Precalculus Examples

$f (- 6) = x^{3} + 4 x^{2} - 8 x - 10$

Step 1

Replace the variable $x$ with $- 6$ in the expression.

$f (- 6) = {(- 6)}^{3} + 4 {(- 6)}^{2} - 8 \cdot - 6 - 10$

Step 2

Simplify the result.

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Step 2.1

Simplify each term.

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Step 2.1.1

Raise $- 6$ to the power of $3$ .

$f (- 6) = - 216 + 4 {(- 6)}^{2} - 8 \cdot - 6 - 10$

Step 2.1.2

Raise $- 6$ to the power of $2$ .

$f (- 6) = - 216 + 4 \cdot 36 - 8 \cdot - 6 - 10$

Step 2.1.3

Multiply $4$ by $36$ .

$f (- 6) = - 216 + 144 - 8 \cdot - 6 - 10$

Step 2.1.4

Multiply $- 8$ by $- 6$ .

$f (- 6) = - 216 + 144 + 48 - 10$

Step 2.2

Simplify by adding and subtracting.

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Step 2.2.1

Add $- 216$ and $144$ .

$f (- 6) = - 72 + 48 - 10$

Step 2.2.2

Add $- 72$ and $48$ .

$f (- 6) = - 24 - 10$

Step 2.2.3

Subtract $10$ from $- 24$ .

$f (- 6) = - 34$

Step 2.3

The final answer is $- 34$ .

$- 34$

Step 3