Precalculus Examples

$t = \frac{\ln (2)}{0.085}$

Step 1

Replace $e$ with an approximation.

$t = \frac{\log_{2.71828182} (2)}{0.085}$

Step 2

Log base $2.71828182$ of $2$ is approximately $0.69314718$ .

$t = \frac{0.69314718}{0.085}$

Step 3

Divide $0.69314718$ by $0.085$ .

$t = 8.15467271$