Precalculus Examples

$| 13 x - 8 | < - 3$

Step 1

Since $| 13 x - 8 |$ is always positive and $- 3$ is negative, $| 13 x - 8 |$ is always greater than $- 3$ so the inequality cannot be true.

No solution

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$