

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Step 1.2.1

Divide each term in $- 2 x = - y^{2} - 6 y - 13$ by $- 2$ .

$\frac{- 2 x}{- 2} = \frac{- y^{2}}{- 2} + \frac{- 6 y}{- 2} + \frac{- 13}{- 2}$

Step 1.2.2

Simplify the left side.

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Step 1.2.2.1

Cancel the common factor of $- 2$ .

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Step 1.2.2.1.1

Cancel the common factor.

$\frac{- 2 x}{- 2} = \frac{- y^{2}}{- 2} + \frac{- 6 y}{- 2} + \frac{- 13}{- 2}$

Step 1.2.2.1.2

Divide $x$ by $1$ .

$x = \frac{- y^{2}}{- 2} + \frac{- 6 y}{- 2} + \frac{- 13}{- 2}$

Step 1.2.3

Simplify the right side.

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Step 1.2.3.1

Simplify each term.

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Step 1.2.3.1.1

Dividing two negative values results in a positive value.

$x = \frac{y^{2}}{2} + \frac{- 6 y}{- 2} + \frac{- 13}{- 2}$

Step 1.2.3.1.2

Cancel the common factor of $- 6$ and $- 2$ .

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Step 1.2.3.1.2.1

Factor $- 2$ out of $- 6 y$ .

$x = \frac{y^{2}}{2} + \frac{- 2 (3 y)}{- 2} + \frac{- 13}{- 2}$

Step 1.2.3.1.2.2

Cancel the common factors.

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Step 1.2.3.1.2.2.1

Factor $- 2$ out of $- 2$ .

$x = \frac{y^{2}}{2} + \frac{- 2 (3 y)}{- 2 (1)} + \frac{- 13}{- 2}$

Step 1.2.3.1.2.2.2

Cancel the common factor.

$x = \frac{y^{2}}{2} + \frac{- 2 (3 y)}{- 2 \cdot 1} + \frac{- 13}{- 2}$

Step 1.2.3.1.2.2.3

Rewrite the expression.

$x = \frac{y^{2}}{2} + \frac{3 y}{1} + \frac{- 13}{- 2}$

Step 1.2.3.1.2.2.4

Divide $3 y$ by $1$ .

$x = \frac{y^{2}}{2} + 3 y + \frac{- 13}{- 2}$

Step 1.2.3.1.3

Dividing two negative values results in a positive value.

$x = \frac{y^{2}}{2} + 3 y + \frac{13}{2}$

Step 2

Complete the square for $\frac{y^{2}}{2} + 3 y + \frac{13}{2}$ .

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Step 2.1

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = \frac{1}{2}$

$b = 3$

$c = \frac{13}{2}$

Step 2.2

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Step 2.3

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

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Step 2.3.1

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{3}{2 (\frac{1}{2})}$

Step 2.3.2

Simplify the right side.

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Step 2.3.2.1

Combine $2$ and $\frac{1}{2}$ .

$d = \frac{3}{\frac{2}{2}}$

Step 2.3.2.2

Divide $2$ by $2$ .

$d = \frac{3}{1}$

Step 2.3.2.3

Divide $3$ by $1$ .

$d = 3$

Step 2.4

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

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Step 2.4.1

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = \frac{13}{2} - \frac{3^{2}}{4 (\frac{1}{2})}$

Step 2.4.2

Simplify the right side.

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Step 2.4.2.1

Simplify each term.

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Step 2.4.2.1.1

Raise $3$ to the power of $2$ .

$e = \frac{13}{2} - \frac{9}{4 (\frac{1}{2})}$

Step 2.4.2.1.2

Combine $4$ and $\frac{1}{2}$ .

$e = \frac{13}{2} - \frac{9}{\frac{4}{2}}$

Step 2.4.2.1.3

Divide $4$ by $2$ .

$e = \frac{13}{2} - \frac{9}{2}$

Step 2.4.2.2

Combine the numerators over the common denominator.

$e = \frac{13 - 9}{2}$

Step 2.4.2.3

Subtract $9$ from $13$ .

$e = \frac{4}{2}$

Step 2.4.2.4

Divide $4$ by $2$ .

$e = 2$

Step 2.5

Substitute the values of $a$ , $d$ , and $e$ into the vertex form $\frac{1}{2} {(y + 3)}^{2} + 2$ .

$\frac{1}{2} {(y + 3)}^{2} + 2$

Step 3

Set $x$ equal to the new right side.

$x = \frac{1}{2} \cdot {(y + 3)}^{2} + 2$