Precalculus Examples

$\frac{9 x^{2} - 9 x + 6}{2 x^{3} - x^{2} - 8 x + 4}$

Step 1

Decompose the fraction and multiply through by the common denominator.

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Step 1.1

Factor the fraction.

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Step 1.1.1

Factor $3$ out of $9 x^{2} - 9 x + 6$ .

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Step 1.1.1.1

Factor $3$ out of $9 x^{2}$ .

$\frac{3 (3 x^{2}) - 9 x + 6}{2 x^{3} - x^{2} - 8 x + 4}$

Step 1.1.1.2

Factor $3$ out of $- 9 x$ .

$\frac{3 (3 x^{2}) + 3 (- 3 x) + 6}{2 x^{3} - x^{2} - 8 x + 4}$

Step 1.1.1.3

Factor $3$ out of $6$ .

$\frac{3 (3 x^{2}) + 3 (- 3 x) + 3 (2)}{2 x^{3} - x^{2} - 8 x + 4}$

Step 1.1.1.4

Factor $3$ out of $3 (3 x^{2}) + 3 (- 3 x)$ .

$\frac{3 (3 x^{2} - 3 x) + 3 (2)}{2 x^{3} - x^{2} - 8 x + 4}$

Step 1.1.1.5

Factor $3$ out of $3 (3 x^{2} - 3 x) + 3 (2)$ .

$\frac{3 (3 x^{2} - 3 x + 2)}{2 x^{3} - x^{2} - 8 x + 4}$

Step 1.1.2

Factor out the greatest common factor from each group.

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Step 1.1.2.1

Group the first two terms and the last two terms.

$\frac{3 (3 x^{2} - 3 x + 2)}{(2 x^{3} - x^{2}) - 8 x + 4}$

Step 1.1.2.2

Factor out the greatest common factor (GCF) from each group.

$\frac{3 (3 x^{2} - 3 x + 2)}{x^{2} (2 x - 1) - 4 (2 x - 1)}$

Step 1.1.3

Factor the polynomial by factoring out the greatest common factor, $2 x - 1$ .

$\frac{3 (3 x^{2} - 3 x + 2)}{(2 x - 1) (x^{2} - 4)}$

Step 1.1.4

Rewrite $4$ as $2^{2}$ .

$\frac{3 (3 x^{2} - 3 x + 2)}{(2 x - 1) (x^{2} - 2^{2})}$

Step 1.1.5

Factor.

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Step 1.1.5.1

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x$ and $b = 2$ .

$\frac{3 (3 x^{2} - 3 x + 2)}{(2 x - 1) ((x + 2) (x - 2))}$

Step 1.1.5.2

Remove unnecessary parentheses.

$\frac{3 (3 x^{2} - 3 x + 2)}{(2 x - 1) (x + 2) (x - 2)}$

Step 1.2

For each factor in the denominator, create a new fraction using the factor as the denominator, and an unknown value as the numerator. Since the factor in the denominator is linear, put a single variable in its place $A$ .

$\frac{A}{2 x - 1}$

Step 1.3

$\frac{A}{2 x - 1} + \frac{B}{x + 2}$

Step 1.4

$\frac{A}{2 x - 1} + \frac{B}{x + 2} + \frac{C}{x - 2}$

Step 1.5

Multiply each fraction in the equation by the denominator of the original expression. In this case, the denominator is $(2 x - 1) (x + 2) (x - 2)$ .

$\frac{3 (3 x^{2} - 3 x + 2) (2 x - 1) (x + 2) (x - 2)}{(2 x - 1) (x + 2) (x - 2)} = \frac{(A) (2 x - 1) (x + 2) (x - 2)}{2 x - 1} + \frac{(B) (2 x - 1) (x + 2) (x - 2)}{x + 2} + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.6

Cancel the common factor of $2 x - 1$ .

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Step 1.6.1

Cancel the common factor.

Step 1.6.2

Rewrite the expression.

$\frac{(3 (3 x^{2} - 3 x + 2) (x + 2)) (x - 2)}{(x + 2) (x - 2)} = \frac{(A) (2 x - 1) (x + 2) (x - 2)}{2 x - 1} + \frac{(B) (2 x - 1) (x + 2) (x - 2)}{x + 2} + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.7

Cancel the common factor of $x + 2$ .

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Step 1.7.1

Cancel the common factor.

$\frac{3 (3 x^{2} - 3 x + 2) (x + 2) (x - 2)}{(x + 2) (x - 2)} = \frac{(A) (2 x - 1) (x + 2) (x - 2)}{2 x - 1} + \frac{(B) (2 x - 1) (x + 2) (x - 2)}{x + 2} + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.7.2

Rewrite the expression.

$\frac{(3 (3 x^{2} - 3 x + 2)) (x - 2)}{x - 2} = \frac{(A) (2 x - 1) (x + 2) (x - 2)}{2 x - 1} + \frac{(B) (2 x - 1) (x + 2) (x - 2)}{x + 2} + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.8

Cancel the common factor of $x - 2$ .

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Step 1.8.1

Cancel the common factor.

$\frac{3 (3 x^{2} - 3 x + 2) (x - 2)}{x - 2} = \frac{(A) (2 x - 1) (x + 2) (x - 2)}{2 x - 1} + \frac{(B) (2 x - 1) (x + 2) (x - 2)}{x + 2} + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.8.2

Divide $3 (3 x^{2} - 3 x + 2)$ by $1$ .

$3 (3 x^{2} - 3 x + 2) = \frac{(A) (2 x - 1) (x + 2) (x - 2)}{2 x - 1} + \frac{(B) (2 x - 1) (x + 2) (x - 2)}{x + 2} + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.9

Apply the distributive property.

$3 (3 x^{2}) + 3 (- 3 x) + 3 \cdot 2 = \frac{(A) (2 x - 1) (x + 2) (x - 2)}{2 x - 1} + \frac{(B) (2 x - 1) (x + 2) (x - 2)}{x + 2} + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.10

Simplify.

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Step 1.10.1

Multiply $3$ by $3$ .

$9 x^{2} + 3 (- 3 x) + 3 \cdot 2 = \frac{(A) (2 x - 1) (x + 2) (x - 2)}{2 x - 1} + \frac{(B) (2 x - 1) (x + 2) (x - 2)}{x + 2} + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.10.2

Multiply $- 3$ by $3$ .

$9 x^{2} - 9 x + 3 \cdot 2 = \frac{(A) (2 x - 1) (x + 2) (x - 2)}{2 x - 1} + \frac{(B) (2 x - 1) (x + 2) (x - 2)}{x + 2} + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.10.3

Multiply $3$ by $2$ .

$9 x^{2} - 9 x + 6 = \frac{(A) (2 x - 1) (x + 2) (x - 2)}{2 x - 1} + \frac{(B) (2 x - 1) (x + 2) (x - 2)}{x + 2} + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.11

Simplify each term.

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Step 1.11.1

Cancel the common factor of $2 x - 1$ .

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Step 1.11.1.1

Cancel the common factor.

$9 x^{2} - 9 x + 6 = \frac{A (2 x - 1) (x + 2) (x - 2)}{2 x - 1} + \frac{(B) (2 x - 1) (x + 2) (x - 2)}{x + 2} + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.11.1.2

Divide $((A) (x + 2)) (x - 2)$ by $1$ .

$9 x^{2} - 9 x + 6 = ((A) (x + 2)) (x - 2) + \frac{(B) (2 x - 1) (x + 2) (x - 2)}{x + 2} + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.11.2

Apply the distributive property.

$9 x^{2} - 9 x + 6 = (A x + A \cdot 2) (x - 2) + \frac{(B) (2 x - 1) (x + 2) (x - 2)}{x + 2} + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.11.3

Move $2$ to the left of $A$ .

$9 x^{2} - 9 x + 6 = (A x + 2 \cdot A) (x - 2) + \frac{(B) (2 x - 1) (x + 2) (x - 2)}{x + 2} + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.11.4

Expand $(A x + 2 A) (x - 2)$ using the FOIL Method.

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Step 1.11.4.1

Apply the distributive property.

$9 x^{2} - 9 x + 6 = A x (x - 2) + 2 A (x - 2) + \frac{(B) (2 x - 1) (x + 2) (x - 2)}{x + 2} + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.11.4.2

Apply the distributive property.

$9 x^{2} - 9 x + 6 = A x \cdot x + A x \cdot - 2 + 2 A (x - 2) + \frac{(B) (2 x - 1) (x + 2) (x - 2)}{x + 2} + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.11.4.3

Apply the distributive property.

$9 x^{2} - 9 x + 6 = A x \cdot x + A x \cdot - 2 + 2 A x + 2 A \cdot - 2 + \frac{(B) (2 x - 1) (x + 2) (x - 2)}{x + 2} + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.11.5

Combine the opposite terms in $A x \cdot x + A x \cdot - 2 + 2 A x + 2 A \cdot - 2$ .

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Step 1.11.5.1

Reorder the factors in the terms $A x \cdot - 2$ and $2 A x$ .

$9 x^{2} - 9 x + 6 = A x \cdot x - 2 A x + 2 A x + 2 A \cdot - 2 + \frac{(B) (2 x - 1) (x + 2) (x - 2)}{x + 2} + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.11.5.2

Add $- 2 A x$ and $2 A x$ .

$9 x^{2} - 9 x + 6 = A x \cdot x + 0 + 2 A \cdot - 2 + \frac{(B) (2 x - 1) (x + 2) (x - 2)}{x + 2} + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.11.5.3

Add $A x \cdot x$ and $0$ .

$9 x^{2} - 9 x + 6 = A x \cdot x + 2 A \cdot - 2 + \frac{(B) (2 x - 1) (x + 2) (x - 2)}{x + 2} + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.11.6

Simplify each term.

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Step 1.11.6.1

Multiply $x$ by $x$ by adding the exponents.

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Step 1.11.6.1.1

Move $x$ .

$9 x^{2} - 9 x + 6 = A (x \cdot x) + 2 A \cdot - 2 + \frac{(B) (2 x - 1) (x + 2) (x - 2)}{x + 2} + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.11.6.1.2

Multiply $x$ by $x$ .

$9 x^{2} - 9 x + 6 = A x^{2} + 2 A \cdot - 2 + \frac{(B) (2 x - 1) (x + 2) (x - 2)}{x + 2} + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.11.6.2

Multiply $- 2$ by $2$ .

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + \frac{(B) (2 x - 1) (x + 2) (x - 2)}{x + 2} + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.11.7

Cancel the common factor of $x + 2$ .

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Step 1.11.7.1

Cancel the common factor.

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + \frac{(B) (2 x - 1) (x + 2) (x - 2)}{x + 2} + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.11.7.2

Divide $(B) (2 x - 1) (x - 2)$ by $1$ .

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + (B) (2 x - 1) (x - 2) + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.11.8

Apply the distributive property.

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + (B (2 x) + B \cdot - 1) (x - 2) + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.11.9

Rewrite using the commutative property of multiplication.

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + (2 B x + B \cdot - 1) (x - 2) + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.11.10

Move $- 1$ to the left of $B$ .

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + (2 B x - 1 \cdot B) (x - 2) + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.11.11

Rewrite $- 1 B$ as $- B$ .

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + (2 B x - B) (x - 2) + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.11.12

Expand $(2 B x - B) (x - 2)$ using the FOIL Method.

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Step 1.11.12.1

Apply the distributive property.

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + 2 B x (x - 2) - B (x - 2) + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.11.12.2

Apply the distributive property.

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + 2 B x \cdot x + 2 B x \cdot - 2 - B (x - 2) + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.11.12.3

Apply the distributive property.

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + 2 B x \cdot x + 2 B x \cdot - 2 - B x - B \cdot - 2 + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.11.13

Simplify and combine like terms.

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Step 1.11.13.1

Simplify each term.

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Step 1.11.13.1.1

Multiply $x$ by $x$ by adding the exponents.

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Step 1.11.13.1.1.1

Move $x$ .

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + 2 B (x \cdot x) + 2 B x \cdot - 2 - B x - B \cdot - 2 + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.11.13.1.1.2

Multiply $x$ by $x$ .

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + 2 B x^{2} + 2 B x \cdot - 2 - B x - B \cdot - 2 + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.11.13.1.2

Multiply $- 2$ by $2$ .

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + 2 B x^{2} - 4 B x - B x - B \cdot - 2 + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.11.13.1.3

Multiply $- 2$ by $- 1$ .

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + 2 B x^{2} - 4 B x - B x + 2 B + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.11.13.2

Subtract $B x$ from $- 4 B x$ .

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + 2 B x^{2} - 5 B x + 2 B + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.11.14

Cancel the common factor of $x - 2$ .

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Step 1.11.14.1

Cancel the common factor.

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + 2 B x^{2} - 5 B x + 2 B + \frac{(C) (2 x - 1) (x + 2) (x - 2)}{x - 2}$

Step 1.11.14.2

Divide $(C) (2 x - 1) (x + 2)$ by $1$ .

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + 2 B x^{2} - 5 B x + 2 B + (C) (2 x - 1) (x + 2)$

Step 1.11.15

Apply the distributive property.

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + 2 B x^{2} - 5 B x + 2 B + (C (2 x) + C \cdot - 1) (x + 2)$

Step 1.11.16

Rewrite using the commutative property of multiplication.

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + 2 B x^{2} - 5 B x + 2 B + (2 C x + C \cdot - 1) (x + 2)$

Step 1.11.17

Move $- 1$ to the left of $C$ .

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + 2 B x^{2} - 5 B x + 2 B + (2 C x - 1 \cdot C) (x + 2)$

Step 1.11.18

Rewrite $- 1 C$ as $- C$ .

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + 2 B x^{2} - 5 B x + 2 B + (2 C x - C) (x + 2)$

Step 1.11.19

Expand $(2 C x - C) (x + 2)$ using the FOIL Method.

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Step 1.11.19.1

Apply the distributive property.

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + 2 B x^{2} - 5 B x + 2 B + 2 C x (x + 2) - C (x + 2)$

Step 1.11.19.2

Apply the distributive property.

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + 2 B x^{2} - 5 B x + 2 B + 2 C x \cdot x + 2 C x \cdot 2 - C (x + 2)$

Step 1.11.19.3

Apply the distributive property.

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + 2 B x^{2} - 5 B x + 2 B + 2 C x \cdot x + 2 C x \cdot 2 - C x - C \cdot 2$

Step 1.11.20

Simplify and combine like terms.

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Step 1.11.20.1

Simplify each term.

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Step 1.11.20.1.1

Multiply $x$ by $x$ by adding the exponents.

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Step 1.11.20.1.1.1

Move $x$ .

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + 2 B x^{2} - 5 B x + 2 B + 2 C (x \cdot x) + 2 C x \cdot 2 - C x - C \cdot 2$

Step 1.11.20.1.1.2

Multiply $x$ by $x$ .

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + 2 B x^{2} - 5 B x + 2 B + 2 C x^{2} + 2 C x \cdot 2 - C x - C \cdot 2$

Step 1.11.20.1.2

Multiply $2$ by $2$ .

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + 2 B x^{2} - 5 B x + 2 B + 2 C x^{2} + 4 C x - C x - C \cdot 2$

Step 1.11.20.1.3

Multiply $2$ by $- 1$ .

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + 2 B x^{2} - 5 B x + 2 B + 2 C x^{2} + 4 C x - C x - 2 C$

Step 1.11.20.2

Subtract $C x$ from $4 C x$ .

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + 2 B x^{2} - 5 B x + 2 B + 2 C x^{2} + 3 C x - 2 C$

Step 1.12

Simplify the expression.

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Step 1.12.1

Move $B$ .

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + 2 x^{2} B - 5 B x + 2 B + 2 C x^{2} + 3 C x - 2 C$

Step 1.12.2

Move $B$ .

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + 2 x^{2} B - 5 x B + 2 B + 2 C x^{2} + 3 C x - 2 C$

Step 1.12.3

Move $2 B$ .

$9 x^{2} - 9 x + 6 = A x^{2} - 4 A + 2 x^{2} B - 5 x B + 2 C x^{2} + 3 C x + 2 B - 2 C$

Step 1.12.4

Move $- 4 A$ .

$9 x^{2} - 9 x + 6 = A x^{2} + 2 x^{2} B - 5 x B + 2 C x^{2} + 3 C x - 4 A + 2 B - 2 C$

Step 1.12.5

Move $- 5 x B$ .

$9 x^{2} - 9 x + 6 = A x^{2} + 2 x^{2} B + 2 C x^{2} - 5 x B + 3 C x - 4 A + 2 B - 2 C$

Step 2

Create equations for the partial fraction variables and use them to set up a system of equations.

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Step 2.1

Create an equation for the partial fraction variables by equating the coefficients of $x^{2}$ from each side of the equation. For the equation to be equal, the equivalent coefficients on each side of the equation must be equal.

$9 = A + 2 B + 2 C$

Step 2.2

Create an equation for the partial fraction variables by equating the coefficients of $x$ from each side of the equation. For the equation to be equal, the equivalent coefficients on each side of the equation must be equal.

$- 9 = - 5 B + 3 C$

Step 2.3

Create an equation for the partial fraction variables by equating the coefficients of the terms not containing $x$ . For the equation to be equal, the equivalent coefficients on each side of the equation must be equal.

$6 = - 4 A + 2 B - 2 C$

Step 2.4

Set up the system of equations to find the coefficients of the partial fractions.

$9 = A + 2 B + 2 C$

$- 9 = - 5 B + 3 C$

$6 = - 4 A + 2 B - 2 C$

$9 = A + 2 B + 2 C$

$- 9 = - 5 B + 3 C$

$6 = - 4 A + 2 B - 2 C$

Step 3

Solve the system of equations.

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Step 3.1

Solve for $A$ in $9 = A + 2 B + 2 C$ .

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Step 3.1.1

Rewrite the equation as $A + 2 B + 2 C = 9$ .

$A + 2 B + 2 C = 9$

$- 9 = - 5 B + 3 C$

$6 = - 4 A + 2 B - 2 C$

Step 3.1.2

Move all terms not containing $A$ to the right side of the equation.

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Step 3.1.2.1

Subtract $2 B$ from both sides of the equation.

$A + 2 C = 9 - 2 B$

$- 9 = - 5 B + 3 C$

$6 = - 4 A + 2 B - 2 C$

Step 3.1.2.2

Subtract $2 C$ from both sides of the equation.

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

$6 = - 4 A + 2 B - 2 C$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

$6 = - 4 A + 2 B - 2 C$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

$6 = - 4 A + 2 B - 2 C$

Step 3.2

Replace all occurrences of $A$ with $9 - 2 B - 2 C$ in each equation.

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Step 3.2.1

Replace all occurrences of $A$ in $6 = - 4 A + 2 B - 2 C$ with $9 - 2 B - 2 C$ .

$6 = - 4 (9 - 2 B - 2 C) + 2 B - 2 C$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

Step 3.2.2

Simplify the right side.

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Step 3.2.2.1

Simplify $- 4 (9 - 2 B - 2 C) + 2 B - 2 C$ .

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Step 3.2.2.1.1

Simplify each term.

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Step 3.2.2.1.1.1

Apply the distributive property.

$6 = - 4 \cdot 9 - 4 (- 2 B) - 4 (- 2 C) + 2 B - 2 C$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

Step 3.2.2.1.1.2

Simplify.

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Step 3.2.2.1.1.2.1

Multiply $- 4$ by $9$ .

$6 = - 36 - 4 (- 2 B) - 4 (- 2 C) + 2 B - 2 C$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

Step 3.2.2.1.1.2.2

Multiply $- 2$ by $- 4$ .

$6 = - 36 + 8 B - 4 (- 2 C) + 2 B - 2 C$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

Step 3.2.2.1.1.2.3

Multiply $- 2$ by $- 4$ .

$6 = - 36 + 8 B + 8 C + 2 B - 2 C$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

$6 = - 36 + 8 B + 8 C + 2 B - 2 C$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

$6 = - 36 + 8 B + 8 C + 2 B - 2 C$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

Step 3.2.2.1.2

Simplify by adding terms.

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Step 3.2.2.1.2.1

Add $8 B$ and $2 B$ .

$6 = - 36 + 10 B + 8 C - 2 C$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

Step 3.2.2.1.2.2

Subtract $2 C$ from $8 C$ .

$6 = - 36 + 10 B + 6 C$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

$6 = - 36 + 10 B + 6 C$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

$6 = - 36 + 10 B + 6 C$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

$6 = - 36 + 10 B + 6 C$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

$6 = - 36 + 10 B + 6 C$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

Step 3.3

Solve for $B$ in $6 = - 36 + 10 B + 6 C$ .

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Step 3.3.1

Rewrite the equation as $- 36 + 10 B + 6 C = 6$ .

$- 36 + 10 B + 6 C = 6$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

Step 3.3.2

Move all terms not containing $B$ to the right side of the equation.

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Step 3.3.2.1

Add $36$ to both sides of the equation.

$10 B + 6 C = 6 + 36$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

Step 3.3.2.2

Subtract $6 C$ from both sides of the equation.

$10 B = 6 + 36 - 6 C$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

Step 3.3.2.3

Add $6$ and $36$ .

$10 B = 42 - 6 C$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

$10 B = 42 - 6 C$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

Step 3.3.3

Divide each term in $10 B = 42 - 6 C$ by $10$ and simplify.

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Step 3.3.3.1

Divide each term in $10 B = 42 - 6 C$ by $10$ .

$\frac{10 B}{10} = \frac{42}{10} + \frac{- 6 C}{10}$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

Step 3.3.3.2

Simplify the left side.

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Step 3.3.3.2.1

Cancel the common factor of $10$ .

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Step 3.3.3.2.1.1

Cancel the common factor.

$\frac{10 B}{10} = \frac{42}{10} + \frac{- 6 C}{10}$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

Step 3.3.3.2.1.2

Divide $B$ by $1$ .

$B = \frac{42}{10} + \frac{- 6 C}{10}$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

$B = \frac{42}{10} + \frac{- 6 C}{10}$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

$B = \frac{42}{10} + \frac{- 6 C}{10}$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

Step 3.3.3.3

Simplify the right side.

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Step 3.3.3.3.1

Simplify each term.

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Step 3.3.3.3.1.1

Cancel the common factor of $42$ and $10$ .

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Step 3.3.3.3.1.1.1

Factor $2$ out of $42$ .

$B = \frac{2 (21)}{10} + \frac{- 6 C}{10}$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

Step 3.3.3.3.1.1.2

Cancel the common factors.

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Step 3.3.3.3.1.1.2.1

Factor $2$ out of $10$ .

$B = \frac{2 \cdot 21}{2 \cdot 5} + \frac{- 6 C}{10}$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

Step 3.3.3.3.1.1.2.2

Cancel the common factor.

$B = \frac{2 \cdot 21}{2 \cdot 5} + \frac{- 6 C}{10}$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

Step 3.3.3.3.1.1.2.3

Rewrite the expression.

$B = \frac{21}{5} + \frac{- 6 C}{10}$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

$B = \frac{21}{5} + \frac{- 6 C}{10}$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

$B = \frac{21}{5} + \frac{- 6 C}{10}$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

Step 3.3.3.3.1.2

Cancel the common factor of $- 6$ and $10$ .

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Step 3.3.3.3.1.2.1

Factor $2$ out of $- 6 C$ .

$B = \frac{21}{5} + \frac{2 (- 3 C)}{10}$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

Step 3.3.3.3.1.2.2

Cancel the common factors.

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Step 3.3.3.3.1.2.2.1

Factor $2$ out of $10$ .

$B = \frac{21}{5} + \frac{2 (- 3 C)}{2 (5)}$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

Step 3.3.3.3.1.2.2.2

Cancel the common factor.

$B = \frac{21}{5} + \frac{2 (- 3 C)}{2 \cdot 5}$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

Step 3.3.3.3.1.2.2.3

Rewrite the expression.

$B = \frac{21}{5} + \frac{- 3 C}{5}$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

$B = \frac{21}{5} + \frac{- 3 C}{5}$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

$B = \frac{21}{5} + \frac{- 3 C}{5}$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

Step 3.3.3.3.1.3

Move the negative in front of the fraction.

$B = \frac{21}{5} - \frac{3 C}{5}$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

$B = \frac{21}{5} - \frac{3 C}{5}$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

$B = \frac{21}{5} - \frac{3 C}{5}$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

$B = \frac{21}{5} - \frac{3 C}{5}$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

$B = \frac{21}{5} - \frac{3 C}{5}$

$A = 9 - 2 B - 2 C$

$- 9 = - 5 B + 3 C$

Step 3.4

Replace all occurrences of $B$ with $\frac{21}{5} - \frac{3 C}{5}$ in each equation.

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Step 3.4.1

Replace all occurrences of $B$ in $A = 9 - 2 B - 2 C$ with $\frac{21}{5} - \frac{3 C}{5}$ .

$A = 9 - 2 (\frac{21}{5} - \frac{3 C}{5}) - 2 C$

$B = \frac{21}{5} - \frac{3 C}{5}$

$- 9 = - 5 B + 3 C$

Step 3.4.2

Simplify the right side.

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Step 3.4.2.1

Simplify $9 - 2 (\frac{21}{5} - \frac{3 C}{5}) - 2 C$ .

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Step 3.4.2.1.1

Simplify each term.

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Step 3.4.2.1.1.1

Apply the distributive property.

$A = 9 - 2 (\frac{21}{5}) - 2 (- \frac{3 C}{5}) - 2 C$

$B = \frac{21}{5} - \frac{3 C}{5}$

$- 9 = - 5 B + 3 C$

Step 3.4.2.1.1.2

Multiply $- 2 (\frac{21}{5})$ .

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Step 3.4.2.1.1.2.1

Combine $- 2$ and $\frac{21}{5}$ .

$A = 9 + \frac{- 2 \cdot 21}{5} - 2 (- \frac{3 C}{5}) - 2 C$

$B = \frac{21}{5} - \frac{3 C}{5}$

$- 9 = - 5 B + 3 C$

Step 3.4.2.1.1.2.2

Multiply $- 2$ by $21$ .

$A = 9 + \frac{- 42}{5} - 2 (- \frac{3 C}{5}) - 2 C$

$B = \frac{21}{5} - \frac{3 C}{5}$

$- 9 = - 5 B + 3 C$

$A = 9 + \frac{- 42}{5} - 2 (- \frac{3 C}{5}) - 2 C$

$B = \frac{21}{5} - \frac{3 C}{5}$

$- 9 = - 5 B + 3 C$

Step 3.4.2.1.1.3

Multiply $- 2 (- \frac{3 C}{5})$ .

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Step 3.4.2.1.1.3.1

Multiply $- 1$ by $- 2$ .

$A = 9 + \frac{- 42}{5} + 2 (\frac{3 C}{5}) - 2 C$

$B = \frac{21}{5} - \frac{3 C}{5}$

$- 9 = - 5 B + 3 C$

Step 3.4.2.1.1.3.2

Combine $2$ and $\frac{3 C}{5}$ .

$A = 9 + \frac{- 42}{5} + \frac{2 (3 C)}{5} - 2 C$

$B = \frac{21}{5} - \frac{3 C}{5}$

$- 9 = - 5 B + 3 C$

Step 3.4.2.1.1.3.3

Multiply $3$ by $2$ .

$A = 9 + \frac{- 42}{5} + \frac{6 C}{5} - 2 C$

$B = \frac{21}{5} - \frac{3 C}{5}$

$- 9 = - 5 B + 3 C$

$A = 9 + \frac{- 42}{5} + \frac{6 C}{5} - 2 C$

$B = \frac{21}{5} - \frac{3 C}{5}$

$- 9 = - 5 B + 3 C$

Step 3.4.2.1.1.4

Move the negative in front of the fraction.

$A = 9 - \frac{42}{5} + \frac{6 C}{5} - 2 C$

$B = \frac{21}{5} - \frac{3 C}{5}$

$- 9 = - 5 B + 3 C$

$A = 9 - \frac{42}{5} + \frac{6 C}{5} - 2 C$

$B = \frac{21}{5} - \frac{3 C}{5}$

$- 9 = - 5 B + 3 C$

Step 3.4.2.1.2

To write $9$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$A = 9 \cdot \frac{5}{5} - \frac{42}{5} + \frac{6 C}{5} - 2 C$

$B = \frac{21}{5} - \frac{3 C}{5}$

$- 9 = - 5 B + 3 C$

Step 3.4.2.1.3

Combine $9$ and $\frac{5}{5}$ .

$A = \frac{9 \cdot 5}{5} - \frac{42}{5} + \frac{6 C}{5} - 2 C$

$B = \frac{21}{5} - \frac{3 C}{5}$

$- 9 = - 5 B + 3 C$

Step 3.4.2.1.4

Combine the numerators over the common denominator.

$A = \frac{9 \cdot 5 - 42}{5} + \frac{6 C}{5} - 2 C$

$B = \frac{21}{5} - \frac{3 C}{5}$

$- 9 = - 5 B + 3 C$

Step 3.4.2.1.5

Simplify the numerator.

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Step 3.4.2.1.5.1

Multiply $9$ by $5$ .

$A = \frac{45 - 42}{5} + \frac{6 C}{5} - 2 C$

$B = \frac{21}{5} - \frac{3 C}{5}$

$- 9 = - 5 B + 3 C$

Step 3.4.2.1.5.2

Subtract $42$ from $45$ .

$A = \frac{3}{5} + \frac{6 C}{5} - 2 C$

$B = \frac{21}{5} - \frac{3 C}{5}$

$- 9 = - 5 B + 3 C$

$A = \frac{3}{5} + \frac{6 C}{5} - 2 C$

$B = \frac{21}{5} - \frac{3 C}{5}$

$- 9 = - 5 B + 3 C$

Step 3.4.2.1.6

To write $- 2 C$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$A = \frac{3}{5} + \frac{6 C}{5} - 2 C \cdot \frac{5}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

$- 9 = - 5 B + 3 C$

Step 3.4.2.1.7

Combine $- 2 C$ and $\frac{5}{5}$ .

$A = \frac{3}{5} + \frac{6 C}{5} + \frac{- 2 C \cdot 5}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

$- 9 = - 5 B + 3 C$

Step 3.4.2.1.8

Combine the numerators over the common denominator.

$A = \frac{3}{5} + \frac{6 C - 2 C \cdot 5}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

$- 9 = - 5 B + 3 C$

Step 3.4.2.1.9

Combine the numerators over the common denominator.

$A = \frac{3 + 6 C - 2 C \cdot 5}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

$- 9 = - 5 B + 3 C$

Step 3.4.2.1.10

Multiply $5$ by $- 2$ .

$A = \frac{3 + 6 C - 10 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

$- 9 = - 5 B + 3 C$

Step 3.4.2.1.11

Subtract $10 C$ from $6 C$ .

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

$- 9 = - 5 B + 3 C$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

$- 9 = - 5 B + 3 C$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

$- 9 = - 5 B + 3 C$

Step 3.4.3

Replace all occurrences of $B$ in $- 9 = - 5 B + 3 C$ with $\frac{21}{5} - \frac{3 C}{5}$ .

$- 9 = - 5 (\frac{21}{5} - \frac{3 C}{5}) + 3 C$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

Step 3.4.4

Simplify the right side.

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Step 3.4.4.1

Simplify $- 5 (\frac{21}{5} - \frac{3 C}{5}) + 3 C$ .

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Step 3.4.4.1.1

Simplify each term.

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Step 3.4.4.1.1.1

Apply the distributive property.

$- 9 = - 5 (\frac{21}{5}) - 5 (- \frac{3 C}{5}) + 3 C$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

Step 3.4.4.1.1.2

Cancel the common factor of $5$ .

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Step 3.4.4.1.1.2.1

Factor $5$ out of $- 5$ .

$- 9 = 5 (- 1) (\frac{21}{5}) - 5 (- \frac{3 C}{5}) + 3 C$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

Step 3.4.4.1.1.2.2

Cancel the common factor.

$- 9 = 5 \cdot (- 1 (\frac{21}{5})) - 5 (- \frac{3 C}{5}) + 3 C$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

Step 3.4.4.1.1.2.3

Rewrite the expression.

$- 9 = - 1 \cdot 21 - 5 (- \frac{3 C}{5}) + 3 C$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

$- 9 = - 1 \cdot 21 - 5 (- \frac{3 C}{5}) + 3 C$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

Step 3.4.4.1.1.3

Multiply $- 1$ by $21$ .

$- 9 = - 21 - 5 (- \frac{3 C}{5}) + 3 C$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

Step 3.4.4.1.1.4

Cancel the common factor of $5$ .

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Step 3.4.4.1.1.4.1

Move the leading negative in $- \frac{3 C}{5}$ into the numerator.

$- 9 = - 21 - 5 \frac{- 3 C}{5} + 3 C$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

Step 3.4.4.1.1.4.2

Factor $5$ out of $- 5$ .

$- 9 = - 21 + 5 (- 1) (\frac{- 3 C}{5}) + 3 C$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

Step 3.4.4.1.1.4.3

Cancel the common factor.

$- 9 = - 21 + 5 \cdot (- 1 \frac{- 3 C}{5}) + 3 C$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

Step 3.4.4.1.1.4.4

Rewrite the expression.

$- 9 = - 21 - 1 (- 3 C) + 3 C$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

$- 9 = - 21 - 1 (- 3 C) + 3 C$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

Step 3.4.4.1.1.5

Multiply $- 3$ by $- 1$ .

$- 9 = - 21 + 3 C + 3 C$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

$- 9 = - 21 + 3 C + 3 C$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

Step 3.4.4.1.2

Add $3 C$ and $3 C$ .

$- 9 = - 21 + 6 C$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

$- 9 = - 21 + 6 C$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

$- 9 = - 21 + 6 C$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

$- 9 = - 21 + 6 C$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

Step 3.5

Solve for $C$ in $- 9 = - 21 + 6 C$ .

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Step 3.5.1

Rewrite the equation as $- 21 + 6 C = - 9$ .

$- 21 + 6 C = - 9$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

Step 3.5.2

Move all terms not containing $C$ to the right side of the equation.

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Step 3.5.2.1

Add $21$ to both sides of the equation.

$6 C = - 9 + 21$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

Step 3.5.2.2

Add $- 9$ and $21$ .

$6 C = 12$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

$6 C = 12$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

Step 3.5.3

Divide each term in $6 C = 12$ by $6$ and simplify.

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Step 3.5.3.1

Divide each term in $6 C = 12$ by $6$ .

$\frac{6 C}{6} = \frac{12}{6}$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

Step 3.5.3.2

Simplify the left side.

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Step 3.5.3.2.1

Cancel the common factor of $6$ .

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Step 3.5.3.2.1.1

Cancel the common factor.

$\frac{6 C}{6} = \frac{12}{6}$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

Step 3.5.3.2.1.2

Divide $C$ by $1$ .

$C = \frac{12}{6}$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

$C = \frac{12}{6}$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

$C = \frac{12}{6}$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

Step 3.5.3.3

Simplify the right side.

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Step 3.5.3.3.1

Divide $12$ by $6$ .

$C = 2$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

$C = 2$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

$C = 2$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

$C = 2$

$A = \frac{3 - 4 C}{5}$

$B = \frac{21}{5} - \frac{3 C}{5}$

Step 3.6

Replace all occurrences of $C$ with $2$ in each equation.

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Step 3.6.1

Replace all occurrences of $C$ in $A = \frac{3 - 4 C}{5}$ with $2$ .

$A = \frac{3 - 4 \cdot 2}{5}$

$C = 2$

$B = \frac{21}{5} - \frac{3 C}{5}$

Step 3.6.2

Simplify the right side.

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Step 3.6.2.1

Simplify $\frac{3 - 4 \cdot 2}{5}$ .

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Step 3.6.2.1.1

Simplify the numerator.

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Step 3.6.2.1.1.1

Multiply $- 4$ by $2$ .

$A = \frac{3 - 8}{5}$

$C = 2$

$B = \frac{21}{5} - \frac{3 C}{5}$

Step 3.6.2.1.1.2

Subtract $8$ from $3$ .

$A = \frac{- 5}{5}$

$C = 2$

$B = \frac{21}{5} - \frac{3 C}{5}$

$A = \frac{- 5}{5}$

$C = 2$

$B = \frac{21}{5} - \frac{3 C}{5}$

Step 3.6.2.1.2

Divide $- 5$ by $5$ .

$A = - 1$

$C = 2$

$B = \frac{21}{5} - \frac{3 C}{5}$

$A = - 1$

$C = 2$

$B = \frac{21}{5} - \frac{3 C}{5}$

$A = - 1$

$C = 2$

$B = \frac{21}{5} - \frac{3 C}{5}$

Step 3.6.3

Replace all occurrences of $C$ in $B = \frac{21}{5} - \frac{3 C}{5}$ with $2$ .

$B = \frac{21}{5} - \frac{3 (2)}{5}$

$A = - 1$

$C = 2$

Step 3.6.4

Simplify the right side.

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Step 3.6.4.1

Simplify $\frac{21}{5} - \frac{3 (2)}{5}$ .

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Step 3.6.4.1.1

Combine the numerators over the common denominator.

$B = \frac{21 - 3 \cdot 2}{5}$

$A = - 1$

$C = 2$

Step 3.6.4.1.2

Simplify the expression.

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Step 3.6.4.1.2.1

Multiply $- 3$ by $2$ .

$B = \frac{21 - 6}{5}$

$A = - 1$

$C = 2$

Step 3.6.4.1.2.2

Subtract $6$ from $21$ .

$B = \frac{15}{5}$

$A = - 1$

$C = 2$

Step 3.6.4.1.2.3

Divide $15$ by $5$ .

$B = 3$

$A = - 1$

$C = 2$

$B = 3$

$A = - 1$

$C = 2$

$B = 3$

$A = - 1$

$C = 2$

$B = 3$

$A = - 1$

$C = 2$

$B = 3$

$A = - 1$

$C = 2$

Step 3.7

List all of the solutions.

$B = 3, A = - 1, C = 2$

Step 4

Replace each of the partial fraction coefficients in $\frac{A}{2 x - 1} + \frac{B}{x + 2} + \frac{C}{x - 2}$ with the values found for $A$ , $B$ , and $C$ .

$\frac{- 1}{2 x - 1} + \frac{3}{x + 2} + \frac{2}{x - 2}$